Finite Math Examples

$0.8 t \cdot 1 - 0.6 t \cdot 2 = 16$

Step 1

Simplify $0.8 t \cdot 1 - 0.6 t \cdot 2$ .

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Step 1.1

Simplify each term.

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Step 1.1.1

Multiply $0.8$ by $1$ .

$0.8 t - 0.6 t \cdot 2 = 16$

Step 1.1.2

Multiply $2$ by $- 0.6$ .

$0.8 t - 1.2 t = 16$

$0.8 t - 1.2 t = 16$

Step 1.2

Subtract $1.2 t$ from $0.8 t$ .

$- 0.4 t = 16$

$- 0.4 t = 16$

Step 2

Divide each term in $- 0.4 t = 16$ by $- 0.4$ and simplify.

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Step 2.1

Divide each term in $- 0.4 t = 16$ by $- 0.4$ .

$\frac{- 0.4 t}{- 0.4} = \frac{16}{- 0.4}$

Step 2.2

Simplify the left side.

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Step 2.2.1

Cancel the common factor of $- 0.4$ .

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Step 2.2.1.1

Cancel the common factor.

$\frac{- 0.4 t}{- 0.4} = \frac{16}{- 0.4}$

Step 2.2.1.2

Divide $t$ by $1$ .

$t = \frac{16}{- 0.4}$

$t = \frac{16}{- 0.4}$

$t = \frac{16}{- 0.4}$

Step 2.3

Simplify the right side.

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Step 2.3.1

Divide $16$ by $- 0.4$ .

$t = - 40$

$t = - 40$

$t = - 40$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$