Finite Math Examples

$f (x) = 25 e + 2 p e$

Step 1

Set $25 e + 2 p e$ equal to $0$ .

$25 e + 2 p e = 0$

Step 2

Solve for $x$ .

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Step 2.1

Subtract $25 e$ from both sides of the equation.

$2 p e = - 25 e$

Step 2.2

Divide each term in $2 p e = - 25 e$ by $2 e$ and simplify.

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Step 2.2.1

Divide each term in $2 p e = - 25 e$ by $2 e$ .

$\frac{2 p e}{2 e} = \frac{- 25 e}{2 e}$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Cancel the common factor of $2$ .

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Step 2.2.2.1.1

Cancel the common factor.

$\frac{2 p e}{2 e} = \frac{- 25 e}{2 e}$

Step 2.2.2.1.2

Rewrite the expression.

$\frac{p e}{e} = \frac{- 25 e}{2 e}$

$\frac{p e}{e} = \frac{- 25 e}{2 e}$

Step 2.2.2.2

Cancel the common factor of $e$ .

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Step 2.2.2.2.1

Cancel the common factor.

$\frac{p e}{e} = \frac{- 25 e}{2 e}$

Step 2.2.2.2.2

Divide $p$ by $1$ .

$p = \frac{- 25 e}{2 e}$

$p = \frac{- 25 e}{2 e}$

$p = \frac{- 25 e}{2 e}$

Step 2.2.3

Simplify the right side.

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Step 2.2.3.1

Cancel the common factor of $e$ .

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Step 2.2.3.1.1

Cancel the common factor.

$p = \frac{- 25 e}{2 e}$

Step 2.2.3.1.2

Rewrite the expression.

$p = \frac{- 25}{2}$

$p = \frac{- 25}{2}$

Step 2.2.3.2

Move the negative in front of the fraction.

$p = - \frac{25}{2}$

$p = - \frac{25}{2}$

$p = - \frac{25}{2}$

$p = - \frac{25}{2}$

Step 3

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$