Finite Math Examples

$(- 1, 3)$ , $6 x + 3 y = 1$

Step 1

Solve $6 x + 3 y = 1$ .

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Step 1.1

Subtract $6 x$ from both sides of the equation.

$3 y = 1 - 6 x$

Step 1.2

Divide each term in $3 y = 1 - 6 x$ by $3$ and simplify.

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Step 1.2.1

Divide each term in $3 y = 1 - 6 x$ by $3$ .

$\frac{3 y}{3} = \frac{1}{3} + \frac{- 6 x}{3}$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $3$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{1}{3} + \frac{- 6 x}{3}$

Step 1.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{1}{3} + \frac{- 6 x}{3}$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Cancel the common factor of $- 6$ and $3$ .

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Step 1.2.3.1.1

Factor $3$ out of $- 6 x$ .

$y = \frac{1}{3} + \frac{3 (- 2 x)}{3}$

Step 1.2.3.1.2

Cancel the common factors.

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Step 1.2.3.1.2.1

Factor $3$ out of $3$ .

$y = \frac{1}{3} + \frac{3 (- 2 x)}{3 (1)}$

Step 1.2.3.1.2.2

Cancel the common factor.

$y = \frac{1}{3} + \frac{3 (- 2 x)}{3 \cdot 1}$

Step 1.2.3.1.2.3

Rewrite the expression.

$y = \frac{1}{3} + \frac{- 2 x}{1}$

Step 1.2.3.1.2.4

Divide $- 2 x$ by $1$ .

$y = \frac{1}{3} - 2 x$

Step 2

Find the slope when $y = \frac{1}{3} - 2 x$ .

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Step 2.1

Rewrite in slope-intercept form.

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Step 2.1.1

The slope-intercept form is $y = m x + b$ , where $m$ is the slope and $b$ is the y-intercept.

$y = m x + b$

Step 2.1.2

Reorder $\frac{1}{3}$ and $- 2 x$ .

$y = - 2 x + \frac{1}{3}$

Step 2.2

Using the slope-intercept form, the slope is $- 2$ .

$m = - 2$

Step 3

The equation of a perpendicular line must have a slope that is the negative reciprocal of the original slope.

$m_{perpendicular} = - \frac{1}{- 2}$

Step 4

Simplify $- \frac{1}{- 2}$ to find the slope of the perpendicular line.

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Step 4.1

Move the negative in front of the fraction.

$m_{perpendicular} = \frac{1}{2}$

Step 4.2

Multiply $- - \frac{1}{2}$ .

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Step 4.2.1

Multiply $- 1$ by $- 1$ .

$m_{perpendicular} = 1 (\frac{1}{2})$

Step 4.2.2

Multiply $\frac{1}{2}$ by $1$ .

$m_{perpendicular} = \frac{1}{2}$

Step 5

Find the equation of the perpendicular line using the point-slope formula.

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Step 5.1

Use the slope $\frac{1}{2}$ and a given point $(- 1, 3)$ to substitute for $x_{1}$ and $y_{1}$ in the point-slope form $y - y_{1} = m (x - x_{1})$ , which is derived from the slope equation $m = \frac{y_{2} - y_{1}}{x_{2} - x_{1}}$ .

$y - (3) = \frac{1}{2} \cdot (x - (- 1))$

Step 5.2

Simplify the equation and keep it in point-slope form.

$y - 3 = \frac{1}{2} \cdot (x + 1)$

Step 6

Write in $y = m x + b$ form.

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Step 6.1

Solve for $y$ .

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Step 6.1.1

Simplify $\frac{1}{2} \cdot (x + 1)$ .

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Step 6.1.1.1

Rewrite.

$y - 3 = 0 + 0 + \frac{1}{2} \cdot (x + 1)$

Step 6.1.1.2

Simplify by adding zeros.

$y - 3 = \frac{1}{2} \cdot (x + 1)$

Step 6.1.1.3

Apply the distributive property.

$y - 3 = \frac{1}{2} x + \frac{1}{2} \cdot 1$

Step 6.1.1.4

Combine $\frac{1}{2}$ and $x$ .

$y - 3 = \frac{x}{2} + \frac{1}{2} \cdot 1$

Step 6.1.1.5

Multiply $\frac{1}{2}$ by $1$ .

$y - 3 = \frac{x}{2} + \frac{1}{2}$

Step 6.1.2

Move all terms not containing $y$ to the right side of the equation.

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Step 6.1.2.1

Add $3$ to both sides of the equation.

$y = \frac{x}{2} + \frac{1}{2} + 3$

Step 6.1.2.2

To write $3$ as a fraction with a common denominator, multiply by $\frac{2}{2}$ .

$y = \frac{x}{2} + \frac{1}{2} + 3 \cdot \frac{2}{2}$

Step 6.1.2.3

Combine $3$ and $\frac{2}{2}$ .

$y = \frac{x}{2} + \frac{1}{2} + \frac{3 \cdot 2}{2}$

Step 6.1.2.4

Combine the numerators over the common denominator.

$y = \frac{x}{2} + \frac{1 + 3 \cdot 2}{2}$

Step 6.1.2.5

Simplify the numerator.

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Step 6.1.2.5.1

Multiply $3$ by $2$ .

$y = \frac{x}{2} + \frac{1 + 6}{2}$

Step 6.1.2.5.2

Add $1$ and $6$ .

$y = \frac{x}{2} + \frac{7}{2}$

Step 6.2

Reorder terms.

$y = \frac{1}{2} x + \frac{7}{2}$

Step 7