Finite Math Examples

$2 x + y^{2} = 6$

Step 1

Solve the equation for $y$ .

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Step 1.1

Subtract $2 x$ from both sides of the equation.

$y^{2} = 6 - 2 x$

Step 1.2

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$y = \pm \sqrt{6 - 2 x}$

Step 1.3

Factor $2$ out of $6 - 2 x$ .

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Step 1.3.1

Factor $2$ out of $6$ .

$y = \pm \sqrt{2 (3) - 2 x}$

Step 1.3.2

Factor $2$ out of $- 2 x$ .

$y = \pm \sqrt{2 (3) + 2 (- x)}$

Step 1.3.3

Factor $2$ out of $2 (3) + 2 (- x)$ .

$y = \pm \sqrt{2 (3 - x)}$

Step 1.4

The complete solution is the result of both the positive and negative portions of the solution.

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Step 1.4.1

First, use the positive value of the $\pm$ to find the first solution.

$y = \sqrt{2 (3 - x)}$

Step 1.4.2

Next, use the negative value of the $\pm$ to find the second solution.

$y = - \sqrt{2 (3 - x)}$

Step 1.4.3

The complete solution is the result of both the positive and negative portions of the solution.

$y = \sqrt{2 (3 - x)}$

$y = - \sqrt{2 (3 - x)}$

$y = \sqrt{2 (3 - x)}$

$y = - \sqrt{2 (3 - x)}$

$y = \sqrt{2 (3 - x)}$

$y = - \sqrt{2 (3 - x)}$

Step 2

A linear equation is an equation of a straight line, which means that the degree of a linear equation must be $0$ or $1$ for each of its variables. In this case, the degree of the variable in the equation violates the linear equation definition, which means that the equation is not a linear equation.

Not Linear