Finite Math Examples

$\frac{1}{2} \cdot ((\frac{p \cdot 4}{3} \cdot (p (7))) (2800))$

Step 1

Rewrite using the commutative property of multiplication.

$\frac{1}{2} \cdot (7 \frac{p \cdot 4}{3} p \cdot 2800)$

Step 2

Move $4$ to the left of $p$ .

$\frac{1}{2} \cdot (7 \frac{4 \cdot p}{3} p \cdot 2800)$

Step 3

Multiply $7 \frac{4 p}{3}$ .

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Step 3.1

Combine $7$ and $\frac{4 p}{3}$ .

$\frac{1}{2} \cdot (\frac{7 (4 p)}{3} p \cdot 2800)$

Step 3.2

Multiply $4$ by $7$ .

$\frac{1}{2} \cdot (\frac{28 p}{3} p \cdot 2800)$

Step 4

Cancel the common factor of $2$ .

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Step 4.1

Factor $2$ out of $\frac{28 p}{3} p \cdot 2800$ .

$\frac{1}{2} \cdot (2 (\frac{14 p}{3} p \cdot 2800))$

Step 4.2

Cancel the common factor.

$\frac{1}{2} \cdot (2 (\frac{14 p}{3} p \cdot 2800))$

Step 4.3

Rewrite the expression.

$\frac{14 p}{3} p \cdot 2800$

Step 5

Combine $\frac{14 p}{3}$ and $p$ .

$\frac{14 p \cdot p}{3} \cdot 2800$

Step 6

Raise $p$ to the power of $1$ .

$\frac{14 (p^{1} p)}{3} \cdot 2800$

Step 7

Raise $p$ to the power of $1$ .

$\frac{14 (p^{1} p^{1})}{3} \cdot 2800$

Step 8

Use the power rule $a^{m} a^{n} = a^{m + n}$ to combine exponents.

$\frac{14 p^{1 + 1}}{3} \cdot 2800$

Step 9

Add $1$ and $1$ .

$\frac{14 p^{2}}{3} \cdot 2800$

Step 10

Combine $\frac{14 p^{2}}{3}$ and $2800$ .

$\frac{14 p^{2} \cdot 2800}{3}$

Step 11

Multiply $2800$ by $14$ .

$\frac{39200 p^{2}}{3}$