Finite Math Examples

(- 2, 4)

$(- 2, 4)$ ,

y = \frac{1}{3} \cdot (x + 2) + 4

$y = \frac{1}{3} \cdot (x + 2) + 4$

Step 1

Insert the values of

x = - 2

$x = - 2$ and

y = 4

$y = 4$ into the equation to find if the ordered pair is a solution.

4 = \frac{1}{3} \cdot ((- 2) + 2) + 4

$4 = \frac{1}{3} \cdot ((- 2) + 2) + 4$

Step 2

Simplify

\frac{1}{3} \cdot ((- 2) + 2) + 4

$\frac{1}{3} \cdot ((- 2) + 2) + 4$ .

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Step 2.1

Simplify each term.

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Step 2.1.1

Add

- 2

$- 2$ and

2

$2$ .

4 = \frac{1}{3} \cdot 0 + 4

$4 = \frac{1}{3} \cdot 0 + 4$

Step 2.1.2

Multiply

\frac{1}{3}

$\frac{1}{3}$ by

0

$0$ .

4 = 0 + 4

$4 = 0 + 4$

4 = 0 + 4

$4 = 0 + 4$

Step 2.2

Add

0

$0$ and

4

$4$ .

4 = 4

$4 = 4$

4 = 4

$4 = 4$

Step 3

Since

4 = 4

$4 = 4$ , the equation will always be true.

Always true

Step 4

Since the equation is always true when the values are used, the ordered pair is a solution.

The ordered pair is a solution to the equation.