Linear Algebra Examples

$[\begin{array}{c} 2 & 8 \\ 0 & - 4 \\ - 1 & 6 \end{array}] + [\begin{array}{c} - 4 & 0 \\ - 7 & - 5 \\ \frac{1}{4} & - 2 \end{array}]$

Step 1

Add the corresponding elements.

$[\begin{array}{c} 2 - 4 & 8 + 0 \\ 0 - 7 & - 4 - 5 \\ - 1 + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2

Simplify each element.

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Step 2.1

Subtract $4$ from $2$ .

$[\begin{array}{c} - 2 & 8 + 0 \\ 0 - 7 & - 4 - 5 \\ - 1 + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2.2

Add $8$ and $0$ .

$[\begin{array}{c} - 2 & 8 \\ 0 - 7 & - 4 - 5 \\ - 1 + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2.3

Subtract $7$ from $0$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 4 - 5 \\ - 1 + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2.4

Subtract $5$ from $- 4$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ - 1 + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2.5

To write $- 1$ as a fraction with a common denominator, multiply by $\frac{4}{4}$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ - 1 \cdot \frac{4}{4} + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2.6

Combine $- 1$ and $\frac{4}{4}$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ \frac{- 1 \cdot 4}{4} + \frac{1}{4} & 6 - 2 \end{array}]$

Step 2.7

Combine the numerators over the common denominator.

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ \frac{- 1 \cdot 4 + 1}{4} & 6 - 2 \end{array}]$

Step 2.8

Simplify the numerator.

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Step 2.8.1

Multiply $- 1$ by $4$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ \frac{- 4 + 1}{4} & 6 - 2 \end{array}]$

Step 2.8.2

Add $- 4$ and $1$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ \frac{- 3}{4} & 6 - 2 \end{array}]$

Step 2.9

Move the negative in front of the fraction.

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ - \frac{3}{4} & 6 - 2 \end{array}]$

Step 2.10

Subtract $2$ from $6$ .

$[\begin{array}{c} - 2 & 8 \\ - 7 & - 9 \\ - \frac{3}{4} & 4 \end{array}]$