Finite Math Examples

$S (t) = - 16 t^{2} + 96 (0) t + 168 (0)$

Step 1

Simplify each term.

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Step 1.1

Multiply $96$ by $0$ .

$S (t) = - 16 t^{2} + 0 t + 168 (0)$

Step 1.2

Multiply $0$ by $t$ .

$S (t) = - 16 t^{2} + 0 + 168 (0)$

Step 1.3

Multiply $168$ by $0$ .

$S (t) = - 16 t^{2} + 0 + 0$

Step 2

Combine the opposite terms in $- 16 t^{2} + 0 + 0$ .

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Step 2.1

Add $- 16 t^{2}$ and $0$ .

$S (t) = - 16 t^{2} + 0$

Step 2.2

Add $- 16 t^{2}$ and $0$ .

$S (t) = - 16 t^{2}$

Step 3

Find every combination of $\pm \frac{p}{q}$ .

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Step 3.1

If a polynomial function has integer coefficients, then every rational zero will have the form $\frac{p}{q}$ where $p$ is a factor of the constant and $q$ is a factor of the leading coefficient.

$p = \pm 0$

$q = \pm 1, \pm 2, \pm 4, \pm 8, \pm 16$

Step 3.2

Find every combination of $\pm \frac{p}{q}$ . These are the possible roots of the polynomial function.

$0$

Step 4

Determine the upper and lower bounds.

No Upper Bounds

No Lower Bounds

Step 5