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Finite Math Examples
516-22-26⋅f26516−22−26⋅f26
Step 1
Step 1.1
Simplify each term.
Step 1.1.1
Cancel the common factor of 2626.
Step 1.1.1.1
Factor 2626 out of -26−26.
516-22+26(-1)⋅f26516−22+26(−1)⋅f26
Step 1.1.1.2
Cancel the common factor.
516-22+26⋅-1⋅f26
Step 1.1.1.3
Rewrite the expression.
516-22-1⋅f
516-22-1⋅f
Step 1.1.2
Rewrite -1f as -f.
516-22-f
516-22-f
Step 1.2
Simplify the expression.
Step 1.2.1
Subtract 22 from 516.
494-f
Step 1.2.2
Reorder 494 and -f.
-f+494
-f+494
-f+494
Step 2
If a polynomial function has integer coefficients, then every rational zero will have the form pq where p is a factor of the constant and q is a factor of the leading coefficient.
p=±1,±2,±13,±19,±26,±38,±247,±494
q=±1
Step 3
Find every combination of ±pq. These are the possible roots of the polynomial function.
±1,±2,±13,±19,±26,±38,±247,±494