Finite Math Examples

$9000 = p {(1 + 0.045)}^{20}$

Step 1

Rewrite the equation as $p {(1 + 0.045)}^{20} = 9000$ .

$p {(1 + 0.045)}^{20} = 9000$

Step 2

Add $1$ and $0.045$ .

$p \cdot {1.045}^{20} = 9000$

Step 3

Divide each term in $p \cdot {1.045}^{20} = 9000$ by ${1.045}^{20}$ and simplify.

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Step 3.1

Divide each term in $p \cdot {1.045}^{20} = 9000$ by ${1.045}^{20}$ .

$\frac{p \cdot {1.045}^{20}}{{1.045}^{20}} = \frac{9000}{{1.045}^{20}}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of ${1.045}^{20}$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{p \cdot {1.045}^{20}}{{1.045}^{20}} = \frac{9000}{{1.045}^{20}}$

Step 3.2.1.2

Divide $p$ by $1$ .

$p = \frac{9000}{{1.045}^{20}}$

Step 3.3

Simplify the right side.

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Step 3.3.1

Raise $1.045$ to the power of $20$ .

$p = \frac{9000}{2.41171402}$

Step 3.3.2

Divide $9000$ by $2.41171402$ .

$p = 3731.78573716$