Finite Math Examples

$y^{3} = 36 y$

Step 1

Subtract $36 y$ from both sides of the equation.

$y^{3} - 36 y = 0$

Step 2

Factor the left side of the equation.

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Step 2.1

Factor $y$ out of $y^{3} - 36 y$ .

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Step 2.1.1

Factor $y$ out of $y^{3}$ .

$y \cdot y^{2} - 36 y = 0$

Step 2.1.2

Factor $y$ out of $- 36 y$ .

$y \cdot y^{2} + y \cdot - 36 = 0$

Step 2.1.3

Factor $y$ out of $y \cdot y^{2} + y \cdot - 36$ .

$y (y^{2} - 36) = 0$

Step 2.2

Rewrite $36$ as $6^{2}$ .

$y (y^{2} - 6^{2}) = 0$

Step 2.3

Factor.

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Step 2.3.1

Since both terms are perfect squares, factor using the difference of squares formula, $a^{2} - b^{2} = (a + b) (a - b)$ where $a = y$ and $b = 6$ .

$y ((y + 6) (y - 6)) = 0$

Step 2.3.2

Remove unnecessary parentheses.

$y (y + 6) (y - 6) = 0$

Step 3

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$y = 0$

$y + 6 = 0$

$y - 6 = 0$

Step 4

Set $y$ equal to $0$ .

$y = 0$

Step 5

Set $y + 6$ equal to $0$ and solve for $y$ .

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Step 5.1

Set $y + 6$ equal to $0$ .

$y + 6 = 0$

Step 5.2

Subtract $6$ from both sides of the equation.

$y = - 6$

Step 6

Set $y - 6$ equal to $0$ and solve for $y$ .

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Step 6.1

Set $y - 6$ equal to $0$ .

$y - 6 = 0$

Step 6.2

Add $6$ to both sides of the equation.

$y = 6$

Step 7

The final solution is all the values that make $y (y + 6) (y - 6) = 0$ true.

$y = 0, - 6, 6$