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Finite Math Examples
f(x)=x3−2x2−x+2 , f(1)
Step 1
Set up the long division problem to evaluate the function at 1.
x3−2x2−x+2x−(1)
Step 2
Step 2.1
Place the numbers representing the divisor and the dividend into a division-like configuration.
1 | 1 | −2 | −1 | 2 |
Step 2.2
The first number in the dividend (1) is put into the first position of the result area (below the horizontal line).
1 | 1 | −2 | −1 | 2 |
1 |
Step 2.3
Multiply the newest entry in the result (1) by the divisor (1) and place the result of (1) under the next term in the dividend (−2).
1 | 1 | −2 | −1 | 2 |
1 | ||||
1 |
Step 2.4
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | −2 | −1 | 2 |
1 | ||||
1 | −1 |
Step 2.5
Multiply the newest entry in the result (−1) by the divisor (1) and place the result of (−1) under the next term in the dividend (−1).
1 | 1 | −2 | −1 | 2 |
1 | −1 | |||
1 | −1 |
Step 2.6
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | −2 | −1 | 2 |
1 | −1 | |||
1 | −1 | −2 |
Step 2.7
Multiply the newest entry in the result (−2) by the divisor (1) and place the result of (−2) under the next term in the dividend (2).
1 | 1 | −2 | −1 | 2 |
1 | −1 | −2 | ||
1 | −1 | −2 |
Step 2.8
Add the product of the multiplication and the number from the dividend and put the result in the next position on the result line.
1 | 1 | −2 | −1 | 2 |
1 | −1 | −2 | ||
1 | −1 | −2 | 0 |
Step 2.9
All numbers except the last become the coefficients of the quotient polynomial. The last value in the result line is the remainder.
1x2+−1x−2
Step 2.10
Simplify the quotient polynomial.
x2−x−2
x2−x−2
Step 3
The remainder of the synthetic division is the result based on the remainder theorem.
0
Step 4