Finite Math Examples

$7791.3 \cdot \frac{{(\frac{0.25}{12} \cdot 1 + \frac{0.25}{12})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1

Simplify the numerator.

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Step 1.1

Simplify each term.

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Step 1.1.1

Cancel the common factor of $0.25$ .

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Step 1.1.1.1

Cancel the common factor.

$7791.3 \cdot \frac{{(\frac{0.25}{12} \cdot 1 + \frac{0.25}{12})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.1.1.2

Rewrite the expression.

$7791.3 \cdot \frac{{(\frac{1}{12} \cdot \frac{1}{4} + \frac{0.25}{12})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.1.2

Multiply $\frac{1}{12}$ by $\frac{1}{4}$ .

$7791.3 \cdot \frac{{(\frac{1}{12 \cdot 4} + \frac{0.25}{12})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.1.3

Multiply $12$ by $4$ .

$7791.3 \cdot \frac{{(\frac{1}{48} + \frac{0.25}{12})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.1.4

Divide $0.25$ by $12$ .

$7791.3 \cdot \frac{{(\frac{1}{48} + 0.0208\overline{3})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.2

To write $0.0208\overline{3}$ as a fraction with a common denominator, multiply by $\frac{48}{48}$ .

$7791.3 \cdot \frac{{(\frac{1}{48} + 0.0208\overline{3} \cdot \frac{48}{48})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.3

Combine $0.0208\overline{3}$ and $\frac{48}{48}$ .

$7791.3 \cdot \frac{{(\frac{1}{48} + \frac{0.0208\overline{3} \cdot 48}{48})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.4

Combine the numerators over the common denominator.

$7791.3 \cdot \frac{{(\frac{1 + 0.0208\overline{3} \cdot 48}{48})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.5

Simplify the numerator.

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Step 1.5.1

Multiply $0.0208\overline{3}$ by $48$ .

$7791.3 \cdot \frac{{(\frac{1 + 1}{48})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.5.2

Add $1$ and $1$ .

$7791.3 \cdot \frac{{(\frac{2}{48})}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.6

Divide $2$ by $48$ .

$7791.3 \cdot \frac{{0.041\overline{6}}^{12 \cdot 2}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.7

Multiply $12$ by $2$ .

$7791.3 \cdot \frac{{0.041\overline{6}}^{24}}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 1.8

Raise $0.041\overline{6}$ to the power of $24$ .

$7791.3 \cdot \frac{0}{{(1 + \frac{0.25}{12})}^{12 \cdot 2} - 1}$

Step 2

Simplify the denominator.

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Step 2.1

Divide $0.25$ by $12$ .

$7791.3 \cdot \frac{0}{{(1 + 0.0208\overline{3})}^{12 \cdot 2} - 1}$

Step 2.2

Add $1$ and $0.0208\overline{3}$ .

$7791.3 \cdot \frac{0}{{1.0208\overline{3}}^{12 \cdot 2} - 1}$

Step 2.3

Multiply $12$ by $2$ .

$7791.3 \cdot \frac{0}{{1.0208\overline{3}}^{24} - 1}$

Step 2.4

Raise $1.0208\overline{3}$ to the power of $24$ .

$7791.3 \cdot \frac{0}{1.64027333 - 1}$

Step 2.5

Subtract $1$ from $1.64027333$ .

$7791.3 \cdot \frac{0}{0.64027333}$

Step 3

Simplify the expression.

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Step 3.1

Divide $0$ by $0.64027333$ .

$7791.3 \cdot 0$

Step 3.2

Multiply $7791.3$ by $0$ .

$0$