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Finite Math Examples
logg(x-12)+logg(x)=2
Step 1
Step 1.1
Simplify the left side.
Step 1.1.1
Use the product property of logarithms, logb(x)+logb(y)=logb(xy).
logg((x-12)x)=2
Step 1.1.2
Apply the distributive property.
logg(x⋅x-12x)=2
Step 1.1.3
Multiply x by x.
logg(x2-12x)=2
logg(x2-12x)=2
Step 1.2
Rewrite logg(x2-12x)=2 in exponential form using the definition of a logarithm. If x and b are positive real numbers and b≠1, then logb(x)=y is equivalent to by=x.
g2=x2-12x
Step 1.3
Solve for g.
Step 1.3.1
Take the specified root of both sides of the equation to eliminate the exponent on the left side.
g=±√x2-12x
Step 1.3.2
Factor x out of x2-12x.
Step 1.3.2.1
Factor x out of x2.
g=±√x⋅x-12x
Step 1.3.2.2
Factor x out of -12x.
g=±√x⋅x+x⋅-12
Step 1.3.2.3
Factor x out of x⋅x+x⋅-12.
g=±√x(x-12)
g=±√x(x-12)
Step 1.3.3
The complete solution is the result of both the positive and negative portions of the solution.
Step 1.3.3.1
First, use the positive value of the ± to find the first solution.
g=√x(x-12)
Step 1.3.3.2
Next, use the negative value of the ± to find the second solution.
g=-√x(x-12)
Step 1.3.3.3
The complete solution is the result of both the positive and negative portions of the solution.
g=√x(x-12)
g=-√x(x-12)
g=√x(x-12)
g=-√x(x-12)
g=√x(x-12)
g=-√x(x-12)
g=√x(x-12)
g=-√x(x-12)
Step 2
A linear equation is an equation of a straight line, which means that the degree of a linear equation must be 0 or 1 for each of its variables. In this case, the degree of the variable in the equation violates the linear equation definition, which means that the equation is not a linear equation.
Not Linear