Finite Math Examples

$[\begin{array}{c} 3 a - 2 c & 3 b - 2 d \\ 2 a - c & 2 b - d \end{array}] = [\begin{array}{c} - 2 & 2 \\ - 1 & 2 \end{array}]$

Step 1

Write as a linear system of equations.

$3 a - 2 c = - 2$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

Step 2

Solve the system of equations.

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Step 2.1

Solve for $a$ in $3 a - 2 c = - 2$ .

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Step 2.1.1

Add $2 c$ to both sides of the equation.

$3 a = - 2 + 2 c$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

Step 2.1.2

Divide each term in $3 a = - 2 + 2 c$ by $3$ and simplify.

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Step 2.1.2.1

Divide each term in $3 a = - 2 + 2 c$ by $3$ .

$\frac{3 a}{3} = \frac{- 2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

Step 2.1.2.2

Simplify the left side.

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Step 2.1.2.2.1

Cancel the common factor of $3$ .

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Step 2.1.2.2.1.1

Cancel the common factor.

$\frac{3 a}{3} = \frac{- 2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

Step 2.1.2.2.1.2

Divide $a$ by $1$ .

$a = \frac{- 2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

$a = \frac{- 2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

$a = \frac{- 2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

Step 2.1.2.3

Simplify the right side.

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Step 2.1.2.3.1

Move the negative in front of the fraction.

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 a - c = - 1$

$2 b - d = 2$

Step 2.2

Replace all occurrences of $a$ with $- \frac{2}{3} + \frac{2 c}{3}$ in each equation.

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Step 2.2.1

Replace all occurrences of $a$ in $2 a - c = - 1$ with $- \frac{2}{3} + \frac{2 c}{3}$ .

$2 (- \frac{2}{3} + \frac{2 c}{3}) - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2

Simplify the left side.

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Step 2.2.2.1

Simplify $2 (- \frac{2}{3} + \frac{2 c}{3}) - c$ .

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Step 2.2.2.1.1

Simplify each term.

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Step 2.2.2.1.1.1

Apply the distributive property.

$2 (- \frac{2}{3}) + 2 (\frac{2 c}{3}) - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.1.2

Multiply $2 (- \frac{2}{3})$ .

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Step 2.2.2.1.1.2.1

Multiply $- 1$ by $2$ .

$- 2 (\frac{2}{3}) + 2 (\frac{2 c}{3}) - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.1.2.2

Combine $- 2$ and $\frac{2}{3}$ .

$\frac{- 2 \cdot 2}{3} + 2 (\frac{2 c}{3}) - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.1.2.3

Multiply $- 2$ by $2$ .

$\frac{- 4}{3} + 2 (\frac{2 c}{3}) - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$\frac{- 4}{3} + 2 (\frac{2 c}{3}) - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.1.3

Multiply $2 \frac{2 c}{3}$ .

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Step 2.2.2.1.1.3.1

Combine $2$ and $\frac{2 c}{3}$ .

$\frac{- 4}{3} + \frac{2 (2 c)}{3} - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.1.3.2

Multiply $2$ by $2$ .

$\frac{- 4}{3} + \frac{4 c}{3} - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$\frac{- 4}{3} + \frac{4 c}{3} - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.1.4

Move the negative in front of the fraction.

$- \frac{4}{3} + \frac{4 c}{3} - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$- \frac{4}{3} + \frac{4 c}{3} - c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.2

To write $- c$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{4}{3} + \frac{4 c}{3} - c \cdot \frac{3}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.3

Combine $- c$ and $\frac{3}{3}$ .

$- \frac{4}{3} + \frac{4 c}{3} + \frac{- c \cdot 3}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.4

Combine the numerators over the common denominator.

$- \frac{4}{3} + \frac{4 c - c \cdot 3}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.5

Combine the numerators over the common denominator.

$\frac{- 4 + 4 c - c \cdot 3}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.6

Multiply $3$ by $- 1$ .

$\frac{- 4 + 4 c - 3 c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.7

Subtract $3 c$ from $4 c$ .

$\frac{- 4 + c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.8

Rewrite $- 4$ as $- 1 (4)$ .

$\frac{- 1 \cdot 4 + c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.9

Factor $- 1$ out of $c$ .

$\frac{- 1 \cdot 4 - 1 (- c)}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.10

Factor $- 1$ out of $- 1 (4) - 1 (- c)$ .

$\frac{- 1 (4 - c)}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.2.2.1.11

Move the negative in front of the fraction.

$- \frac{4 - c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$- \frac{4 - c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$- \frac{4 - c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$- \frac{4 - c}{3} = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3

Solve for $c$ in $- \frac{4 - c}{3} = - 1$ .

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Step 2.3.1

Multiply both sides of the equation by $- 3$ .

$- 3 (- \frac{4 - c}{3}) = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2

Simplify both sides of the equation.

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Step 2.3.2.1

Simplify the left side.

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Step 2.3.2.1.1

Simplify $- 3 (- \frac{4 - c}{3})$ .

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Step 2.3.2.1.1.1

Cancel the common factor of $3$ .

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Step 2.3.2.1.1.1.1

Move the leading negative in $- \frac{4 - c}{3}$ into the numerator.

$- 3 \frac{- (4 - c)}{3} = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2.1.1.1.2

Factor $3$ out of $- 3$ .

$3 (- 1) (\frac{- (4 - c)}{3}) = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2.1.1.1.3

Cancel the common factor.

$3 \cdot (- 1 \frac{- (4 - c)}{3}) = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2.1.1.1.4

Rewrite the expression.

$4 - c = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$4 - c = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2.1.1.2

Multiply.

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Step 2.3.2.1.1.2.1

Multiply $- 1$ by $- 1$ .

$1 (4 - c) = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2.1.1.2.2

Multiply $4 - c$ by $1$ .

$4 - c = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$4 - c = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$4 - c = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$4 - c = - 3 \cdot - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.2.2

Simplify the right side.

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Step 2.3.2.2.1

Multiply $- 3$ by $- 1$ .

$4 - c = 3$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$4 - c = 3$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$4 - c = 3$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.3

Move all terms not containing $c$ to the right side of the equation.

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Step 2.3.3.1

Subtract $4$ from both sides of the equation.

$- c = 3 - 4$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.3.2

Subtract $4$ from $3$ .

$- c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$- c = - 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.4

Divide each term in $- c = - 1$ by $- 1$ and simplify.

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Step 2.3.4.1

Divide each term in $- c = - 1$ by $- 1$ .

$\frac{- c}{- 1} = \frac{- 1}{- 1}$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.4.2

Simplify the left side.

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Step 2.3.4.2.1

Dividing two negative values results in a positive value.

$\frac{c}{1} = \frac{- 1}{- 1}$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.4.2.2

Divide $c$ by $1$ .

$c = \frac{- 1}{- 1}$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$c = \frac{- 1}{- 1}$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.3.4.3

Simplify the right side.

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Step 2.3.4.3.1

Divide $- 1$ by $- 1$ .

$c = 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$c = 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$c = 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

$c = 1$

$a = - \frac{2}{3} + \frac{2 c}{3}$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.4

Replace all occurrences of $c$ with $1$ in each equation.

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Step 2.4.1

Replace all occurrences of $c$ in $a = - \frac{2}{3} + \frac{2 c}{3}$ with $1$ .

$a = - \frac{2}{3} + \frac{2 (1)}{3}$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.4.2

Simplify the right side.

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Step 2.4.2.1

Simplify $- \frac{2}{3} + \frac{2 (1)}{3}$ .

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Step 2.4.2.1.1

Combine the numerators over the common denominator.

$a = \frac{- 2 + 2 (1)}{3}$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.4.2.1.2

Simplify the expression.

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Step 2.4.2.1.2.1

Multiply $2$ by $1$ .

$a = \frac{- 2 + 2}{3}$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.4.2.1.2.2

Add $- 2$ and $2$ .

$a = \frac{0}{3}$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.4.2.1.2.3

Divide $0$ by $3$ .

$a = 0$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

$a = 0$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

$a = 0$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

$a = 0$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

$a = 0$

$c = 1$

$3 b - 2 d = 2$

$2 b - d = 2$

Step 2.5

Solve for $b$ in $3 b - 2 d = 2$ .

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Step 2.5.1

Add $2 d$ to both sides of the equation.

$3 b = 2 + 2 d$

$a = 0$

$c = 1$

$2 b - d = 2$

Step 2.5.2

Divide each term in $3 b = 2 + 2 d$ by $3$ and simplify.

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Step 2.5.2.1

Divide each term in $3 b = 2 + 2 d$ by $3$ .

$\frac{3 b}{3} = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

Step 2.5.2.2

Simplify the left side.

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Step 2.5.2.2.1

Cancel the common factor of $3$ .

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Step 2.5.2.2.1.1

Cancel the common factor.

$\frac{3 b}{3} = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

Step 2.5.2.2.1.2

Divide $b$ by $1$ .

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$2 b - d = 2$

Step 2.6

Replace all occurrences of $b$ with $\frac{2}{3} + \frac{2 d}{3}$ in each equation.

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Step 2.6.1

Replace all occurrences of $b$ in $2 b - d = 2$ with $\frac{2}{3} + \frac{2 d}{3}$ .

$2 (\frac{2}{3} + \frac{2 d}{3}) - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2

Simplify the left side.

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Step 2.6.2.1

Simplify $2 (\frac{2}{3} + \frac{2 d}{3}) - d$ .

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Step 2.6.2.1.1

Simplify each term.

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Step 2.6.2.1.1.1

Apply the distributive property.

$2 (\frac{2}{3}) + 2 (\frac{2 d}{3}) - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.1.2

Multiply $2 (\frac{2}{3})$ .

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Step 2.6.2.1.1.2.1

Combine $2$ and $\frac{2}{3}$ .

$\frac{2 \cdot 2}{3} + 2 (\frac{2 d}{3}) - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.1.2.2

Multiply $2$ by $2$ .

$\frac{4}{3} + 2 (\frac{2 d}{3}) - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$\frac{4}{3} + 2 (\frac{2 d}{3}) - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.1.3

Multiply $2 \frac{2 d}{3}$ .

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Step 2.6.2.1.1.3.1

Combine $2$ and $\frac{2 d}{3}$ .

$\frac{4}{3} + \frac{2 (2 d)}{3} - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.1.3.2

Multiply $2$ by $2$ .

$\frac{4}{3} + \frac{4 d}{3} - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$\frac{4}{3} + \frac{4 d}{3} - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$\frac{4}{3} + \frac{4 d}{3} - d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.2

To write $- d$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$\frac{4}{3} + \frac{4 d}{3} - d \cdot \frac{3}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.3

Combine $- d$ and $\frac{3}{3}$ .

$\frac{4}{3} + \frac{4 d}{3} + \frac{- d \cdot 3}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.4

Combine the numerators over the common denominator.

$\frac{4}{3} + \frac{4 d - d \cdot 3}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.5

Combine the numerators over the common denominator.

$\frac{4 + 4 d - d \cdot 3}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.6

Multiply $3$ by $- 1$ .

$\frac{4 + 4 d - 3 d}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.6.2.1.7

Subtract $3 d$ from $4 d$ .

$\frac{4 + d}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$\frac{4 + d}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$\frac{4 + d}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$\frac{4 + d}{3} = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.7

Solve for $d$ in $\frac{4 + d}{3} = 2$ .

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Step 2.7.1

Multiply both sides of the equation by $3$ .

$3 (\frac{4 + d}{3}) = 3 \cdot 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.7.2

Simplify both sides of the equation.

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Step 2.7.2.1

Simplify the left side.

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Step 2.7.2.1.1

Cancel the common factor of $3$ .

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Step 2.7.2.1.1.1

Cancel the common factor.

$3 (\frac{4 + d}{3}) = 3 \cdot 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.7.2.1.1.2

Rewrite the expression.

$4 + d = 3 \cdot 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$4 + d = 3 \cdot 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$4 + d = 3 \cdot 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.7.2.2

Simplify the right side.

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Step 2.7.2.2.1

Multiply $3$ by $2$ .

$4 + d = 6$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$4 + d = 6$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$4 + d = 6$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.7.3

Move all terms not containing $d$ to the right side of the equation.

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Step 2.7.3.1

Subtract $4$ from both sides of the equation.

$d = 6 - 4$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.7.3.2

Subtract $4$ from $6$ .

$d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

$d = 2$

$b = \frac{2}{3} + \frac{2 d}{3}$

$a = 0$

$c = 1$

Step 2.8

Replace all occurrences of $d$ with $2$ in each equation.

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Step 2.8.1

Replace all occurrences of $d$ in $b = \frac{2}{3} + \frac{2 d}{3}$ with $2$ .

$b = \frac{2}{3} + \frac{2 (2)}{3}$

$d = 2$

$a = 0$

$c = 1$

Step 2.8.2

Simplify the right side.

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Step 2.8.2.1

Simplify $\frac{2}{3} + \frac{2 (2)}{3}$ .

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Step 2.8.2.1.1

Combine the numerators over the common denominator.

$b = \frac{2 + 2 (2)}{3}$

$d = 2$

$a = 0$

$c = 1$

Step 2.8.2.1.2

Simplify the expression.

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Step 2.8.2.1.2.1

Multiply $2$ by $2$ .

$b = \frac{2 + 4}{3}$

$d = 2$

$a = 0$

$c = 1$

Step 2.8.2.1.2.2

Add $2$ and $4$ .

$b = \frac{6}{3}$

$d = 2$

$a = 0$

$c = 1$

Step 2.8.2.1.2.3

Divide $6$ by $3$ .

$b = 2$

$d = 2$

$a = 0$

$c = 1$

$b = 2$

$d = 2$

$a = 0$

$c = 1$

$b = 2$

$d = 2$

$a = 0$

$c = 1$

$b = 2$

$d = 2$

$a = 0$

$c = 1$

$b = 2$

$d = 2$

$a = 0$

$c = 1$

Step 2.9

List all of the solutions.

$b = 2, d = 2, a = 0, c = 1$