Finite Math Examples

$x = \frac{7 - v^{49} - 4 \cdot 8 \cdot - 1}{16}$

Step 1

Simplify the numerator.

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Step 1.1

Multiply $- 4 \cdot 8 \cdot - 1$ .

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Step 1.1.1

Multiply $- 4$ by $8$ .

$x = \frac{7 - v^{49} - 32 \cdot - 1}{16}$

Step 1.1.2

Multiply $- 32$ by $- 1$ .

$x = \frac{7 - v^{49} + 32}{16}$

$x = \frac{7 - v^{49} + 32}{16}$

Step 1.2

Add $7$ and $32$ .

$x = \frac{- v^{49} + 39}{16}$

$x = \frac{- v^{49} + 39}{16}$

Step 2

Simplify with factoring out.

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Step 2.1

Factor $- 1$ out of $- v^{49}$ .

$x = \frac{- (v^{49}) + 39}{16}$

Step 2.2

Rewrite $39$ as $- 1 (- 39)$ .

$x = \frac{- (v^{49}) - 1 (- 39)}{16}$

Step 2.3

Factor $- 1$ out of $- (v^{49}) - 1 (- 39)$ .

$x = \frac{- (v^{49} - 39)}{16}$

Step 2.4

Simplify the expression.

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Step 2.4.1

Rewrite $- (v^{49} - 39)$ as $- 1 (v^{49} - 39)$ .

$x = \frac{- 1 (v^{49} - 39)}{16}$

Step 2.4.2

Move the negative in front of the fraction.

$x = - \frac{v^{49} - 39}{16}$

$x = - \frac{v^{49} - 39}{16}$

$x = - \frac{v^{49} - 39}{16}$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$