Linear Algebra Examples

$59 = 4 + 5 \cdot (n - 1)$

Step 1

Rewrite the equation as $4 + 5 \cdot (n - 1) = 59$ .

$4 + 5 \cdot (n - 1) = 59$

Step 2

Simplify $4 + 5 \cdot (n - 1)$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Apply the distributive property.

$4 + 5 n + 5 \cdot - 1 = 59$

Step 2.1.2

Multiply $5$ by $- 1$ .

$4 + 5 n - 5 = 59$

Step 2.2

Subtract $5$ from $4$ .

$5 n - 1 = 59$

Step 3

Move all terms not containing $n$ to the right side of the equation.

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Step 3.1

Add $1$ to both sides of the equation.

$5 n = 59 + 1$

Step 3.2

Add $59$ and $1$ .

$5 n = 60$

Step 4

Divide each term in $5 n = 60$ by $5$ and simplify.

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Step 4.1

Divide each term in $5 n = 60$ by $5$ .

$\frac{5 n}{5} = \frac{60}{5}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $5$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{5 n}{5} = \frac{60}{5}$

Step 4.2.1.2

Divide $n$ by $1$ .

$n = \frac{60}{5}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $60$ by $5$ .

$n = 12$

Step 5

The domain is the set of all valid $n$ values.

${n | n = 12}$

Step 6