Finite Math Examples

$g (- 1) = - 1^{2} + 2 (- 1) + 3$

Step 1

Divide each term in $g (- 1) = - 1^{2} + 2 (- 1) + 3$ by $- 1$ .

$\frac{g \cdot - 1}{- 1} = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 2

Simplify the left side.

Tap for more steps...

Step 2.1

Move the negative one from the denominator of $\frac{g \cdot - 1}{- 1}$ .

$- 1 \cdot (g \cdot - 1) = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 2.2

Rewrite $- 1 \cdot (g \cdot - 1)$ as $- (g \cdot - 1)$ .

$- (g \cdot - 1) = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 2.3

Move $- 1$ to the left of $g$ .

$- (- 1 \cdot g) = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 2.4

Rewrite $- 1 g$ as $- g$ .

$- - g = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 2.5

Multiply $- - g$ .

Tap for more steps...

Step 2.5.1

Multiply $- 1$ by $- 1$ .

$1 g = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 2.5.2

Multiply $g$ by $1$ .

$g = \frac{- 1^{2}}{- 1} + \frac{2 (- 1)}{- 1} + \frac{3}{- 1}$

Step 3

Simplify the right side.

Tap for more steps...

Step 3.1

Combine the numerators over the common denominator.

$g = \frac{- 1^{2} + 2 (- 1) + 3}{- 1}$

Step 3.2

Simplify each term.

Tap for more steps...

Step 3.2.1

One to any power is one.

$g = \frac{- 1 \cdot 1 + 2 (- 1) + 3}{- 1}$

Step 3.2.2

Multiply $- 1$ by $1$ .

$g = \frac{- 1 + 2 (- 1) + 3}{- 1}$

Step 3.2.3

Multiply $2$ by $- 1$ .

$g = \frac{- 1 - 2 + 3}{- 1}$

Step 3.3

Simplify the expression.

Tap for more steps...

Step 3.3.1

Subtract $2$ from $- 1$ .

$g = \frac{- 3 + 3}{- 1}$

Step 3.3.2

Add $- 3$ and $3$ .

$g = \frac{0}{- 1}$

Step 3.3.3

Divide $0$ by $- 1$ .

$g = 0$