Finite Math Examples

$60000 = p {(1 + 125)}^{24}$

Step 1

Rewrite the equation as $p {(1 + 125)}^{24} = 60000$ .

$p {(1 + 125)}^{24} = 60000$

Step 2

Add $1$ and $125$ .

$p \cdot 126^{24} = 60000$

Step 3

Divide each term in $p \cdot 126^{24} = 60000$ by $126^{24}$ and simplify.

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Step 3.1

Divide each term in $p \cdot 126^{24} = 60000$ by $126^{24}$ .

$\frac{p \cdot 126^{24}}{126^{24}} = \frac{60000}{126^{24}}$

Step 3.2

Simplify the left side.

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Step 3.2.1

Cancel the common factor of $126^{24}$ .

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Step 3.2.1.1

Cancel the common factor.

$\frac{p \cdot 126^{24}}{126^{24}} = \frac{60000}{126^{24}}$

Step 3.2.1.2

Divide $p$ by $1$ .

$p = \frac{60000}{126^{24}}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$p = \frac{60000}{126^{24}}$

Decimal Form:

$p = 2.34022798 \cdot 10^{- 46}$