Finite Math Examples

$x - 3 y - 3 z = 4$ , $2 x + y + z = 1$ , $3 x - 2 y - 2 z = 6$

Step 1

Write the system as a matrix.

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 2 & 1 & 1 & 1 \\ 3 & - 2 & - 2 & 6 \end{array}]$

Step 2

Find the reduced row echelon form.

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Step 2.1

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

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Step 2.1.1

Perform the row operation $R_{2} = R_{2} - 2 R_{1}$ to make the entry at $2, 1$ a $0$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 2 - 2 \cdot 1 & 1 - 2 \cdot - 3 & 1 - 2 \cdot - 3 & 1 - 2 \cdot 4 \\ 3 & - 2 & - 2 & 6 \end{array}]$

Step 2.1.2

Simplify $R_{2}$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 7 & 7 & - 7 \\ 3 & - 2 & - 2 & 6 \end{array}]$

Step 2.2

Perform the row operation $R_{3} = R_{3} - 3 R_{1}$ to make the entry at $3, 1$ a $0$ .

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Step 2.2.1

Perform the row operation $R_{3} = R_{3} - 3 R_{1}$ to make the entry at $3, 1$ a $0$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 7 & 7 & - 7 \\ 3 - 3 \cdot 1 & - 2 - 3 \cdot - 3 & - 2 - 3 \cdot - 3 & 6 - 3 \cdot 4 \end{array}]$

Step 2.2.2

Simplify $R_{3}$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 7 & 7 & - 7 \\ 0 & 7 & 7 & - 6 \end{array}]$

Step 2.3

Multiply each element of $R_{2}$ by $\frac{1}{7}$ to make the entry at $2, 2$ a $1$ .

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Step 2.3.1

Multiply each element of $R_{2}$ by $\frac{1}{7}$ to make the entry at $2, 2$ a $1$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ \frac{0}{7} & \frac{7}{7} & \frac{7}{7} & \frac{- 7}{7} \\ 0 & 7 & 7 & - 6 \end{array}]$

Step 2.3.2

Simplify $R_{2}$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 1 & 1 & - 1 \\ 0 & 7 & 7 & - 6 \end{array}]$

Step 2.4

Perform the row operation $R_{3} = R_{3} - 7 R_{2}$ to make the entry at $3, 2$ a $0$ .

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Step 2.4.1

Perform the row operation $R_{3} = R_{3} - 7 R_{2}$ to make the entry at $3, 2$ a $0$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 1 & 1 & - 1 \\ 0 - 7 \cdot 0 & 7 - 7 \cdot 1 & 7 - 7 \cdot 1 & - 6 - 7 \cdot - 1 \end{array}]$

Step 2.4.2

Simplify $R_{3}$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 1 & 1 & - 1 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 2.5

Perform the row operation $R_{2} = R_{2} + R_{3}$ to make the entry at $2, 4$ a $0$ .

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Step 2.5.1

Perform the row operation $R_{2} = R_{2} + R_{3}$ to make the entry at $2, 4$ a $0$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 + 0 & 1 + 0 & 1 + 0 & - 1 + 1 \cdot 1 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 2.5.2

Simplify $R_{2}$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 4 \\ 0 & 1 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 2.6

Perform the row operation $R_{1} = R_{1} - 4 R_{3}$ to make the entry at $1, 4$ a $0$ .

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Step 2.6.1

Perform the row operation $R_{1} = R_{1} - 4 R_{3}$ to make the entry at $1, 4$ a $0$ .

$[\begin{array}{c} 1 - 4 \cdot 0 & - 3 - 4 \cdot 0 & - 3 - 4 \cdot 0 & 4 - 4 \cdot 1 \\ 0 & 1 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 2.6.2

Simplify $R_{1}$ .

$[\begin{array}{c} 1 & - 3 & - 3 & 0 \\ 0 & 1 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 2.7

Perform the row operation $R_{1} = R_{1} + 3 R_{2}$ to make the entry at $1, 2$ a $0$ .

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Step 2.7.1

Perform the row operation $R_{1} = R_{1} + 3 R_{2}$ to make the entry at $1, 2$ a $0$ .

$[\begin{array}{c} 1 + 3 \cdot 0 & - 3 + 3 \cdot 1 & - 3 + 3 \cdot 1 & 0 + 3 \cdot 0 \\ 0 & 1 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 2.7.2

Simplify $R_{1}$ .

$[\begin{array}{c} 1 & 0 & 0 & 0 \\ 0 & 1 & 1 & 0 \\ 0 & 0 & 0 & 1 \end{array}]$

Step 3

Use the result matrix to declare the final solution to the system of equations.

$x = 0$

$y + z = 0$

$0 = 1$

Step 4

The system is inconsistent so there is no solution.

$No solution$