Finite Math Examples

$\log (16 + 2 b) = \log (b^{2} - 4 b)$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = 10$ , $x = 16 + 2 b$ , and $y = \log (b^{2} - 4 b)$ .

$b = 10$

$x = 16 + 2 b$

$y = \log (b^{2} - 4 b)$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$10^{\log (b^{2} - 4 b)} = 16 + 2 b$