Finite Math Examples

$S (p) = 9 p + 12$ , $D (p) = 280 - 9 p$

Step 1

Set up the composite result function.

$S (D (p))$

Step 2

Evaluate $S (280 - 9 p)$ by substituting in the value of $D$ into $S$ .

$S (280 - 9 p) = 9 (280 - 9 p) + 12$

Step 3

Simplify each term.

Tap for more steps...

Step 3.1

Apply the distributive property.

$S (280 - 9 p) = 9 \cdot 280 + 9 (- 9 p) + 12$

Step 3.2

Multiply $9$ by $280$ .

$S (280 - 9 p) = 2520 + 9 (- 9 p) + 12$

Step 3.3

Multiply $- 9$ by $9$ .

$S (280 - 9 p) = 2520 - 81 p + 12$

Step 4

Add $2520$ and $12$ .

$S (280 - 9 p) = - 81 p + 2532$