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Write in Exponential Form log base 2 of x-6=3- log base 2 of x+1

$\log_{2} (x - 6) = 3 - \log_{2} (x + 1)$

Step 1

$\log_{2} (x - 6) = 3 - \log_{2} (x + 1)$

$[\begin{array}{c} x^{2} & \frac{1}{2} \\ \sqrt{π} & \int x d x \end{array}]$

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