Finite Math Examples

$\log (8) (h) = 8 x + 6$

Step 1

Rewrite the equation as $8 x + 6 = \log (8) h$ .

$8 x + 6 = \log (8) h$

Step 2

Reorder factors in $\log (8) h$ .

$8 x + 6 = h \log (8)$

Step 3

Subtract $6$ from both sides of the equation.

$8 x = h \log (8) - 6$

Step 4

Divide each term in $8 x = h \log (8) - 6$ by $8$ and simplify.

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Step 4.1

Divide each term in $8 x = h \log (8) - 6$ by $8$ .

$\frac{8 x}{8} = \frac{h \log (8)}{8} + \frac{- 6}{8}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Cancel the common factor of $8$ .

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Step 4.2.1.1

Cancel the common factor.

$\frac{8 x}{8} = \frac{h \log (8)}{8} + \frac{- 6}{8}$

Step 4.2.1.2

Divide $x$ by $1$ .

$x = \frac{h \log (8)}{8} + \frac{- 6}{8}$

Step 4.3

Simplify the right side.

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Step 4.3.1

Simplify each term.

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Step 4.3.1.1

Cancel the common factor of $- 6$ and $8$ .

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Step 4.3.1.1.1

Factor $2$ out of $- 6$ .

$x = \frac{h \log (8)}{8} + \frac{2 (- 3)}{8}$

Step 4.3.1.1.2

Cancel the common factors.

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Step 4.3.1.1.2.1

Factor $2$ out of $8$ .

$x = \frac{h \log (8)}{8} + \frac{2 \cdot - 3}{2 \cdot 4}$

Step 4.3.1.1.2.2

Cancel the common factor.

$x = \frac{h \log (8)}{8} + \frac{2 \cdot - 3}{2 \cdot 4}$

Step 4.3.1.1.2.3

Rewrite the expression.

$x = \frac{h \log (8)}{8} + \frac{- 3}{4}$

Step 4.3.1.2

Move the negative in front of the fraction.

$x = \frac{h \log (8)}{8} - \frac{3}{4}$