Finite Math Examples

$x^{2} + y^{2} + 8 x + 2 y + 8 = 0$

Step 1

Use the quadratic formula to find the solutions.

$\frac{- b \pm \sqrt{b^{2} - 4 (a c)}}{2 a}$

Step 2

Substitute the values $a = 1$ , $b = 2$ , and $c = x^{2} + 8 x + 8$ into the quadratic formula and solve for $y$ .

$\frac{- 2 \pm \sqrt{2^{2} - 4 \cdot (1 \cdot (x^{2} + 8 x + 8))}}{2 \cdot 1}$

Step 3

Simplify.

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Step 3.1

Simplify the numerator.

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Step 3.1.1

Raise $2$ to the power of $2$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 \cdot 1 \cdot (x^{2} + 8 x + 8)}}{2 \cdot 1}$

Step 3.1.2

Multiply $- 4$ by $1$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 \cdot (x^{2} + 8 x + 8)}}{2 \cdot 1}$

Step 3.1.3

Apply the distributive property.

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 4 (8 x) - 4 \cdot 8}}{2 \cdot 1}$

Step 3.1.4

Simplify.

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Step 3.1.4.1

Multiply $8$ by $- 4$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 32 x - 4 \cdot 8}}{2 \cdot 1}$

Step 3.1.4.2

Multiply $- 4$ by $8$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 32 x - 32}}{2 \cdot 1}$

Step 3.1.5

Subtract $32$ from $4$ .

$y = \frac{- 2 \pm \sqrt{- 4 x^{2} - 32 x - 28}}{2 \cdot 1}$

Step 3.1.6

Rewrite $- 4 x^{2} - 32 x - 28$ in a factored form.

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Step 3.1.6.1

Factor $4$ out of $- 4 x^{2} - 32 x - 28$ .

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Step 3.1.6.1.1

Factor $4$ out of $- 4 x^{2}$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) - 32 x - 28}}{2 \cdot 1}$

Step 3.1.6.1.2

Factor $4$ out of $- 32 x$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) + 4 (- 8 x) - 28}}{2 \cdot 1}$

Step 3.1.6.1.3

Factor $4$ out of $- 28$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) + 4 (- 8 x) + 4 (- 7)}}{2 \cdot 1}$

Step 3.1.6.1.4

Factor $4$ out of $4 (- x^{2}) + 4 (- 8 x)$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x) + 4 (- 7)}}{2 \cdot 1}$

Step 3.1.6.1.5

Factor $4$ out of $4 (- x^{2} - 8 x) + 4 (- 7)$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x - 7)}}{2 \cdot 1}$

Step 3.1.6.2

Factor by grouping.

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Step 3.1.6.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 1 \cdot - 7 = 7$ and whose sum is $b = - 8$ .

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Step 3.1.6.2.1.1

Factor $- 8$ out of $- 8 x$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x - 7)}}{2 \cdot 1}$

Step 3.1.6.2.1.2

Rewrite $- 8$ as $- 1$ plus $- 7$

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} + (- 1 - 7) x - 7)}}{2 \cdot 1}$

Step 3.1.6.2.1.3

Apply the distributive property.

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 1 x - 7 x - 7)}}{2 \cdot 1}$

Step 3.1.6.2.2

Factor out the greatest common factor from each group.

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Step 3.1.6.2.2.1

Group the first two terms and the last two terms.

$y = \frac{- 2 \pm \sqrt{4 ((- x^{2} - 1 x) - 7 x - 7)}}{2 \cdot 1}$

Step 3.1.6.2.2.2

Factor out the greatest common factor (GCF) from each group.

$y = \frac{- 2 \pm \sqrt{4 (x (- x - 1) + 7 (- x - 1))}}{2 \cdot 1}$

Step 3.1.6.2.3

Factor the polynomial by factoring out the greatest common factor, $- x - 1$ .

$y = \frac{- 2 \pm \sqrt{4 ((- x - 1) (x + 7))}}{2 \cdot 1}$

$y = \frac{- 2 \pm \sqrt{4 (- x - 1) (x + 7)}}{2 \cdot 1}$

Step 3.1.7

Rewrite $4 (- x - 1) (x + 7)$ as $2^{2} ((- x - 1) (x + 7))$ .

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Step 3.1.7.1

Rewrite $4$ as $2^{2}$ .

$y = \frac{- 2 \pm \sqrt{2^{2} (- x - 1) (x + 7)}}{2 \cdot 1}$

Step 3.1.7.2

Add parentheses.

$y = \frac{- 2 \pm \sqrt{2^{2} ((- x - 1) (x + 7))}}{2 \cdot 1}$

Step 3.1.8

Pull terms out from under the radical.

$y = \frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2 \cdot 1}$

Step 3.2

Multiply $2$ by $1$ .

$y = \frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2}$

Step 3.3

Simplify $\frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2}$ .

$y = - 1 \pm \sqrt{(- x - 1) (x + 7)}$

Step 4

Simplify the expression to solve for the $+$ portion of the $\pm$ .

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Step 4.1

Simplify the numerator.

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Step 4.1.1

Raise $2$ to the power of $2$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 \cdot 1 \cdot (x^{2} + 8 x + 8)}}{2 \cdot 1}$

Step 4.1.2

Multiply $- 4$ by $1$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 \cdot (x^{2} + 8 x + 8)}}{2 \cdot 1}$

Step 4.1.3

Apply the distributive property.

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 4 (8 x) - 4 \cdot 8}}{2 \cdot 1}$

Step 4.1.4

Simplify.

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Step 4.1.4.1

Multiply $8$ by $- 4$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 32 x - 4 \cdot 8}}{2 \cdot 1}$

Step 4.1.4.2

Multiply $- 4$ by $8$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 32 x - 32}}{2 \cdot 1}$

Step 4.1.5

Subtract $32$ from $4$ .

$y = \frac{- 2 \pm \sqrt{- 4 x^{2} - 32 x - 28}}{2 \cdot 1}$

Step 4.1.6

Rewrite $- 4 x^{2} - 32 x - 28$ in a factored form.

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Step 4.1.6.1

Factor $4$ out of $- 4 x^{2} - 32 x - 28$ .

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Step 4.1.6.1.1

Factor $4$ out of $- 4 x^{2}$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) - 32 x - 28}}{2 \cdot 1}$

Step 4.1.6.1.2

Factor $4$ out of $- 32 x$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) + 4 (- 8 x) - 28}}{2 \cdot 1}$

Step 4.1.6.1.3

Factor $4$ out of $- 28$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) + 4 (- 8 x) + 4 (- 7)}}{2 \cdot 1}$

Step 4.1.6.1.4

Factor $4$ out of $4 (- x^{2}) + 4 (- 8 x)$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x) + 4 (- 7)}}{2 \cdot 1}$

Step 4.1.6.1.5

Factor $4$ out of $4 (- x^{2} - 8 x) + 4 (- 7)$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x - 7)}}{2 \cdot 1}$

Step 4.1.6.2

Factor by grouping.

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Step 4.1.6.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 1 \cdot - 7 = 7$ and whose sum is $b = - 8$ .

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Step 4.1.6.2.1.1

Factor $- 8$ out of $- 8 x$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x - 7)}}{2 \cdot 1}$

Step 4.1.6.2.1.2

Rewrite $- 8$ as $- 1$ plus $- 7$

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} + (- 1 - 7) x - 7)}}{2 \cdot 1}$

Step 4.1.6.2.1.3

Apply the distributive property.

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 1 x - 7 x - 7)}}{2 \cdot 1}$

Step 4.1.6.2.2

Factor out the greatest common factor from each group.

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Step 4.1.6.2.2.1

Group the first two terms and the last two terms.

$y = \frac{- 2 \pm \sqrt{4 ((- x^{2} - 1 x) - 7 x - 7)}}{2 \cdot 1}$

Step 4.1.6.2.2.2

Factor out the greatest common factor (GCF) from each group.

$y = \frac{- 2 \pm \sqrt{4 (x (- x - 1) + 7 (- x - 1))}}{2 \cdot 1}$

Step 4.1.6.2.3

Factor the polynomial by factoring out the greatest common factor, $- x - 1$ .

$y = \frac{- 2 \pm \sqrt{4 ((- x - 1) (x + 7))}}{2 \cdot 1}$

$y = \frac{- 2 \pm \sqrt{4 (- x - 1) (x + 7)}}{2 \cdot 1}$

Step 4.1.7

Rewrite $4 (- x - 1) (x + 7)$ as $2^{2} ((- x - 1) (x + 7))$ .

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Step 4.1.7.1

Rewrite $4$ as $2^{2}$ .

$y = \frac{- 2 \pm \sqrt{2^{2} (- x - 1) (x + 7)}}{2 \cdot 1}$

Step 4.1.7.2

Add parentheses.

$y = \frac{- 2 \pm \sqrt{2^{2} ((- x - 1) (x + 7))}}{2 \cdot 1}$

Step 4.1.8

Pull terms out from under the radical.

$y = \frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2 \cdot 1}$

Step 4.2

Multiply $2$ by $1$ .

$y = \frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2}$

Step 4.3

Simplify $\frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2}$ .

$y = - 1 \pm \sqrt{(- x - 1) (x + 7)}$

Step 4.4

Change the $\pm$ to $+$ .

$y = - 1 + \sqrt{(- x - 1) (x + 7)}$

Step 5

Simplify the expression to solve for the $-$ portion of the $\pm$ .

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Step 5.1

Simplify the numerator.

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Step 5.1.1

Raise $2$ to the power of $2$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 \cdot 1 \cdot (x^{2} + 8 x + 8)}}{2 \cdot 1}$

Step 5.1.2

Multiply $- 4$ by $1$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 \cdot (x^{2} + 8 x + 8)}}{2 \cdot 1}$

Step 5.1.3

Apply the distributive property.

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 4 (8 x) - 4 \cdot 8}}{2 \cdot 1}$

Step 5.1.4

Simplify.

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Step 5.1.4.1

Multiply $8$ by $- 4$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 32 x - 4 \cdot 8}}{2 \cdot 1}$

Step 5.1.4.2

Multiply $- 4$ by $8$ .

$y = \frac{- 2 \pm \sqrt{4 - 4 x^{2} - 32 x - 32}}{2 \cdot 1}$

Step 5.1.5

Subtract $32$ from $4$ .

$y = \frac{- 2 \pm \sqrt{- 4 x^{2} - 32 x - 28}}{2 \cdot 1}$

Step 5.1.6

Rewrite $- 4 x^{2} - 32 x - 28$ in a factored form.

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Step 5.1.6.1

Factor $4$ out of $- 4 x^{2} - 32 x - 28$ .

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Step 5.1.6.1.1

Factor $4$ out of $- 4 x^{2}$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) - 32 x - 28}}{2 \cdot 1}$

Step 5.1.6.1.2

Factor $4$ out of $- 32 x$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) + 4 (- 8 x) - 28}}{2 \cdot 1}$

Step 5.1.6.1.3

Factor $4$ out of $- 28$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2}) + 4 (- 8 x) + 4 (- 7)}}{2 \cdot 1}$

Step 5.1.6.1.4

Factor $4$ out of $4 (- x^{2}) + 4 (- 8 x)$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x) + 4 (- 7)}}{2 \cdot 1}$

Step 5.1.6.1.5

Factor $4$ out of $4 (- x^{2} - 8 x) + 4 (- 7)$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x - 7)}}{2 \cdot 1}$

Step 5.1.6.2

Factor by grouping.

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Step 5.1.6.2.1

For a polynomial of the form $a x^{2} + b x + c$ , rewrite the middle term as a sum of two terms whose product is $a \cdot c = - 1 \cdot - 7 = 7$ and whose sum is $b = - 8$ .

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Step 5.1.6.2.1.1

Factor $- 8$ out of $- 8 x$ .

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 8 x - 7)}}{2 \cdot 1}$

Step 5.1.6.2.1.2

Rewrite $- 8$ as $- 1$ plus $- 7$

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} + (- 1 - 7) x - 7)}}{2 \cdot 1}$

Step 5.1.6.2.1.3

Apply the distributive property.

$y = \frac{- 2 \pm \sqrt{4 (- x^{2} - 1 x - 7 x - 7)}}{2 \cdot 1}$

Step 5.1.6.2.2

Factor out the greatest common factor from each group.

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Step 5.1.6.2.2.1

Group the first two terms and the last two terms.

$y = \frac{- 2 \pm \sqrt{4 ((- x^{2} - 1 x) - 7 x - 7)}}{2 \cdot 1}$

Step 5.1.6.2.2.2

Factor out the greatest common factor (GCF) from each group.

$y = \frac{- 2 \pm \sqrt{4 (x (- x - 1) + 7 (- x - 1))}}{2 \cdot 1}$

Step 5.1.6.2.3

Factor the polynomial by factoring out the greatest common factor, $- x - 1$ .

$y = \frac{- 2 \pm \sqrt{4 ((- x - 1) (x + 7))}}{2 \cdot 1}$

$y = \frac{- 2 \pm \sqrt{4 (- x - 1) (x + 7)}}{2 \cdot 1}$

Step 5.1.7

Rewrite $4 (- x - 1) (x + 7)$ as $2^{2} ((- x - 1) (x + 7))$ .

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Step 5.1.7.1

Rewrite $4$ as $2^{2}$ .

$y = \frac{- 2 \pm \sqrt{2^{2} (- x - 1) (x + 7)}}{2 \cdot 1}$

Step 5.1.7.2

Add parentheses.

$y = \frac{- 2 \pm \sqrt{2^{2} ((- x - 1) (x + 7))}}{2 \cdot 1}$

Step 5.1.8

Pull terms out from under the radical.

$y = \frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2 \cdot 1}$

Step 5.2

Multiply $2$ by $1$ .

$y = \frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2}$

Step 5.3

Simplify $\frac{- 2 \pm 2 \sqrt{(- x - 1) (x + 7)}}{2}$ .

$y = - 1 \pm \sqrt{(- x - 1) (x + 7)}$

Step 5.4

Change the $\pm$ to $-$ .

$y = - 1 - \sqrt{(- x - 1) (x + 7)}$

Step 6

The final answer is the combination of both solutions.

$y = - 1 + \sqrt{(- x - 1) (x + 7)}$

$y = - 1 - \sqrt{(- x - 1) (x + 7)}$

Step 7

Set the radicand in $\sqrt{(- x - 1) (x + 7)}$ greater than or equal to $0$ to find where the expression is defined.

$(- x - 1) (x + 7) \geq 0$

Step 8

Solve for $x$ .

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Step 8.1

If any individual factor on the left side of the equation is equal to $0$ , the entire expression will be equal to $0$ .

$- x - 1 = 0$

$x + 7 = 0$

Step 8.2

Set $- x - 1$ equal to $0$ and solve for $x$ .

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Step 8.2.1

Set $- x - 1$ equal to $0$ .

$- x - 1 = 0$

Step 8.2.2

Solve $- x - 1 = 0$ for $x$ .

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Step 8.2.2.1

Add $1$ to both sides of the equation.

$- x = 1$

Step 8.2.2.2

Divide each term in $- x = 1$ by $- 1$ and simplify.

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Step 8.2.2.2.1

Divide each term in $- x = 1$ by $- 1$ .

$\frac{- x}{- 1} = \frac{1}{- 1}$

Step 8.2.2.2.2

Simplify the left side.

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Step 8.2.2.2.2.1

Dividing two negative values results in a positive value.

$\frac{x}{1} = \frac{1}{- 1}$

Step 8.2.2.2.2.2

Divide $x$ by $1$ .

$x = \frac{1}{- 1}$

Step 8.2.2.2.3

Simplify the right side.

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Step 8.2.2.2.3.1

Divide $1$ by $- 1$ .

$x = - 1$

Step 8.3

Set $x + 7$ equal to $0$ and solve for $x$ .

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Step 8.3.1

Set $x + 7$ equal to $0$ .

$x + 7 = 0$

Step 8.3.2

Subtract $7$ from both sides of the equation.

$x = - 7$

Step 8.4

The final solution is all the values that make $(- x - 1) (x + 7) \geq 0$ true.

$x = - 1, - 7$

Step 8.5

Use each root to create test intervals.

$x < - 7$

$- 7 < x < - 1$

$x > - 1$

Step 8.6

Choose a test value from each interval and plug this value into the original inequality to determine which intervals satisfy the inequality.

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Step 8.6.1

Test a value on the interval $x < - 7$ to see if it makes the inequality true.

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Step 8.6.1.1

Choose a value on the interval $x < - 7$ and see if this value makes the original inequality true.

$x = - 10$

Step 8.6.1.2

Replace $x$ with $- 10$ in the original inequality.

$(- (- 10) - 1) ((- 10) + 7) \geq 0$

Step 8.6.1.3

The left side $- 27$ is less than the right side $0$ , which means that the given statement is false.

False

Step 8.6.2

Test a value on the interval $- 7 < x < - 1$ to see if it makes the inequality true.

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Step 8.6.2.1

Choose a value on the interval $- 7 < x < - 1$ and see if this value makes the original inequality true.

$x = - 4$

Step 8.6.2.2

Replace $x$ with $- 4$ in the original inequality.

$(- (- 4) - 1) ((- 4) + 7) \geq 0$

Step 8.6.2.3

The left side $9$ is greater than the right side $0$ , which means that the given statement is always true.

True

Step 8.6.3

Test a value on the interval $x > - 1$ to see if it makes the inequality true.

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Step 8.6.3.1

Choose a value on the interval $x > - 1$ and see if this value makes the original inequality true.

$x = 0$

Step 8.6.3.2

Replace $x$ with $0$ in the original inequality.

$(- (0) - 1) ((0) + 7) \geq 0$

Step 8.6.3.3

The left side $- 7$ is less than the right side $0$ , which means that the given statement is false.

False

Step 8.6.4

Compare the intervals to determine which ones satisfy the original inequality.

$x < - 7$ False

$- 7 < x < - 1$ True

$x > - 1$ False

$x < - 7$ False

$- 7 < x < - 1$ True

$x > - 1$ False

Step 8.7

The solution consists of all of the true intervals.

$- 7 \leq x \leq - 1$

Step 9

The domain is all values of $x$ that make the expression defined.

Interval Notation:

$[- 7, - 1]$

Set-Builder Notation:

${x | - 7 \leq x \leq - 1}$

Step 10

The range is the set of all valid $y$ values. Use the graph to find the range.

Interval Notation:

$[- 4, 2]$

Set-Builder Notation:

${y | - 4 \leq y \leq 2}$

Step 11

Determine the domain and range.

Domain: $[- 7, - 1], {x | - 7 \leq x \leq - 1}$

Range: $[- 4, 2], {y | - 4 \leq y \leq 2}$

Step 12