Finite Math Examples

$- 1 \cdot \frac{7}{80} + \frac{1}{15}$

Step 1

Rewrite $- 1 (\frac{7}{80})$ as $- (\frac{7}{80})$ .

$- \frac{7}{80} + \frac{1}{15}$

Step 2

To write $- \frac{7}{80}$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$- \frac{7}{80} \cdot \frac{3}{3} + \frac{1}{15}$

Step 3

To write $\frac{1}{15}$ as a fraction with a common denominator, multiply by $\frac{16}{16}$ .

$- \frac{7}{80} \cdot \frac{3}{3} + \frac{1}{15} \cdot \frac{16}{16}$

Step 4

Write each expression with a common denominator of $240$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.1

Multiply $\frac{7}{80}$ by $\frac{3}{3}$ .

$- \frac{7 \cdot 3}{80 \cdot 3} + \frac{1}{15} \cdot \frac{16}{16}$

Step 4.2

Multiply $80$ by $3$ .

$- \frac{7 \cdot 3}{240} + \frac{1}{15} \cdot \frac{16}{16}$

Step 4.3

Multiply $\frac{1}{15}$ by $\frac{16}{16}$ .

$- \frac{7 \cdot 3}{240} + \frac{16}{15 \cdot 16}$

Step 4.4

Multiply $15$ by $16$ .

$- \frac{7 \cdot 3}{240} + \frac{16}{240}$

Step 5

Combine the numerators over the common denominator.

$\frac{- 7 \cdot 3 + 16}{240}$

Step 6

Simplify the numerator.

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Step 6.1

Multiply $- 7$ by $3$ .

$\frac{- 21 + 16}{240}$

Step 6.2

Add $- 21$ and $16$ .

$\frac{- 5}{240}$

Step 7

Cancel the common factor of $- 5$ and $240$ .

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Step 7.1

Factor $5$ out of $- 5$ .

$\frac{5 (- 1)}{240}$

Step 7.2

Cancel the common factors.

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Step 7.2.1

Factor $5$ out of $240$ .

$\frac{5 \cdot - 1}{5 \cdot 48}$

Step 7.2.2

Cancel the common factor.

$\frac{5 \cdot - 1}{5 \cdot 48}$

Step 7.2.3

Rewrite the expression.

$\frac{- 1}{48}$

Step 8

Move the negative in front of the fraction.

$- \frac{1}{48}$

Step 9

The result can be shown in multiple forms.

Exact Form:

$- \frac{1}{48}$

Decimal Form:

$- 0.0208\overline{3}$