Finite Math Examples

Find the Slope for Each Equation y=x-4 , y=-x+7
y=x-4y=x4 , y=-x+7y=x+7
Step 1
Use the slope-intercept form to find the slope.
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Step 1.1
The slope-intercept form is y=mx+by=mx+b, where mm is the slope and bb is the y-intercept.
y=mx+by=mx+b
Step 1.2
Using the slope-intercept form, the slope is 11.
m1=1m1=1
m1=1m1=1
Step 2
Use the slope-intercept form to find the slope.
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Step 2.1
The slope-intercept form is y=mx+by=mx+b, where mm is the slope and bb is the y-intercept.
y=mx+by=mx+b
Step 2.2
Using the slope-intercept form, the slope is -11.
m2=-1m2=1
m2=-1m2=1
Step 3
Set up the system of equations to find any points of intersection.
y=x-4,y=-x+7y=x4,y=x+7
Step 4
Solve the system of equations to find the point of intersection.
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Step 4.1
Eliminate the equal sides of each equation and combine.
x-4=-x+7x4=x+7
Step 4.2
Solve x-4=-x+7x4=x+7 for xx.
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Step 4.2.1
Move all terms containing xx to the left side of the equation.
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Step 4.2.1.1
Add xx to both sides of the equation.
x-4+x=7x4+x=7
Step 4.2.1.2
Add xx and xx.
2x-4=72x4=7
2x-4=72x4=7
Step 4.2.2
Move all terms not containing xx to the right side of the equation.
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Step 4.2.2.1
Add 44 to both sides of the equation.
2x=7+42x=7+4
Step 4.2.2.2
Add 77 and 44.
2x=112x=11
2x=112x=11
Step 4.2.3
Divide each term in 2x=112x=11 by 22 and simplify.
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Step 4.2.3.1
Divide each term in 2x=112x=11 by 22.
2x2=1122x2=112
Step 4.2.3.2
Simplify the left side.
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Step 4.2.3.2.1
Cancel the common factor of 22.
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Step 4.2.3.2.1.1
Cancel the common factor.
2x2=112
Step 4.2.3.2.1.2
Divide x by 1.
x=112
x=112
x=112
x=112
x=112
Step 4.3
Evaluate y when x=112.
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Step 4.3.1
Substitute 112 for x.
y=-(112)+7
Step 4.3.2
Substitute 112 for x in y=-(112)+7 and solve for y.
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Step 4.3.2.1
Multiply -1 by 112.
y=-112+7
Step 4.3.2.2
Simplify -112+7.
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Step 4.3.2.2.1
To write 7 as a fraction with a common denominator, multiply by 22.
y=-112+722
Step 4.3.2.2.2
Combine 7 and 22.
y=-112+722
Step 4.3.2.2.3
Combine the numerators over the common denominator.
y=-11+722
Step 4.3.2.2.4
Simplify the numerator.
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Step 4.3.2.2.4.1
Multiply 7 by 2.
y=-11+142
Step 4.3.2.2.4.2
Add -11 and 14.
y=32
y=32
y=32
y=32
y=32
Step 4.4
The solution to the system is the complete set of ordered pairs that are valid solutions.
(112,32)
(112,32)
Step 5
Since the slopes are different, the lines will have exactly one intersection point.
m1=1
m2=-1
(112,32)
Step 6
 [x2  12  π  xdx ]