Finite Math Examples

$\ln (\ln (x - e^{6} x)) = 0$

Step 1

To solve for $x$ , rewrite the equation using properties of logarithms.

$e^{\ln (\ln (x - e^{6} x))} = e^{0}$

Step 2

Rewrite $\ln (\ln (x - e^{6} x)) = 0$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$e^{0} = \ln (x - e^{6} x)$

Step 3

Solve for $x$ .

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Step 3.1

Rewrite the equation as $\ln (x - e^{6} x) = e^{0}$ .

$\ln (x - e^{6} x) = e^{0}$

Step 3.2

To solve for $x$ , rewrite the equation using properties of logarithms.

$e^{\ln (x - e^{6} x)} = e^{e^{0}}$

Step 3.3

Rewrite $\ln (x - e^{6} x) = e^{0}$ in exponential form using the definition of a logarithm. If $x$ and $b$ are positive real numbers and $b \neq 1$ , then $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ .

$e^{e^{0}} = x - e^{6} x$

Step 3.4

Solve for $x$ .

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Step 3.4.1

Rewrite the equation as $x - e^{6} x = e^{e^{0}}$ .

$x - e^{6} x = e^{e^{0}}$

Step 3.4.2

Simplify $e^{e^{0}}$ .

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Step 3.4.2.1

Anything raised to $0$ is $1$ .

$x - e^{6} x = e^{1}$

Step 3.4.2.2

Simplify.

$x - e^{6} x = e$

Step 3.4.3

Factor the left side of the equation.

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Step 3.4.3.1

Factor $x$ out of $x - e^{6} x$ .

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Step 3.4.3.1.1

Raise $x$ to the power of $1$ .

$x - e^{6} x = e$

Step 3.4.3.1.2

Factor $x$ out of $x^{1}$ .

$x \cdot 1 - e^{6} x = e$

Step 3.4.3.1.3

Factor $x$ out of $- e^{6} x$ .

$x \cdot 1 + x (- e^{6}) = e$

Step 3.4.3.1.4

Factor $x$ out of $x \cdot 1 + x (- e^{6})$ .

$x (1 - e^{6}) = e$

Step 3.4.3.2

Rewrite $1$ as $1^{3}$ .

$x (1^{3} - e^{6}) = e$

Step 3.4.3.3

Rewrite $e^{6}$ as ${(e^{2})}^{3}$ .

$x (1^{3} - {(e^{2})}^{3}) = e$

Step 3.4.3.4

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 1$ and $b = e^{2}$ .

$x ((1 - e^{2}) (1^{2} + 1 e^{2} + {(e^{2})}^{2})) = e$

Step 3.4.3.5

Factor.

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Step 3.4.3.5.1

Simplify.

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Step 3.4.3.5.1.1

Rewrite $1$ as $1^{2}$ .

$x ((1^{2} - e^{2}) (1^{2} + 1 e^{2} + {(e^{2})}^{2})) = e$

Step 3.4.3.5.1.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = e$ .

$x ((1 + e) (1 - e) (1^{2} + 1 e^{2} + {(e^{2})}^{2})) = e$

Step 3.4.3.5.1.3

Multiply $e^{2}$ by $1$ .

$x ((1 + e) (1 - e) (1^{2} + e^{2} + {(e^{2})}^{2})) = e$

Step 3.4.3.5.2

Remove unnecessary parentheses.

$x (1 + e) (1 - e) (1^{2} + e^{2} + {(e^{2})}^{2}) = e$

Step 3.4.3.6

One to any power is one.

$x (1 + e) (1 - e) (1 + e^{2} + {(e^{2})}^{2}) = e$

Step 3.4.3.7

Multiply the exponents in ${(e^{2})}^{2}$ .

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Step 3.4.3.7.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x (1 + e) (1 - e) (1 + e^{2} + e^{2 \cdot 2}) = e$

Step 3.4.3.7.2

Multiply $2$ by $2$ .

$x (1 + e) (1 - e) (1 + e^{2} + e^{4}) = e$

Step 3.4.4

Divide each term in $x (1 + e) (1 - e) (1 + e^{2} + e^{4}) = e$ by $1 - e^{6}$ and simplify.

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Step 3.4.4.1

Divide each term in $x (1 + e) (1 - e) (1 + e^{2} + e^{4}) = e$ by $1 - e^{6}$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{1 - e^{6}} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2

Simplify the left side.

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Step 3.4.4.2.1

Simplify the denominator.

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Step 3.4.4.2.1.1

Rewrite $1$ as $1^{3}$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{1^{3} - e^{6}} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.2

Rewrite $e^{6}$ as ${(e^{2})}^{3}$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{1^{3} - {(e^{2})}^{3}} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.3

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 1$ and $b = e^{2}$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 - e^{2}) (1^{2} + 1 e^{2} + {(e^{2})}^{2})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.4

Simplify.

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Step 3.4.4.2.1.4.1

Rewrite $1$ as $1^{2}$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1^{2} - e^{2}) (1^{2} + 1 e^{2} + {(e^{2})}^{2})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.4.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = e$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 + e) (1 - e) (1^{2} + 1 e^{2} + {(e^{2})}^{2})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.4.3

Multiply $e^{2}$ by $1$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 + e) (1 - e) (1^{2} + e^{2} + {(e^{2})}^{2})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.5

Simplify each term.

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Step 3.4.4.2.1.5.1

One to any power is one.

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 + e) (1 - e) (1 + e^{2} + {(e^{2})}^{2})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.5.2

Multiply the exponents in ${(e^{2})}^{2}$ .

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Step 3.4.4.2.1.5.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 + e) (1 - e) (1 + e^{2} + e^{2 \cdot 2})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.1.5.2.2

Multiply $2$ by $2$ .

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 + e) (1 - e) (1 + e^{2} + e^{4})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.2

Reduce the expression by cancelling the common factors.

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Step 3.4.4.2.2.1

Cancel the common factor of $1 + e$ .

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Step 3.4.4.2.2.1.1

Cancel the common factor.

$\frac{x (1 + e) (1 - e) (1 + e^{2} + e^{4})}{(1 + e) (1 - e) (1 + e^{2} + e^{4})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.2.1.2

Rewrite the expression.

$\frac{(x (1 - e)) (1 + e^{2} + e^{4})}{(1 - e) (1 + e^{2} + e^{4})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.2.2

Cancel the common factor of $1 - e$ .

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Step 3.4.4.2.2.2.1

Cancel the common factor.

$\frac{x (1 - e) (1 + e^{2} + e^{4})}{(1 - e) (1 + e^{2} + e^{4})} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.2.2.2

Rewrite the expression.

$\frac{(x) (1 + e^{2} + e^{4})}{1 + e^{2} + e^{4}} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.2.3

Cancel the common factor of $1 + e^{2} + e^{4}$ .

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Step 3.4.4.2.2.3.1

Cancel the common factor.

$\frac{x (1 + e^{2} + e^{4})}{1 + e^{2} + e^{4}} = \frac{e}{1 - e^{6}}$

Step 3.4.4.2.2.3.2

Divide $x$ by $1$ .

$x = \frac{e}{1 - e^{6}}$

Step 3.4.4.3

Simplify the right side.

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Step 3.4.4.3.1

Simplify the denominator.

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Step 3.4.4.3.1.1

Rewrite $1$ as $1^{3}$ .

$x = \frac{e}{1^{3} - e^{6}}$

Step 3.4.4.3.1.2

Rewrite $e^{6}$ as ${(e^{2})}^{3}$ .

$x = \frac{e}{1^{3} - {(e^{2})}^{3}}$

Step 3.4.4.3.1.3

Since both terms are perfect cubes, factor using the difference of cubes formula, $a^{3} - b^{3} = (a - b) (a^{2} + a b + b^{2})$ where $a = 1$ and $b = e^{2}$ .

$x = \frac{e}{(1 - e^{2}) (1^{2} + 1 e^{2} + {(e^{2})}^{2})}$

Step 3.4.4.3.1.4

Simplify.

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Step 3.4.4.3.1.4.1

Rewrite $1$ as $1^{2}$ .

$x = \frac{e}{(1^{2} - e^{2}) (1^{2} + 1 e^{2} + {(e^{2})}^{2})}$

Step 3.4.4.3.1.4.2

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = 1$ and $b = e$ .

$x = \frac{e}{(1 + e) (1 - e) (1^{2} + 1 e^{2} + {(e^{2})}^{2})}$

Step 3.4.4.3.1.4.3

Multiply $e^{2}$ by $1$ .

$x = \frac{e}{(1 + e) (1 - e) (1^{2} + e^{2} + {(e^{2})}^{2})}$

Step 3.4.4.3.1.5

Simplify each term.

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Step 3.4.4.3.1.5.1

One to any power is one.

$x = \frac{e}{(1 + e) (1 - e) (1 + e^{2} + {(e^{2})}^{2})}$

Step 3.4.4.3.1.5.2

Multiply the exponents in ${(e^{2})}^{2}$ .

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Step 3.4.4.3.1.5.2.1

Apply the power rule and multiply exponents, ${(a^{m})}^{n} = a^{m n}$ .

$x = \frac{e}{(1 + e) (1 - e) (1 + e^{2} + e^{2 \cdot 2})}$

Step 3.4.4.3.1.5.2.2

Multiply $2$ by $2$ .

$x = \frac{e}{(1 + e) (1 - e) (1 + e^{2} + e^{4})}$

Step 4

The result can be shown in multiple forms.

Exact Form:

$x = \frac{e}{(1 + e) (1 - e) (1 + e^{2} + e^{4})}$

Decimal Form:

$x = - 0.00675469 \dots$