Finite Math Examples

$P (B) = 0.2$ , $P (A) = 0.13$ , $P (A o r B) = 0.33$

Step 1

$B$ and $A$ are mutually exclusive events if they cannot occur at the same time. For example, tossing a coin once results in either head or tail, but not both. The probability of their joint occurrence is zero $P (B \cap A) = 0$ and it is not possible for $B$ and $A$ to be independent because $P (B | A) = P (A | B) = 0$ for mutually exclusive $B$ and $A$ .

$P (B \cup A) = P (B) + P (A)$ for mutually exclusive events

Step 2

Add $0.2$ and $0.13$ .

$P (B) + P (A) = 0.33$

Step 3

$P (B \cup A) = P (B) + P (A)$ , which means that $B$ and $A$ are mutually exclusive events.

B and A are mutually exclusive events