Finite Math Examples

$2 x^{2} + 4 x - 3 = 0$

Step 1

Add $3$ to both sides of the equation.

$2 x^{2} + 4 x = 3$

Step 2

Divide each term in $2 x^{2} + 4 x = 3$ by $2$ and simplify.

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Step 2.1

Divide each term in $2 x^{2} + 4 x = 3$ by $2$ .

$\frac{2 x^{2}}{2} + \frac{4 x}{2} = \frac{3}{2}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify each term.

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Step 2.2.1.1

Cancel the common factor of $2$ .

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Step 2.2.1.1.1

Cancel the common factor.

$\frac{2 x^{2}}{2} + \frac{4 x}{2} = \frac{3}{2}$

Step 2.2.1.1.2

Divide $x^{2}$ by $1$ .

$x^{2} + \frac{4 x}{2} = \frac{3}{2}$

Step 2.2.1.2

Cancel the common factor of $4$ and $2$ .

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Step 2.2.1.2.1

Factor $2$ out of $4 x$ .

$x^{2} + \frac{2 (2 x)}{2} = \frac{3}{2}$

Step 2.2.1.2.2

Cancel the common factors.

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Step 2.2.1.2.2.1

Factor $2$ out of $2$ .

$x^{2} + \frac{2 (2 x)}{2 (1)} = \frac{3}{2}$

Step 2.2.1.2.2.2

Cancel the common factor.

$x^{2} + \frac{2 (2 x)}{2 \cdot 1} = \frac{3}{2}$

Step 2.2.1.2.2.3

Rewrite the expression.

$x^{2} + \frac{2 x}{1} = \frac{3}{2}$

Step 2.2.1.2.2.4

Divide $2 x$ by $1$ .

$x^{2} + 2 x = \frac{3}{2}$

Step 3

To create a trinomial square on the left side of the equation, find a value that is equal to the square of half of $b$ .

${(\frac{b}{2})}^{2} = {(1)}^{2}$

Step 4

Add the term to each side of the equation.

$x^{2} + 2 x + {(1)}^{2} = \frac{3}{2} + {(1)}^{2}$

Step 5

Simplify the equation.

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Step 5.1

Simplify the left side.

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Step 5.1.1

One to any power is one.

$x^{2} + 2 x + 1 = \frac{3}{2} + {(1)}^{2}$

Step 5.2

Simplify the right side.

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Step 5.2.1

Simplify $\frac{3}{2} + {(1)}^{2}$ .

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Step 5.2.1.1

One to any power is one.

$x^{2} + 2 x + 1 = \frac{3}{2} + 1$

Step 5.2.1.2

Write $1$ as a fraction with a common denominator.

$x^{2} + 2 x + 1 = \frac{3}{2} + \frac{2}{2}$

Step 5.2.1.3

Combine the numerators over the common denominator.

$x^{2} + 2 x + 1 = \frac{3 + 2}{2}$

Step 5.2.1.4

Add $3$ and $2$ .

$x^{2} + 2 x + 1 = \frac{5}{2}$

Step 6

Factor the perfect trinomial square into ${(x + 1)}^{2}$ .

${(x + 1)}^{2} = \frac{5}{2}$

Step 7

Solve the equation for $x$ .

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Step 7.1

Take the specified root of both sides of the equation to eliminate the exponent on the left side.

$x + 1 = \pm \sqrt{\frac{5}{2}}$

Step 7.2

Simplify $\pm \sqrt{\frac{5}{2}}$ .

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Step 7.2.1

Rewrite $\sqrt{\frac{5}{2}}$ as $\frac{\sqrt{5}}{\sqrt{2}}$ .

$x + 1 = \pm \frac{\sqrt{5}}{\sqrt{2}}$

Step 7.2.2

Multiply $\frac{\sqrt{5}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$x + 1 = \pm \frac{\sqrt{5}}{\sqrt{2}} \cdot \frac{\sqrt{2}}{\sqrt{2}}$

Step 7.2.3

Combine and simplify the denominator.

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Step 7.2.3.1

Multiply $\frac{\sqrt{5}}{\sqrt{2}}$ by $\frac{\sqrt{2}}{\sqrt{2}}$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{\sqrt{2} \sqrt{2}}$

Step 7.2.3.2

Raise $\sqrt{2}$ to the power of $1$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{{\sqrt{2}}^{1} \sqrt{2}}$

Step 7.2.3.3

Raise $\sqrt{2}$ to the power of $1$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{{\sqrt{2}}^{1} {\sqrt{2}}^{1}}$

Step 7.2.3.4

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{{\sqrt{2}}^{1 + 1}}$

Step 7.2.3.5

Add $1$ and $1$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{{\sqrt{2}}^{2}}$

Step 7.2.3.6

Rewrite ${\sqrt{2}}^{2}$ as $2$ .

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Step 7.2.3.6.1

Use $\sqrt[n]{a^{x}} = a^{\frac{x}{n}}$ to rewrite $\sqrt{2}$ as $2^{\frac{1}{2}}$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{{(2^{\frac{1}{2}})}^{2}}$

Step 7.2.3.6.2

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{2^{\frac{1}{2} \cdot 2}}$

Step 7.2.3.6.3

Combine $\frac{1}{2}$ and $2$ .

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{2^{\frac{2}{2}}}$

Step 7.2.3.6.4

Cancel the common factor of $2$ .

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Step 7.2.3.6.4.1

Cancel the common factor.

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{2^{\frac{2}{2}}}$

Step 7.2.3.6.4.2

Rewrite the expression.

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{2^{1}}$

Step 7.2.3.6.5

Evaluate the exponent.

$x + 1 = \pm \frac{\sqrt{5} \sqrt{2}}{2}$

Step 7.2.4

Simplify the numerator.

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Step 7.2.4.1

Combine using the product rule for radicals.

$x + 1 = \pm \frac{\sqrt{5 \cdot 2}}{2}$

Step 7.2.4.2

Multiply $5$ by $2$ .

$x + 1 = \pm \frac{\sqrt{10}}{2}$

Step 7.3

Subtract $1$ from both sides of the equation.

$x = \pm \frac{\sqrt{10}}{2} - 1$

Step 8

The result can be shown in multiple forms.

Exact Form:

$x = \pm \frac{\sqrt{10}}{2} - 1$

Decimal Form:

$x = 0.58113883 \dots, - 2.58113883 \dots$