Finite Math Examples

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{2 (p^{78})}{56 + 98 g^{9}}} = 52$

Step 1

Cancel the common factor of $2$ and $56 + 98 g^{9}$ .

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Step 1.1

Factor $2$ out of $2 p^{78}$ .

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{2 (p^{78})}{56 + 98 g^{9}}} = 52$

Step 1.2

Cancel the common factors.

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Step 1.2.1

Factor $2$ out of $56$ .

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{2 p^{78}}{2 \cdot 28 + 98 g^{9}}} = 52$

Step 1.2.2

Factor $2$ out of $98 g^{9}$ .

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{2 p^{78}}{2 \cdot 28 + 2 (49 g^{9})}} = 52$

Step 1.2.3

Factor $2$ out of $2 (28) + 2 (49 g^{9})$ .

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{2 p^{78}}{2 (28 + 49 g^{9})}} = 52$

Step 1.2.4

Cancel the common factor.

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{2 p^{78}}{2 (28 + 49 g^{9})}} = 52$

Step 1.2.5

Rewrite the expression.

$\frac{2 p^{8} \cdot (869 j^{9}) - o^{96}}{\frac{p^{78}}{28 + 49 g^{9}}} = 52$

Step 2

Multiply the numerator by the reciprocal of the denominator.

$(2 p^{8} \cdot 869 j^{9} - o^{96}) \frac{28 + 49 g^{9}}{p^{78}} = 52$

Step 3

Factor $7$ out of $28 + 49 g^{9}$ .

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Step 3.1

Factor $7$ out of $28$ .

$(2 p^{8} \cdot 869 j^{9} - o^{96}) \frac{7 (4) + 49 g^{9}}{p^{78}} = 52$

Step 3.2

Factor $7$ out of $49 g^{9}$ .

$(2 p^{8} \cdot 869 j^{9} - o^{96}) \frac{7 (4) + 7 (7 g^{9})}{p^{78}} = 52$

Step 3.3

Factor $7$ out of $7 (4) + 7 (7 g^{9})$ .

$(2 p^{8} \cdot 869 j^{9} - o^{96}) \frac{7 (4 + 7 g^{9})}{p^{78}} = 52$

Step 4

Multiply $869$ by $2$ .

$(1738 p^{8} j^{9} - o^{96}) \frac{7 (4 + 7 g^{9})}{p^{78}} = 52$

Step 5

Multiply $1738 p^{8} j^{9} - o^{96}$ by $\frac{7 (4 + 7 g^{9})}{p^{78}}$ .

$\frac{(1738 p^{8} j^{9} - o^{96}) (7 (4 + 7 g^{9}))}{p^{78}} = 52$

Step 6

Move $7$ to the left of $1738 p^{8} j^{9} - o^{96}$ .

$\frac{7 (1738 p^{8} j^{9} - o^{96}) (4 + 7 g^{9})}{p^{78}} = 52$