Finite Math Examples

$\frac{6 x^{3} - 8 x^{2} + 1}{x + 2}$

Step 1

To calculate the remainder, first divide the polynomials.

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Step 1.1

Set up the polynomials to be divided. If there is not a term for every exponent, insert one with a value of $0$ .

$x$

$2$

$6 x^{3}$

$8 x^{2}$

$0 x$

$1$

Step 1.2

Divide the highest order term in the dividend $6 x^{3}$ by the highest order term in divisor $x$ .

					$6 x^{2}$
	$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$

Step 1.3

Multiply the new quotient term by the divisor.

				$6 x^{2}$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			+	$6 x^{3}$	+	$12 x^{2}$

Step 1.4

The expression needs to be subtracted from the dividend, so change all the signs in $6 x^{3} + 12 x^{2}$

				$6 x^{2}$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$

Step 1.5

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$6 x^{2}$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$

Step 1.6

Pull the next terms from the original dividend down into the current dividend.

				$6 x^{2}$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$

Step 1.7

Divide the highest order term in the dividend $- 20 x^{2}$ by the highest order term in divisor $x$ .

				$6 x^{2}$	-	$20 x$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$

Step 1.8

Multiply the new quotient term by the divisor.

				$6 x^{2}$	-	$20 x$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					-	$20 x^{2}$	-	$40 x$

Step 1.9

The expression needs to be subtracted from the dividend, so change all the signs in $- 20 x^{2} - 40 x$

				$6 x^{2}$	-	$20 x$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$

Step 1.10

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$6 x^{2}$	-	$20 x$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$
							+	$40 x$

Step 1.11

Pull the next terms from the original dividend down into the current dividend.

				$6 x^{2}$	-	$20 x$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$
							+	$40 x$	+	$1$

Step 1.12

Divide the highest order term in the dividend $40 x$ by the highest order term in divisor $x$ .

				$6 x^{2}$	-	$20 x$	+	$40$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$
							+	$40 x$	+	$1$

Step 1.13

Multiply the new quotient term by the divisor.

				$6 x^{2}$	-	$20 x$	+	$40$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$
							+	$40 x$	+	$1$
							+	$40 x$	+	$80$

Step 1.14

The expression needs to be subtracted from the dividend, so change all the signs in $40 x + 80$

				$6 x^{2}$	-	$20 x$	+	$40$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$
							+	$40 x$	+	$1$
							-	$40 x$	-	$80$

Step 1.15

After changing the signs, add the last dividend from the multiplied polynomial to find the new dividend.

				$6 x^{2}$	-	$20 x$	+	$40$
$x$	+	$2$		$6 x^{3}$	-	$8 x^{2}$	+	$0 x$	+	$1$
			-	$6 x^{3}$	-	$12 x^{2}$
					-	$20 x^{2}$	+	$0 x$
					+	$20 x^{2}$	+	$40 x$
							+	$40 x$	+	$1$
							-	$40 x$	-	$80$
									-	$79$

Step 1.16

The final answer is the quotient plus the remainder over the divisor.

$6 x^{2} - 20 x + 40 - \frac{79}{x + 2}$

Step 2

Since the last term in the resulting expression is a fraction, the numerator of the fraction is the remainder.

$- 79$