Finite Math Examples

$v (\frac{(2) (431 \cdot 10^{- 3}) (9.8)}{(1.3) p {(10.5 \cdot 10^{- 3})}^{2}})$

Step 1

Multiply.

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Step 1.1

Multiply $2$ by $431$ .

$v \frac{862 \cdot 10^{- 3} \cdot 9.8}{(1.3) p {(10.5 \cdot 10^{- 3})}^{2}}$

Step 1.2

Multiply $862$ by $9.8$ .

$v \frac{8447.6 \cdot 10^{- 3}}{(1.3) p {(10.5 \cdot 10^{- 3})}^{2}}$

Step 2

Simplify the numerator.

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Step 2.1

Move the decimal point in $8447.6$ to the left by $3$ places and increase the power of $10^{- 3}$ by $3$ .

$v \frac{8.4476 \cdot 10^{0}}{(1.3) p {(10.5 \cdot 10^{- 3})}^{2}}$

Step 2.2

Convert $8.4476 \cdot 10^{0}$ from scientific notation.

$v \frac{8.4476}{(1.3) p {(10.5 \cdot 10^{- 3})}^{2}}$

Step 3

Multiply ${(10.5 \cdot 10^{- 3})}^{2}$ by $1.3$ .

$v \frac{8.4476}{0.00014332 p}$

Step 4

Simplify with factoring out.

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Step 4.1

Factor $8.4476$ out of $8.4476$ .

$v \frac{8.4476 (1)}{0.00014332 p}$

Step 4.2

Factor $0.00014332$ out of $0.00014332 p$ .

$v \frac{8.4476 (1)}{0.00014332 (p)}$

Step 5

Separate fractions.

$v (\frac{8.4476}{0.00014332} \cdot \frac{1}{p})$

Step 6

Divide $8.4476$ by $0.00014332$ .

$v (58940.\overline{170940} \frac{1}{p})$

Step 7

Rewrite using the commutative property of multiplication.

$58940.\overline{170940} v \frac{1}{p}$

Step 8

Multiply $58940.\overline{170940} v \frac{1}{p}$ .

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Step 8.1

Combine $58940.\overline{170940}$ and $\frac{1}{p}$ .

$v \frac{58940.\overline{170940}}{p}$

Step 8.2

Combine $v$ and $\frac{58940.\overline{170940}}{p}$ .

$\frac{v \cdot 58940.\overline{170940}}{p}$

Step 9

Move $58940.\overline{170940}$ to the left of $v$ .

$\frac{58940.\overline{170940} v}{p}$