Finite Math Examples

$2 x^{2} - 7 x - j = 0$

Step 1

Move all terms not containing $j$ to the right side of the equation.

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Step 1.1

Subtract $2 x^{2}$ from both sides of the equation.

$- 7 x - j = - 2 x^{2}$

Step 1.2

Add $7 x$ to both sides of the equation.

$- j = - 2 x^{2} + 7 x$

Step 2

Divide each term in $- j = - 2 x^{2} + 7 x$ by $- 1$ and simplify.

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Step 2.1

Divide each term in $- j = - 2 x^{2} + 7 x$ by $- 1$ .

$\frac{- j}{- 1} = \frac{- 2 x^{2}}{- 1} + \frac{7 x}{- 1}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Dividing two negative values results in a positive value.

$\frac{j}{1} = \frac{- 2 x^{2}}{- 1} + \frac{7 x}{- 1}$

Step 2.2.2

Divide $j$ by $1$ .

$j = \frac{- 2 x^{2}}{- 1} + \frac{7 x}{- 1}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Simplify each term.

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Step 2.3.1.1

Move the negative one from the denominator of $\frac{- 2 x^{2}}{- 1}$ .

$j = - 1 \cdot (- 2 x^{2}) + \frac{7 x}{- 1}$

Step 2.3.1.2

Rewrite $- 1 \cdot (- 2 x^{2})$ as $- (- 2 x^{2})$ .

$j = - (- 2 x^{2}) + \frac{7 x}{- 1}$

Step 2.3.1.3

Multiply $- 2$ by $- 1$ .

$j = 2 x^{2} + \frac{7 x}{- 1}$

Step 2.3.1.4

Move the negative one from the denominator of $\frac{7 x}{- 1}$ .

$j = 2 x^{2} - 1 \cdot (7 x)$

Step 2.3.1.5

Rewrite $- 1 \cdot (7 x)$ as $- (7 x)$ .

$j = 2 x^{2} - (7 x)$

Step 2.3.1.6

Multiply $7$ by $- 1$ .

$j = 2 x^{2} - 7 x$