Finite Math Examples

$y - c \div y + c + y + c \div y - c = 34 \div 15$

Step 1

Solve for $y$ .

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Step 1.1

Simplify $y - c \div y + c + y + c \div y - c$ .

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Step 1.1.1

Combine the opposite terms in $y - c \div y + c + y + c \div y - c$ .

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Step 1.1.1.1

Add $- c \div y$ and $c \div y$ .

$y + c + y + 0 - c = 34 \div 15$

Step 1.1.1.2

Add $y + c + y$ and $0$ .

$y + c + y - c = 34 \div 15$

Step 1.1.1.3

Subtract $c$ from $c$ .

$y + y + 0 = 34 \div 15$

Step 1.1.1.4

Add $y + y$ and $0$ .

$y + y = 34 \div 15$

Step 1.1.2

Add $y$ and $y$ .

$2 y = 34 \div 15$

Step 1.2

Rewrite the division as a fraction.

$2 y = \frac{34}{15}$

Step 1.3

Divide each term in $2 y = \frac{34}{15}$ by $2$ and simplify.

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Step 1.3.1

Divide each term in $2 y = \frac{34}{15}$ by $2$ .

$\frac{2 y}{2} = \frac{\frac{34}{15}}{2}$

Step 1.3.2

Simplify the left side.

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Step 1.3.2.1

Cancel the common factor of $2$ .

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Step 1.3.2.1.1

Cancel the common factor.

$\frac{2 y}{2} = \frac{\frac{34}{15}}{2}$

Step 1.3.2.1.2

Divide $y$ by $1$ .

$y = \frac{\frac{34}{15}}{2}$

Step 1.3.3

Simplify the right side.

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Step 1.3.3.1

Multiply the numerator by the reciprocal of the denominator.

$y = \frac{34}{15} \cdot \frac{1}{2}$

Step 1.3.3.2

Cancel the common factor of $2$ .

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Step 1.3.3.2.1

Factor $2$ out of $34$ .

$y = \frac{2 (17)}{15} \cdot \frac{1}{2}$

Step 1.3.3.2.2

Cancel the common factor.

$y = \frac{2 \cdot 17}{15} \cdot \frac{1}{2}$

Step 1.3.3.2.3

Rewrite the expression.

$y = \frac{17}{15}$

Step 2

Set $34 \div 15$ equal to $0$ .

$\frac{17}{15} = 0$

Step 3

Solve for $x$ .

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Step 3.1

Set the numerator equal to zero.

$17 = 0$

Step 3.2

Since $17 \neq 0$ , there are no solutions.

No solution