Finite Math Examples

$9 (b + 3) = 9 x - 8$

Step 1

Divide each term in $9 (b + 3) = 9 x - 8$ by $9$ and simplify.

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Step 1.1

Divide each term in $9 (b + 3) = 9 x - 8$ by $9$ .

$\frac{9 (b + 3)}{9} = \frac{9 x}{9} + \frac{- 8}{9}$

Step 1.2

Simplify the left side.

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Step 1.2.1

Cancel the common factor of $9$ .

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Step 1.2.1.1

Cancel the common factor.

$\frac{9 (b + 3)}{9} = \frac{9 x}{9} + \frac{- 8}{9}$

Step 1.2.1.2

Divide $b + 3$ by $1$ .

$b + 3 = \frac{9 x}{9} + \frac{- 8}{9}$

Step 1.3

Simplify the right side.

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Step 1.3.1

Simplify each term.

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Step 1.3.1.1

Cancel the common factor of $9$ .

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Step 1.3.1.1.1

Cancel the common factor.

$b + 3 = \frac{9 x}{9} + \frac{- 8}{9}$

Step 1.3.1.1.2

Divide $x$ by $1$ .

$b + 3 = x + \frac{- 8}{9}$

Step 1.3.1.2

Move the negative in front of the fraction.

$b + 3 = x - \frac{8}{9}$

Step 2

Move all terms not containing $b$ to the right side of the equation.

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Step 2.1

Subtract $3$ from both sides of the equation.

$b = x - \frac{8}{9} - 3$

Step 2.2

To write $- 3$ as a fraction with a common denominator, multiply by $\frac{9}{9}$ .

$b = x - \frac{8}{9} - 3 \cdot \frac{9}{9}$

Step 2.3

Combine $- 3$ and $\frac{9}{9}$ .

$b = x - \frac{8}{9} + \frac{- 3 \cdot 9}{9}$

Step 2.4

Combine the numerators over the common denominator.

$b = x + \frac{- 8 - 3 \cdot 9}{9}$

Step 2.5

Simplify the numerator.

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Step 2.5.1

Multiply $- 3$ by $9$ .

$b = x + \frac{- 8 - 27}{9}$

Step 2.5.2

Subtract $27$ from $- 8$ .

$b = x + \frac{- 35}{9}$

Step 2.6

Move the negative in front of the fraction.

$b = x - \frac{35}{9}$