Finite Math Examples

f (x) = - 6 x + 7 e^{- 9 x}

$f (x) = - 6 x + 7 e^{- 9 x}$ ,

x - 1 = 1

$x - 1 = 1$

Step 1

Replace the variable

x

$x$ with

1

$1$ in the expression.

f (1) = - 6 \cdot 1 + 7 e^{- 9 \cdot 1}

$f (1) = - 6 \cdot 1 + 7 e^{- 9 \cdot 1}$

Step 2

Simplify the result.

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Step 2.1

Simplify each term.

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Step 2.1.1

Multiply

- 6

$- 6$ by

1

$1$ .

f (1) = - 6 + 7 e^{- 9 \cdot 1}

$f (1) = - 6 + 7 e^{- 9 \cdot 1}$

Step 2.1.2

Multiply

- 9

$- 9$ by

1

$1$ .

f (1) = - 6 + 7 e^{- 9}

$f (1) = - 6 + 7 e^{- 9}$

Step 2.1.3

Rewrite the expression using the negative exponent rule

b^{- n} = \frac{1}{b^{n}}

$b^{- n} = \frac{1}{b^{n}}$ .

f (1) = - 6 + 7 (\frac{1}{e^{9}})

$f (1) = - 6 + 7 (\frac{1}{e^{9}})$

Step 2.1.4

Combine

7

$7$ and

\frac{1}{e^{9}}

$\frac{1}{e^{9}}$ .

f (1) = - 6 + \frac{7}{e^{9}}

$f (1) = - 6 + \frac{7}{e^{9}}$

f (1) = - 6 + \frac{7}{e^{9}}

$f (1) = - 6 + \frac{7}{e^{9}}$

Step 2.2

The final answer is

- 6 + \frac{7}{e^{9}}

$- 6 + \frac{7}{e^{9}}$ .

- 6 + \frac{7}{e^{9}}

$- 6 + \frac{7}{e^{9}}$

- 6 + \frac{7}{e^{9}}

$- 6 + \frac{7}{e^{9}}$

Step 3

The result can be shown in multiple forms.

Exact Form:

- 6 + \frac{7}{e^{9}}

$- 6 + \frac{7}{e^{9}}$

Decimal Form:

- 5.99913613 \dots

$- 5.99913613 \dots$

Step 4

⎡ ⎢ ⎣ \begin{matrix} x^{2} & \frac{1}{2} \sqrt{π} & \int x d x \end{matrix} ⎤ ⎥ ⎦

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$