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Finite Math
Solve for x b=(x-(2+2i))(x-(2-2i)(x+2)(x-1))
b
=
(
x
−
(
2
+
2
i
)
)
(
x
−
(
2
−
2
i
)
(
x
+
2
)
(
x
−
1
)
)
b
=
(
x
-
(
2
+
2
i
)
)
(
x
-
(
2
-
2
i
)
(
x
+
2
)
(
x
-
1
)
)
Step 1
Rewrite the
equation
as
(
x
−
(
2
+
2
i
)
)
(
x
−
(
2
−
2
i
)
(
x
+
2
)
(
x
−
1
)
)
=
b
(
x
-
(
2
+
2
i
)
)
(
x
-
(
2
-
2
i
)
(
x
+
2
)
(
x
-
1
)
)
=
b
.
(
x
−
(
2
+
2
i
)
)
(
x
−
(
2
−
2
i
)
(
x
+
2
)
(
x
−
1
)
)
=
b
(
x
-
(
2
+
2
i
)
)
(
x
-
(
2
-
2
i
)
(
x
+
2
)
(
x
-
1
)
)
=
b
⎡
⎢
⎣
x
2
1
2
√
π
∫
x
d
x
⎤
⎥
⎦
[
x
2
1
2
π
∫
x
d
x
]
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