Finite Math Examples

Evaluate Using the Remainder Theorem f(x)=x^3-2x^2-x+2 , f(1)
f(x)=x32x2x+2 , f(1)
Step 1
Set up the long division problem to evaluate the function at 1.
x32x2x+2x(1)
Step 2
Divide using synthetic division.
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Step 2.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
11212
  
Step 2.2
The first number in the dividend (1) is put into the first position of the result area (below the horizontal line).
11212
  
1
Step 2.3
Multiply the newest entry in the result (1) by the divisor (1) and place the result of (1) under the next term in the dividend (2).
11212
 1 
1
Step 2.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
11212
 1 
11
Step 2.5
Multiply the newest entry in the result (1) by the divisor (1) and place the result of (1) under the next term in the dividend (1).
11212
 11 
11
Step 2.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
11212
 11 
112
Step 2.7
Multiply the newest entry in the result (2) by the divisor (1) and place the result of (2) under the next term in the dividend (2).
11212
 112
112
Step 2.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
11212
 112
1120
Step 2.9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x2+1x2
Step 2.10
Simplify the quotient polynomial.
x2x2
x2x2
Step 3
The remainder of the synthetic division is the result based on the remainder theorem.
0
Step 4
 x2  12  π  xdx