Finite Math Examples

$[\begin{array}{c} 15 & 8 \\ 4 x & 0 \end{array}] - [\begin{array}{c} 2 & 5 \\ x & 3 y + 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 1

Subtract the corresponding elements.

$[\begin{array}{c} 15 - 2 & 8 - 5 \\ 4 x - x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2

Simplify each element.

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Step 2.1

Subtract $2$ from $15$ .

$[\begin{array}{c} 13 & 8 - 5 \\ 4 x - x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2.2

Subtract $5$ from $8$ .

$[\begin{array}{c} 13 & 3 \\ 4 x - x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2.3

Subtract $x$ from $4 x$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & 0 - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2.4

Subtract $3 y + 6$ from $0$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & - (3 y + 6) \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2.5

Apply the distributive property.

$[\begin{array}{c} 13 & 3 \\ 3 x & - (3 y) - 1 \cdot 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2.6

Multiply $3$ by $- 1$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & - 3 y - 1 \cdot 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 2.7

Multiply $- 1$ by $6$ .

$[\begin{array}{c} 13 & 3 \\ 3 x & - 3 y - 6 \end{array}] = [\begin{array}{c} 13 & 3 \\ 12 & 4 y + 8 \end{array}]$

Step 3

Write as a linear system of equations.

$13 = 13$

$3 = 3$

$3 x = 12$

$- 3 y - 6 = 4 y + 8$

Step 4

Since $3 = 3$ is always true, the matrix equation has infinite solutions.

Infinite solutions satisfying the system.