Finite Math Examples

$14 - 3 (2 x + 1) = 5 - 4 x$

Step 1

Simplify $14 - 3 (2 x + 1)$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Apply the distributive property.

$14 - 3 (2 x) - 3 \cdot 1 = 5 - 4 x$

Step 1.1.2

Multiply $2$ by $- 3$ .

$14 - 6 x - 3 \cdot 1 = 5 - 4 x$

Step 1.1.3

Multiply $- 3$ by $1$ .

$14 - 6 x - 3 = 5 - 4 x$

Step 1.2

Subtract $3$ from $14$ .

$- 6 x + 11 = 5 - 4 x$

Step 2

Move all terms containing $x$ to the left side of the equation.

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Step 2.1

Add $4 x$ to both sides of the equation.

$- 6 x + 11 + 4 x = 5$

Step 2.2

Add $- 6 x$ and $4 x$ .

$- 2 x + 11 = 5$

Step 3

Move all terms not containing $x$ to the right side of the equation.

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Step 3.1

Subtract $11$ from both sides of the equation.

$- 2 x = 5 - 11$

Step 3.2

Subtract $11$ from $5$ .

$- 2 x = - 6$

Step 4

Divide each term in $- 2 x = - 6$ by $- 2$ and simplify.

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Step 4.1

Divide each term in $- 2 x = - 6$ by $- 2$ .

$\frac{- 2 x}{- 2} = \frac{- 6}{- 2}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $- 2$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{- 2 x}{- 2} = \frac{- 6}{- 2}$

Step 4.2.1.2

Divide $x$ by $1$ .

$x = \frac{- 6}{- 2}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Divide $- 6$ by $- 2$ .

$x = 3$