Finite Math Examples

$\ln (\frac{6}{9}) = \ln (e^{- 0.2 t})$

Step 1

For logarithmic equations, $\log_{b} (x) = y$ is equivalent to $b^{y} = x$ such that $x > 0$ , $b > 0$ , and $b \neq 1$ . In this case, $b = e$ , $x = \frac{6}{9}$ , and $y = \ln (e^{- 0.2 t})$ .

$b = e$

$x = \frac{6}{9}$

$y = \ln (e^{- 0.2 t})$

Step 2

Substitute the values of $b$ , $x$ , and $y$ into the equation $b^{y} = x$ .

$e^{\ln (e^{- 0.2 t})} = \frac{6}{9}$