Finite Math Examples

$x + y = 40$ , $y = 22$ , $y = 12$ , $x = 28$ , $x = 16$

Step 1

Replace all occurrences of $y$ with $22$ in each equation.

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Step 1.1

Replace all occurrences of $y$ in $x + y = 40$ with $22$ .

$x + 22 = 40$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

Step 1.2

Simplify the left side.

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Step 1.2.1

Remove parentheses.

$x + 22 = 40$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

$x + 22 = 40$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

$x + 22 = 40$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

Step 2

Move all terms not containing $x$ to the right side of the equation.

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Step 2.1

Subtract $22$ from both sides of the equation.

$x = 40 - 22$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

Step 2.2

Subtract $22$ from $40$ .

$x = 18$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

$x = 18$

$y = 22$

$y = 12$

$x = 28$

$x = 16$

Step 3

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(18, 22)$

$(28, 12)$

Step 4

The result can be shown in multiple forms.

Point Form:

$(18, 22), (28, 12)$

Equation Form:

$x = 18, y = 22$

$x = 28, y = 12$

Step 5