Finite Math Examples

$[\begin{array}{c} - \frac{1}{6} & \frac{5}{14} & - \frac{2}{3} \\ - \frac{1}{2} & \frac{9}{14} & - 1 \\ \frac{1}{2} & - \frac{1}{2} & 1 \end{array}] [\begin{array}{c} x \\ y \\ z \end{array}] = [\begin{array}{c} - 4 \\ 0 \\ 1 \end{array}]$

Step 1

Multiply $[\begin{array}{c} - \frac{1}{6} & \frac{5}{14} & - \frac{2}{3} \\ - \frac{1}{2} & \frac{9}{14} & - 1 \\ \frac{1}{2} & - \frac{1}{2} & 1 \end{array}] [\begin{array}{c} x \\ y \\ z \end{array}]$ .

Tap for more steps...

Step 1.1

Two matrices can be multiplied if and only if the number of columns in the first matrix is equal to the number of rows in the second matrix. In this case, the first matrix is $3 \times 3$ and the second matrix is $3 \times 1$ .

Step 1.2

Multiply each row in the first matrix by each column in the second matrix.

$[\begin{array}{c} - \frac{1}{6} x + \frac{5}{14} y - \frac{2}{3} z \\ - \frac{1}{2} x + \frac{9}{14} y - z \\ \frac{1}{2} x - \frac{1}{2} y + 1 z \end{array}] = [\begin{array}{c} - 4 \\ 0 \\ 1 \end{array}]$

Step 1.3

Simplify each element of the matrix by multiplying out all the expressions.

Tap for more steps...

Step 1.3.1

Combine $\frac{1}{2}$ and $x$ .

$[\begin{array}{c} - \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} \\ - \frac{x}{2} + \frac{9 y}{14} - z \\ \frac{x}{2} - \frac{1}{2} y + 1 z \end{array}] = [\begin{array}{c} - 4 \\ 0 \\ 1 \end{array}]$

Step 1.3.2

Combine $y$ and $\frac{1}{2}$ .

$[\begin{array}{c} - \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} \\ - \frac{x}{2} + \frac{9 y}{14} - z \\ \frac{x}{2} - \frac{y}{2} + 1 z \end{array}] = [\begin{array}{c} - 4 \\ 0 \\ 1 \end{array}]$

Step 1.3.3

Multiply $z$ by $1$ .

$[\begin{array}{c} - \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} \\ - \frac{x}{2} + \frac{9 y}{14} - z \\ \frac{x}{2} - \frac{y}{2} + z \end{array}] = [\begin{array}{c} - 4 \\ 0 \\ 1 \end{array}]$

Step 2

Write as a linear system of equations.

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} = - 4$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{x}{2} - \frac{y}{2} + z = 1$

Step 3

Solve the system of equations.

Tap for more steps...

Step 3.1

Move all terms not containing $z$ to the right side of the equation.

Tap for more steps...

Step 3.1.1

Subtract $\frac{x}{2}$ from both sides of the equation.

$- \frac{y}{2} + z = 1 - \frac{x}{2}$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} = - 4$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.1.2

Add $\frac{y}{2}$ to both sides of the equation.

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} = - 4$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} = - 4$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2

Replace all occurrences of $z$ with $1 - \frac{x}{2} + \frac{y}{2}$ in each equation.

Tap for more steps...

Step 3.2.1

Replace all occurrences of $z$ in $- \frac{x}{6} + \frac{5 y}{14} - \frac{2 z}{3} = - 4$ with $1 - \frac{x}{2} + \frac{y}{2}$ .

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 (1 - \frac{x}{2} + \frac{y}{2})}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2

Simplify the left side.

Tap for more steps...

Step 3.2.2.1

Simplify $- \frac{x}{6} + \frac{5 y}{14} - \frac{2 (1 - \frac{x}{2} + \frac{y}{2})}{3}$ .

Tap for more steps...

Step 3.2.2.1.1

Simplify each term.

Tap for more steps...

Step 3.2.2.1.1.1

Simplify the numerator.

Tap for more steps...

Step 3.2.2.1.1.1.1

Write $1$ as a fraction with a common denominator.

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 (\frac{2}{2} - \frac{x}{2} + \frac{y}{2})}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.1.1.2

Combine the numerators over the common denominator.

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 (\frac{2 - x}{2} + \frac{y}{2})}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.1.1.3

Combine the numerators over the common denominator.

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 (\frac{2 - x + y}{2})}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 (\frac{2 - x + y}{2})}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.1.2

Combine $2$ and $\frac{2 - x + y}{2}$ .

$- \frac{x}{6} + \frac{5 y}{14} - \frac{\frac{2 (2 - x + y)}{2}}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.1.3

Reduce the expression by cancelling the common factors.

Tap for more steps...

Step 3.2.2.1.1.3.1

Reduce the expression $\frac{2 (2 - x + y)}{2}$ by cancelling the common factors.

Tap for more steps...

Step 3.2.2.1.1.3.1.1

Cancel the common factor.

$- \frac{x}{6} + \frac{5 y}{14} - \frac{\frac{2 (2 - x + y)}{2}}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.1.3.1.2

Rewrite the expression.

$- \frac{x}{6} + \frac{5 y}{14} - \frac{\frac{2 - x + y}{1}}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{\frac{2 - x + y}{1}}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.1.3.2

Divide $2 - x + y$ by $1$ .

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 - x + y}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 - x + y}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$- \frac{x}{6} + \frac{5 y}{14} - \frac{2 - x + y}{3} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.2

To write $- \frac{2 - x + y}{3}$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$\frac{5 y}{14} - \frac{x}{6} - \frac{2 - x + y}{3} \cdot \frac{2}{2} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.3

Write each expression with a common denominator of $6$ , by multiplying each by an appropriate factor of $1$ .

Tap for more steps...

Step 3.2.2.1.3.1

Multiply $\frac{2 - x + y}{3}$ by $\frac{2}{2}$ .

$\frac{5 y}{14} - \frac{x}{6} - \frac{(2 - x + y) \cdot 2}{3 \cdot 2} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.3.2

Multiply $3$ by $2$ .

$\frac{5 y}{14} - \frac{x}{6} - \frac{(2 - x + y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{5 y}{14} - \frac{x}{6} - \frac{(2 - x + y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.4

Combine the numerators over the common denominator.

$\frac{5 y}{14} + \frac{- x - (2 - x + y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5

Simplify the numerator.

Tap for more steps...

Step 3.2.2.1.5.1

Apply the distributive property.

$\frac{5 y}{14} + \frac{- x + (- 1 \cdot 2 + x - y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.2

Simplify.

Tap for more steps...

Step 3.2.2.1.5.2.1

Multiply $- 1$ by $2$ .

$\frac{5 y}{14} + \frac{- x + (- 2 + x - y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.2.2

Multiply $- - x$ .

Tap for more steps...

Step 3.2.2.1.5.2.2.1

Multiply $- 1$ by $- 1$ .

$\frac{5 y}{14} + \frac{- x + (- 2 + 1 x - y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.2.2.2

Multiply $x$ by $1$ .

$\frac{5 y}{14} + \frac{- x + (- 2 + x - y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{5 y}{14} + \frac{- x + (- 2 + x - y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{5 y}{14} + \frac{- x + (- 2 + x - y) \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.3

Apply the distributive property.

$\frac{5 y}{14} + \frac{- x - 2 \cdot 2 + x \cdot 2 - y \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.4

Simplify.

Tap for more steps...

Step 3.2.2.1.5.4.1

Multiply $- 2$ by $2$ .

$\frac{5 y}{14} + \frac{- x - 4 + x \cdot 2 - y \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.4.2

Move $2$ to the left of $x$ .

$\frac{5 y}{14} + \frac{- x - 4 + 2 \cdot x - y \cdot 2}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.4.3

Multiply $2$ by $- 1$ .

$\frac{5 y}{14} + \frac{- x - 4 + 2 \cdot x - 2 y}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{5 y}{14} + \frac{- x - 4 + 2 \cdot x - 2 y}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.5.5

Add $- x$ and $2 x$ .

$\frac{5 y}{14} + \frac{x - 4 - 2 y}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{5 y}{14} + \frac{x - 4 - 2 y}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.6

To write $\frac{5 y}{14}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{5 y}{14} \cdot \frac{3}{3} + \frac{x - 4 - 2 y}{6} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.7

To write $\frac{x - 4 - 2 y}{6}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$\frac{5 y}{14} \cdot \frac{3}{3} + \frac{x - 4 - 2 y}{6} \cdot \frac{7}{7} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.8

Write each expression with a common denominator of $42$ , by multiplying each by an appropriate factor of $1$ .

Tap for more steps...

Step 3.2.2.1.8.1

Multiply $\frac{5 y}{14}$ by $\frac{3}{3}$ .

$\frac{5 y \cdot 3}{14 \cdot 3} + \frac{x - 4 - 2 y}{6} \cdot \frac{7}{7} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.8.2

Multiply $14$ by $3$ .

$\frac{5 y \cdot 3}{42} + \frac{x - 4 - 2 y}{6} \cdot \frac{7}{7} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.8.3

Multiply $\frac{x - 4 - 2 y}{6}$ by $\frac{7}{7}$ .

$\frac{5 y \cdot 3}{42} + \frac{(x - 4 - 2 y) \cdot 7}{6 \cdot 7} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.8.4

Multiply $6$ by $7$ .

$\frac{5 y \cdot 3}{42} + \frac{(x - 4 - 2 y) \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{5 y \cdot 3}{42} + \frac{(x - 4 - 2 y) \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.9

Combine the numerators over the common denominator.

$\frac{5 y \cdot 3 + (x - 4 - 2 y) \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.10

Simplify the numerator.

Tap for more steps...

Step 3.2.2.1.10.1

Multiply $3$ by $5$ .

$\frac{15 y + (x - 4 - 2 y) \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.10.2

Apply the distributive property.

$\frac{15 y + x \cdot 7 - 4 \cdot 7 - 2 y \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.10.3

Simplify.

Tap for more steps...

Step 3.2.2.1.10.3.1

Move $7$ to the left of $x$ .

$\frac{15 y + 7 \cdot x - 4 \cdot 7 - 2 y \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.10.3.2

Multiply $- 4$ by $7$ .

$\frac{15 y + 7 \cdot x - 28 - 2 y \cdot 7}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.10.3.3

Multiply $7$ by $- 2$ .

$\frac{15 y + 7 \cdot x - 28 - 14 y}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{15 y + 7 \cdot x - 28 - 14 y}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.2.1.10.4

Subtract $14 y$ from $15 y$ .

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - z = 0$

Step 3.2.3

Replace all occurrences of $z$ in $- \frac{x}{2} + \frac{9 y}{14} - z = 0$ with $1 - \frac{x}{2} + \frac{y}{2}$ .

$- \frac{x}{2} + \frac{9 y}{14} - (1 - \frac{x}{2} + \frac{y}{2}) = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4

Simplify the left side.

Tap for more steps...

Step 3.2.4.1

Simplify $- \frac{x}{2} + \frac{9 y}{14} - (1 - \frac{x}{2} + \frac{y}{2})$ .

Tap for more steps...

Step 3.2.4.1.1

Simplify each term.

Tap for more steps...

Step 3.2.4.1.1.1

Apply the distributive property.

$- \frac{x}{2} + \frac{9 y}{14} - 1 \cdot 1 + \frac{x}{2} - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.1.2

Simplify.

Tap for more steps...

Step 3.2.4.1.1.2.1

Multiply $- 1$ by $1$ .

$- \frac{x}{2} + \frac{9 y}{14} - 1 + \frac{x}{2} - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.1.2.2

Multiply $- - \frac{x}{2}$ .

Tap for more steps...

Step 3.2.4.1.1.2.2.1

Multiply $- 1$ by $- 1$ .

$- \frac{x}{2} + \frac{9 y}{14} - 1 + 1 (\frac{x}{2}) - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.1.2.2.2

Multiply $\frac{x}{2}$ by $1$ .

$- \frac{x}{2} + \frac{9 y}{14} - 1 + \frac{x}{2} - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - 1 + \frac{x}{2} - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - 1 + \frac{x}{2} - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$- \frac{x}{2} + \frac{9 y}{14} - 1 + \frac{x}{2} - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.2

Combine the opposite terms in $- \frac{x}{2} + \frac{9 y}{14} - 1 + \frac{x}{2} - \frac{y}{2}$ .

Tap for more steps...

Step 3.2.4.1.2.1

Add $- \frac{x}{2}$ and $\frac{x}{2}$ .

$\frac{9 y}{14} - 1 + 0 - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.2.2

Add $\frac{9 y}{14} - 1$ and $0$ .

$\frac{9 y}{14} - 1 - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{9 y}{14} - 1 - \frac{y}{2} = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.3

To write $- \frac{y}{2}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$\frac{9 y}{14} - \frac{y}{2} \cdot \frac{7}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.4

Write each expression with a common denominator of $14$ , by multiplying each by an appropriate factor of $1$ .

Tap for more steps...

Step 3.2.4.1.4.1

Multiply $\frac{y}{2}$ by $\frac{7}{7}$ .

$\frac{9 y}{14} - \frac{y \cdot 7}{2 \cdot 7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.4.2

Multiply $2$ by $7$ .

$\frac{9 y}{14} - \frac{y \cdot 7}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{9 y}{14} - \frac{y \cdot 7}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.5

Combine the numerators over the common denominator.

$\frac{9 y - y \cdot 7}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6

Simplify each term.

Tap for more steps...

Step 3.2.4.1.6.1

Simplify the numerator.

Tap for more steps...

Step 3.2.4.1.6.1.1

Factor $y$ out of $9 y - y \cdot 7$ .

Tap for more steps...

Step 3.2.4.1.6.1.1.1

Factor $y$ out of $9 y$ .

$\frac{y \cdot 9 - y \cdot 7}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.1.1.2

Factor $y$ out of $- y \cdot 7$ .

$\frac{y \cdot 9 + y (- 1 \cdot 7)}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.1.1.3

Factor $y$ out of $y \cdot 9 + y (- 1 \cdot 7)$ .

$\frac{y (9 - 1 \cdot 7)}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y (9 - 1 \cdot 7)}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.1.2

Multiply $- 1$ by $7$ .

$\frac{y (9 - 7)}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.1.3

Subtract $7$ from $9$ .

$\frac{y \cdot 2}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y \cdot 2}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.2

Cancel the common factor of $2$ and $14$ .

Tap for more steps...

Step 3.2.4.1.6.2.1

Factor $2$ out of $y \cdot 2$ .

$\frac{2 \cdot y}{14} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.2.2

Cancel the common factors.

Tap for more steps...

Step 3.2.4.1.6.2.2.1

Factor $2$ out of $14$ .

$\frac{2 \cdot y}{2 \cdot 7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.2.2.2

Cancel the common factor.

$\frac{2 \cdot y}{2 \cdot 7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.2.4.1.6.2.2.3

Rewrite the expression.

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{y}{7} - 1 = 0$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.3

Solve for $y$ in $\frac{y}{7} - 1 = 0$ .

Tap for more steps...

Step 3.3.1

Add $1$ to both sides of the equation.

$\frac{y}{7} = 1$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.3.2

Multiply both sides of the equation by $7$ .

$7 (\frac{y}{7}) = 7 \cdot 1$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.3.3

Simplify both sides of the equation.

Tap for more steps...

Step 3.3.3.1

Simplify the left side.

Tap for more steps...

Step 3.3.3.1.1

Cancel the common factor of $7$ .

Tap for more steps...

Step 3.3.3.1.1.1

Cancel the common factor.

$7 (\frac{y}{7}) = 7 \cdot 1$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.3.3.1.1.2

Rewrite the expression.

$y = 7 \cdot 1$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$y = 7 \cdot 1$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$y = 7 \cdot 1$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.3.3.2

Simplify the right side.

Tap for more steps...

Step 3.3.3.2.1

Multiply $7$ by $1$ .

$y = 7$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$y = 7$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$y = 7$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$y = 7$

$\frac{y + 7 x - 28}{42} = - 4$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4

Replace all occurrences of $y$ with $7$ in each equation.

Tap for more steps...

Step 3.4.1

Replace all occurrences of $y$ in $\frac{y + 7 x - 28}{42} = - 4$ with $7$ .

$\frac{(7) + 7 x - 28}{42} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2

Simplify the left side.

Tap for more steps...

Step 3.4.2.1

Simplify $\frac{(7) + 7 x - 28}{42}$ .

Tap for more steps...

Step 3.4.2.1.1

Cancel the common factor of $(7) + 7 x - 28$ and $42$ .

Tap for more steps...

Step 3.4.2.1.1.1

Factor $7$ out of $7$ .

$\frac{7 \cdot 1 + 7 x - 28}{42} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.2

Factor $7$ out of $7 x$ .

$\frac{7 \cdot 1 + 7 (x) - 28}{42} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.3

Factor $7$ out of $7 \cdot 1 + 7 (x)$ .

$\frac{7 \cdot (1 + x) - 28}{42} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.4

Factor $7$ out of $- 28$ .

$\frac{7 \cdot (1 + x) + 7 (- 4)}{42} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.5

Factor $7$ out of $7 \cdot (1 + x) + 7 (- 4)$ .

$\frac{7 \cdot (1 + x - 4)}{42} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.6

Cancel the common factors.

Tap for more steps...

Step 3.4.2.1.1.6.1

Factor $7$ out of $42$ .

$\frac{7 \cdot (1 + x - 4)}{7 (6)} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.6.2

Cancel the common factor.

$\frac{7 \cdot (1 + x - 4)}{7 \cdot 6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.1.6.3

Rewrite the expression.

$\frac{1 + x - 4}{6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{1 + x - 4}{6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{1 + x - 4}{6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.2.1.2

Subtract $4$ from $1$ .

$\frac{x - 3}{6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

$z = 1 - \frac{x}{2} + \frac{y}{2}$

Step 3.4.3

Replace all occurrences of $y$ in $z = 1 - \frac{x}{2} + \frac{y}{2}$ with $7$ .

$z = 1 - \frac{x}{2} + \frac{7}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

Step 3.4.4

Simplify the right side.

Tap for more steps...

Step 3.4.4.1

Simplify $1 - \frac{x}{2} + \frac{7}{2}$ .

Tap for more steps...

Step 3.4.4.1.1

Write $1$ as a fraction with a common denominator.

$z = - \frac{x}{2} + \frac{2}{2} + \frac{7}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

Step 3.4.4.1.2

Combine the numerators over the common denominator.

$z = - \frac{x}{2} + \frac{2 + 7}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

Step 3.4.4.1.3

Add $2$ and $7$ .

$z = - \frac{x}{2} + \frac{9}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

$z = - \frac{x}{2} + \frac{9}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

$z = - \frac{x}{2} + \frac{9}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

$z = - \frac{x}{2} + \frac{9}{2}$

$\frac{x - 3}{6} = - 4$

$y = 7$

Step 3.5

Solve for $x$ in $\frac{x - 3}{6} = - 4$ .

Tap for more steps...

Step 3.5.1

Multiply both sides of the equation by $6$ .

$6 (\frac{x - 3}{6}) = 6 \cdot - 4$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

Step 3.5.2

Simplify both sides of the equation.

Tap for more steps...

Step 3.5.2.1

Simplify the left side.

Tap for more steps...

Step 3.5.2.1.1

Cancel the common factor of $6$ .

Tap for more steps...

Step 3.5.2.1.1.1

Cancel the common factor.

$6 (\frac{x - 3}{6}) = 6 \cdot - 4$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

Step 3.5.2.1.1.2

Rewrite the expression.

$x - 3 = 6 \cdot - 4$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

$x - 3 = 6 \cdot - 4$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

$x - 3 = 6 \cdot - 4$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

Step 3.5.2.2

Simplify the right side.

Tap for more steps...

Step 3.5.2.2.1

Multiply $6$ by $- 4$ .

$x - 3 = - 24$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

$x - 3 = - 24$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

$x - 3 = - 24$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

Step 3.5.3

Move all terms not containing $x$ to the right side of the equation.

Tap for more steps...

Step 3.5.3.1

Add $3$ to both sides of the equation.

$x = - 24 + 3$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

Step 3.5.3.2

Add $- 24$ and $3$ .

$x = - 21$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

$x = - 21$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

$x = - 21$

$z = - \frac{x}{2} + \frac{9}{2}$

$y = 7$

Step 3.6

Replace all occurrences of $x$ with $- 21$ in each equation.

Tap for more steps...

Step 3.6.1

Replace all occurrences of $x$ in $z = - \frac{x}{2} + \frac{9}{2}$ with $- 21$ .

$z = - \frac{- 21}{2} + \frac{9}{2}$

$x = - 21$

$y = 7$

Step 3.6.2

Simplify the right side.

Tap for more steps...

Step 3.6.2.1

Simplify $- \frac{- 21}{2} + \frac{9}{2}$ .

Tap for more steps...

Step 3.6.2.1.1

Combine the numerators over the common denominator.

$z = \frac{21 + 9}{2}$

$x = - 21$

$y = 7$

Step 3.6.2.1.2

Simplify the expression.

Tap for more steps...

Step 3.6.2.1.2.1

Add $21$ and $9$ .

$z = \frac{30}{2}$

$x = - 21$

$y = 7$

Step 3.6.2.1.2.2

Divide $30$ by $2$ .

$z = 15$

$x = - 21$

$y = 7$

$z = 15$

$x = - 21$

$y = 7$

$z = 15$

$x = - 21$

$y = 7$

$z = 15$

$x = - 21$

$y = 7$

$z = 15$

$x = - 21$

$y = 7$

Step 3.7

List all of the solutions.

$z = 15, x = - 21, y = 7$