Linear Algebra Examples

$- 2 u [\begin{array}{c} 7 u & 3 w^{2} & 5 u & 5 \end{array}]$

Step 1

Multiply $- 2 u$ by each element of the matrix.

$[\begin{array}{c} - 2 u (7 u) & - 2 u (3 w^{2}) & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2

Simplify each element in the matrix.

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Step 2.1

Rewrite using the commutative property of multiplication.

$[\begin{array}{c} - 2 \cdot 7 u \cdot u & - 2 u (3 w^{2}) & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2.2

Multiply $u$ by $u$ by adding the exponents.

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Step 2.2.1

Move $u$ .

$[\begin{array}{c} - 2 \cdot 7 (u \cdot u) & - 2 u (3 w^{2}) & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2.2.2

Multiply $u$ by $u$ .

$[\begin{array}{c} - 2 \cdot 7 u^{2} & - 2 u (3 w^{2}) & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2.3

Multiply $- 2$ by $7$ .

$[\begin{array}{c} - 14 u^{2} & - 2 u (3 w^{2}) & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2.4

Rewrite using the commutative property of multiplication.

$[\begin{array}{c} - 14 u^{2} & - 2 \cdot 3 u w^{2} & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2.5

Multiply $- 2$ by $3$ .

$[\begin{array}{c} - 14 u^{2} & - 6 u w^{2} & - 2 u (5 u) & - 2 u \cdot 5 \end{array}]$

Step 2.6

Rewrite using the commutative property of multiplication.

$[\begin{array}{c} - 14 u^{2} & - 6 u w^{2} & - 2 \cdot 5 u \cdot u & - 2 u \cdot 5 \end{array}]$

Step 2.7

Multiply $u$ by $u$ by adding the exponents.

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Step 2.7.1

Move $u$ .

$[\begin{array}{c} - 14 u^{2} & - 6 u w^{2} & - 2 \cdot 5 (u \cdot u) & - 2 u \cdot 5 \end{array}]$

Step 2.7.2

Multiply $u$ by $u$ .

$[\begin{array}{c} - 14 u^{2} & - 6 u w^{2} & - 2 \cdot 5 u^{2} & - 2 u \cdot 5 \end{array}]$

Step 2.8

Multiply $- 2$ by $5$ .

$[\begin{array}{c} - 14 u^{2} & - 6 u w^{2} & - 10 u^{2} & - 2 u \cdot 5 \end{array}]$

Step 2.9

Multiply $5$ by $- 2$ .

$[\begin{array}{c} - 14 u^{2} & - 6 u w^{2} & - 10 u^{2} & - 10 u \end{array}]$