Finite Math Examples

$6 x + 12 - 9 x = 16 - 13 x + 10 x - 4$

Step 1

Subtract $9 x$ from $6 x$ .

$- 3 x + 12 = 16 - 13 x + 10 x - 4$

Step 2

Simplify $16 - 13 x + 10 x - 4$ .

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Step 2.1

Subtract $4$ from $16$ .

$- 3 x + 12 = - 13 x + 10 x + 12$

Step 2.2

Add $- 13 x$ and $10 x$ .

$- 3 x + 12 = - 3 x + 12$

Step 3

Move all terms containing $x$ to the left side of the equation.

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Step 3.1

Add $3 x$ to both sides of the equation.

$- 3 x + 12 + 3 x = 12$

Step 3.2

Combine the opposite terms in $- 3 x + 12 + 3 x$ .

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Step 3.2.1

Add $- 3 x$ and $3 x$ .

$0 + 12 = 12$

Step 3.2.2

Add $0$ and $12$ .

$12 = 12$

Step 4

Since $12 = 12$ , the equation will always be true for any value of $x$ .

All real numbers

Step 5

The result can be shown in multiple forms.

All real numbers

Interval Notation:

$(- \infty, \infty)$