Finite Math Examples

$3 (x - y) = 5 (x + 3) - 13$ , $2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1

Solve for $y$ in $3 (x - y) = 5 (x + 3) - 13$ .

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Step 1.1

Divide each term in $3 (x - y) = 5 (x + 3) - 13$ by $3$ and simplify.

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Step 1.1.1

Divide each term in $3 (x - y) = 5 (x + 3) - 13$ by $3$ .

$\frac{3 (x - y)}{3} = \frac{5 (x + 3)}{3} + \frac{- 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.1.2

Simplify the left side.

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Step 1.1.2.1

Cancel the common factor of $3$ .

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Step 1.1.2.1.1

Cancel the common factor.

$\frac{3 (x - y)}{3} = \frac{5 (x + 3)}{3} + \frac{- 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.1.2.1.2

Divide $x - y$ by $1$ .

$x - y = \frac{5 (x + 3)}{3} + \frac{- 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$x - y = \frac{5 (x + 3)}{3} + \frac{- 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$x - y = \frac{5 (x + 3)}{3} + \frac{- 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.1.3

Simplify the right side.

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Step 1.1.3.1

Combine the numerators over the common denominator.

$x - y = \frac{5 (x + 3) - 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.1.3.2

Simplify each term.

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Step 1.1.3.2.1

Apply the distributive property.

$x - y = \frac{5 x + 5 \cdot 3 - 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.1.3.2.2

Multiply $5$ by $3$ .

$x - y = \frac{5 x + 15 - 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$x - y = \frac{5 x + 15 - 13}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.1.3.3

Subtract $13$ from $15$ .

$x - y = \frac{5 x + 2}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$x - y = \frac{5 x + 2}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$x - y = \frac{5 x + 2}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.2

Move all terms not containing $y$ to the right side of the equation.

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Step 1.2.1

Subtract $x$ from both sides of the equation.

$- y = \frac{5 x + 2}{3} - x$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.2.2

Split the fraction $\frac{5 x + 2}{3}$ into two fractions.

$- y = \frac{5 x}{3} + \frac{2}{3} - x$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$- y = \frac{5 x}{3} + \frac{2}{3} - x$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3

Divide each term in $- y = \frac{5 x}{3} + \frac{2}{3} - x$ by $- 1$ and simplify.

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Step 1.3.1

Divide each term in $- y = \frac{5 x}{3} + \frac{2}{3} - x$ by $- 1$ .

$\frac{- y}{- 1} = \frac{\frac{5 x}{3}}{- 1} + \frac{\frac{2}{3}}{- 1} + \frac{- x}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.2

Simplify the left side.

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Step 1.3.2.1

Dividing two negative values results in a positive value.

$\frac{y}{1} = \frac{\frac{5 x}{3}}{- 1} + \frac{\frac{2}{3}}{- 1} + \frac{- x}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.2.2

Divide $y$ by $1$ .

$y = \frac{\frac{5 x}{3}}{- 1} + \frac{\frac{2}{3}}{- 1} + \frac{- x}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$y = \frac{\frac{5 x}{3}}{- 1} + \frac{\frac{2}{3}}{- 1} + \frac{- x}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3

Simplify the right side.

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Step 1.3.3.1

Combine the numerators over the common denominator.

$y = \frac{\frac{5 x}{3} + \frac{2}{3} - x}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.2

To write $- x$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$y = \frac{\frac{5 x}{3} - x \cdot \frac{3}{3} + \frac{2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.3

Combine $- x$ and $\frac{3}{3}$ .

$y = \frac{\frac{5 x}{3} + \frac{- x \cdot 3}{3} + \frac{2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.4

Combine the numerators over the common denominator.

$y = \frac{\frac{5 x - x \cdot 3}{3} + \frac{2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.5

Combine the numerators over the common denominator.

$y = \frac{\frac{5 x - x \cdot 3 + 2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.6

Multiply $3$ by $- 1$ .

$y = \frac{\frac{5 x - 3 x + 2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.7

Subtract $3 x$ from $5 x$ .

$y = \frac{\frac{2 x + 2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.8

Factor $2$ out of $2 x + 2$ .

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Step 1.3.3.8.1

Factor $2$ out of $2 x$ .

$y = \frac{\frac{2 (x) + 2}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.8.2

Factor $2$ out of $2$ .

$y = \frac{\frac{2 (x) + 2 (1)}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.8.3

Factor $2$ out of $2 (x) + 2 (1)$ .

$y = \frac{\frac{2 (x + 1)}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$y = \frac{\frac{2 (x + 1)}{3}}{- 1}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.9

Simplify the expression.

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Step 1.3.3.9.1

Move the negative one from the denominator of $\frac{\frac{2 (x + 1)}{3}}{- 1}$ .

$y = - 1 \cdot \frac{2 (x + 1)}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 1.3.3.9.2

Rewrite $- 1 \cdot \frac{2 (x + 1)}{3}$ as $- \frac{2 (x + 1)}{3}$ .

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x - 3 y - 10) = 5 (y + 2)$

Step 2

Replace all occurrences of $y$ with $- \frac{2 (x + 1)}{3}$ in each equation.

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Step 2.1

Replace all occurrences of $y$ in $2 (2 x - 3 y - 10) = 5 (y + 2)$ with $- \frac{2 (x + 1)}{3}$ .

$2 (2 x - 3 (- \frac{2 (x + 1)}{3}) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2

Simplify $2 (2 x - 3 (- \frac{2 (x + 1)}{3}) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$ .

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Step 2.2.1

Simplify the left side.

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Step 2.2.1.1

Simplify $2 (2 x - 3 (- \frac{2 (x + 1)}{3}) - 10)$ .

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Step 2.2.1.1.1

Simplify each term.

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Step 2.2.1.1.1.1

Cancel the common factor of $3$ .

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Step 2.2.1.1.1.1.1

Move the leading negative in $- \frac{2 (x + 1)}{3}$ into the numerator.

$2 (2 x - 3 \frac{- 2 (x + 1)}{3} - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.1.1.2

Factor $3$ out of $- 3$ .

$2 (2 x + 3 (- 1) (\frac{- 2 (x + 1)}{3}) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.1.1.3

Cancel the common factor.

$2 (2 x + 3 \cdot (- 1 \frac{- 2 (x + 1)}{3}) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.1.1.4

Rewrite the expression.

$2 (2 x - 1 (- 2 (x + 1)) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x - 1 (- 2 (x + 1)) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.1.2

Multiply $- 2$ by $- 1$ .

$2 (2 x + 2 (x + 1) - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.1.3

Apply the distributive property.

$2 (2 x + 2 x + 2 \cdot 1 - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.1.4

Multiply $2$ by $1$ .

$2 (2 x + 2 x + 2 - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

$2 (2 x + 2 x + 2 - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.2

Simplify terms.

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Step 2.2.1.1.2.1

Add $2 x$ and $2 x$ .

$2 (4 x + 2 - 10) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.2.2

Subtract $10$ from $2$ .

$2 (4 x - 8) = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.2.3

Apply the distributive property.

$2 (4 x) + 2 \cdot - 8 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.2.4

Multiply.

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Step 2.2.1.1.2.4.1

Multiply $4$ by $2$ .

$8 x + 2 \cdot - 8 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.1.1.2.4.2

Multiply $2$ by $- 8$ .

$8 x - 16 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 ((- \frac{2 (x + 1)}{3}) + 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2

Simplify the right side.

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Step 2.2.2.1

Simplify $5 ((- \frac{2 (x + 1)}{3}) + 2)$ .

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Step 2.2.2.1.1

To write $2$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$8 x - 16 = 5 (- \frac{2 (x + 1)}{3} + 2 \cdot \frac{3}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.2

Simplify terms.

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Step 2.2.2.1.2.1

Combine $2$ and $\frac{3}{3}$ .

$8 x - 16 = 5 (- \frac{2 (x + 1)}{3} + \frac{2 \cdot 3}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.2.2

Combine the numerators over the common denominator.

$8 x - 16 = 5 (\frac{- 2 (x + 1) + 2 \cdot 3}{3})$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 (\frac{- 2 (x + 1) + 2 \cdot 3}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.3

Simplify the numerator.

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Step 2.2.2.1.3.1

Factor $2$ out of $- 2 (x + 1) + 2 \cdot 3$ .

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Step 2.2.2.1.3.1.1

Factor $2$ out of $- 2 (x + 1)$ .

$8 x - 16 = 5 (\frac{2 (- (x + 1)) + 2 \cdot 3}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.3.1.2

Factor $2$ out of $2 \cdot 3$ .

$8 x - 16 = 5 (\frac{2 (- (x + 1)) + 2 (3)}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.3.1.3

Factor $2$ out of $2 (- (x + 1)) + 2 (3)$ .

$8 x - 16 = 5 (\frac{2 (- (x + 1) + 3)}{3})$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 (\frac{2 (- (x + 1) + 3)}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.3.2

Apply the distributive property.

$8 x - 16 = 5 (\frac{2 (- x - 1 \cdot 1 + 3)}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.3.3

Multiply $- 1$ by $1$ .

$8 x - 16 = 5 (\frac{2 (- x - 1 + 3)}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.3.4

Add $- 1$ and $3$ .

$8 x - 16 = 5 (\frac{2 (- x + 2)}{3})$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = 5 (\frac{2 (- x + 2)}{3})$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.4

Multiply $5 \frac{2 (- x + 2)}{3}$ .

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Step 2.2.2.1.4.1

Combine $5$ and $\frac{2 (- x + 2)}{3}$ .

$8 x - 16 = \frac{5 (2 (- x + 2))}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.4.2

Multiply $2$ by $5$ .

$8 x - 16 = \frac{10 (- x + 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = \frac{10 (- x + 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.5

Factor $- 1$ out of $- x$ .

$8 x - 16 = \frac{10 (- (x) + 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.6

Rewrite $2$ as $- 1 (- 2)$ .

$8 x - 16 = \frac{10 (- (x) - 1 \cdot - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.7

Factor $- 1$ out of $- (x) - 1 (- 2)$ .

$8 x - 16 = \frac{10 (- (x - 2))}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.8

Simplify the expression.

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Step 2.2.2.1.8.1

Rewrite $- (x - 2)$ as $- 1 (x - 2)$ .

$8 x - 16 = \frac{10 (- 1 (x - 2))}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 2.2.2.1.8.2

Move the negative in front of the fraction.

$8 x - 16 = - \frac{10 (x - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = - \frac{10 (x - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = - \frac{10 (x - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = - \frac{10 (x - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = - \frac{10 (x - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

$8 x - 16 = - \frac{10 (x - 2)}{3}$

$y = - \frac{2 (x + 1)}{3}$

Step 3

Solve for $x$ in $8 x - 16 = - \frac{10 (x - 2)}{3}$ .

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Step 3.1

Multiply both sides by $3$ .

$(8 x - 16) \cdot 3 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2

Simplify.

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Step 3.2.1

Simplify the left side.

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Step 3.2.1.1

Simplify $(8 x - 16) \cdot 3$ .

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Step 3.2.1.1.1

Apply the distributive property.

$8 x \cdot 3 - 16 \cdot 3 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.1.1.2

Multiply.

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Step 3.2.1.1.2.1

Multiply $3$ by $8$ .

$24 x - 16 \cdot 3 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.1.1.2.2

Multiply $- 16$ by $3$ .

$24 x - 48 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - \frac{10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.2

Simplify the right side.

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Step 3.2.2.1

Simplify $- \frac{10 (x - 2)}{3} \cdot 3$ .

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Step 3.2.2.1.1

Cancel the common factor of $3$ .

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Step 3.2.2.1.1.1

Move the leading negative in $- \frac{10 (x - 2)}{3}$ into the numerator.

$24 x - 48 = \frac{- 10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.2.1.1.2

Cancel the common factor.

$24 x - 48 = \frac{- 10 (x - 2)}{3} \cdot 3$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.2.1.1.3

Rewrite the expression.

$24 x - 48 = - 10 (x - 2)$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - 10 (x - 2)$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.2.1.2

Apply the distributive property.

$24 x - 48 = - 10 x - 10 \cdot - 2$

$y = - \frac{2 (x + 1)}{3}$

Step 3.2.2.1.3

Multiply $- 10$ by $- 2$ .

$24 x - 48 = - 10 x + 20$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - 10 x + 20$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - 10 x + 20$

$y = - \frac{2 (x + 1)}{3}$

$24 x - 48 = - 10 x + 20$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3

Solve for $x$ .

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Step 3.3.1

Move all terms containing $x$ to the left side of the equation.

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Step 3.3.1.1

Add $10 x$ to both sides of the equation.

$24 x - 48 + 10 x = 20$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.1.2

Add $24 x$ and $10 x$ .

$34 x - 48 = 20$

$y = - \frac{2 (x + 1)}{3}$

$34 x - 48 = 20$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.2

Move all terms not containing $x$ to the right side of the equation.

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Step 3.3.2.1

Add $48$ to both sides of the equation.

$34 x = 20 + 48$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.2.2

Add $20$ and $48$ .

$34 x = 68$

$y = - \frac{2 (x + 1)}{3}$

$34 x = 68$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.3

Divide each term in $34 x = 68$ by $34$ and simplify.

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Step 3.3.3.1

Divide each term in $34 x = 68$ by $34$ .

$\frac{34 x}{34} = \frac{68}{34}$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.3.2

Simplify the left side.

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Step 3.3.3.2.1

Cancel the common factor of $34$ .

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Step 3.3.3.2.1.1

Cancel the common factor.

$\frac{34 x}{34} = \frac{68}{34}$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.3.2.1.2

Divide $x$ by $1$ .

$x = \frac{68}{34}$

$y = - \frac{2 (x + 1)}{3}$

$x = \frac{68}{34}$

$y = - \frac{2 (x + 1)}{3}$

$x = \frac{68}{34}$

$y = - \frac{2 (x + 1)}{3}$

Step 3.3.3.3

Simplify the right side.

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Step 3.3.3.3.1

Divide $68$ by $34$ .

$x = 2$

$y = - \frac{2 (x + 1)}{3}$

$x = 2$

$y = - \frac{2 (x + 1)}{3}$

$x = 2$

$y = - \frac{2 (x + 1)}{3}$

$x = 2$

$y = - \frac{2 (x + 1)}{3}$

$x = 2$

$y = - \frac{2 (x + 1)}{3}$

Step 4

Replace all occurrences of $x$ with $2$ in each equation.

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Step 4.1

Replace all occurrences of $x$ in $y = - \frac{2 (x + 1)}{3}$ with $2$ .

$y = - \frac{2 ((2) + 1)}{3}$

$x = 2$

Step 4.2

Simplify the right side.

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Step 4.2.1

Simplify $- \frac{2 ((2) + 1)}{3}$ .

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Step 4.2.1.1

Add $2$ and $1$ .

$y = - \frac{2 \cdot 3}{3}$

$x = 2$

Step 4.2.1.2

Multiply $2$ by $3$ .

$y = - \frac{6}{3}$

$x = 2$

Step 4.2.1.3

Divide $6$ by $3$ .

$y = - 1 \cdot 2$

$x = 2$

Step 4.2.1.4

Multiply $- 1$ by $2$ .

$y = - 2$

$x = 2$

$y = - 2$

$x = 2$

$y = - 2$

$x = 2$

$y = - 2$

$x = 2$

Step 5

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, - 2)$

Step 6

The result can be shown in multiple forms.

Point Form:

$(2, - 2)$

Equation Form:

$x = 2, y = - 2$

Step 7