Finite Math Examples

$100 a - 60 b - 40 c = 12$ , $- 60 a + 104 b - 4 c = 0$ , $- 40 a - 4 b + 104 c = 0$

Step 1

Solve for $a$ in $100 a - 60 b - 40 c = 12$ .

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Step 1.1

Move all terms not containing $a$ to the right side of the equation.

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Step 1.1.1

Add $60 b$ to both sides of the equation.

$100 a - 40 c = 12 + 60 b$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.1.2

Add $40 c$ to both sides of the equation.

$100 a = 12 + 60 b + 40 c$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$100 a = 12 + 60 b + 40 c$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2

Divide each term in $100 a = 12 + 60 b + 40 c$ by $100$ and simplify.

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Step 1.2.1

Divide each term in $100 a = 12 + 60 b + 40 c$ by $100$ .

$\frac{100 a}{100} = \frac{12}{100} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $100$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{100 a}{100} = \frac{12}{100} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.2.1.2

Divide $a$ by $1$ .

$a = \frac{12}{100} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{12}{100} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{12}{100} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Cancel the common factor of $12$ and $100$ .

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Step 1.2.3.1.1.1

Factor $4$ out of $12$ .

$a = \frac{4 (3)}{100} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.1.2

Cancel the common factors.

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Step 1.2.3.1.1.2.1

Factor $4$ out of $100$ .

$a = \frac{4 \cdot 3}{4 \cdot 25} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.1.2.2

Cancel the common factor.

$a = \frac{4 \cdot 3}{4 \cdot 25} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.1.2.3

Rewrite the expression.

$a = \frac{3}{25} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{60 b}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.2

Cancel the common factor of $60$ and $100$ .

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Step 1.2.3.1.2.1

Factor $20$ out of $60 b$ .

$a = \frac{3}{25} + \frac{20 (3 b)}{100} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.2.2

Cancel the common factors.

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Step 1.2.3.1.2.2.1

Factor $20$ out of $100$ .

$a = \frac{3}{25} + \frac{20 (3 b)}{20 (5)} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.2.2.2

Cancel the common factor.

$a = \frac{3}{25} + \frac{20 (3 b)}{20 \cdot 5} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.2.2.3

Rewrite the expression.

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{40 c}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.3

Cancel the common factor of $40$ and $100$ .

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Step 1.2.3.1.3.1

Factor $20$ out of $40 c$ .

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{20 (2 c)}{100}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.3.2

Cancel the common factors.

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Step 1.2.3.1.3.2.1

Factor $20$ out of $100$ .

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{20 (2 c)}{20 (5)}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.3.2.2

Cancel the common factor.

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{20 (2 c)}{20 \cdot 5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 1.2.3.1.3.2.3

Rewrite the expression.

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 60 a + 104 b - 4 c = 0$

$- 40 a - 4 b + 104 c = 0$

Step 2

Replace all occurrences of $a$ with $\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$ in each equation.

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Step 2.1

Replace all occurrences of $a$ in $- 60 a + 104 b - 4 c = 0$ with $\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$ .

$- 60 (\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}) + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $- 60 (\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}) + 104 b - 4 c$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$- 60 (\frac{3}{25}) - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Cancel the common factor of $5$ .

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Step 2.2.1.1.2.1.1

Factor $5$ out of $- 60$ .

$5 (- 12) (\frac{3}{25}) - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.1.2

Factor $5$ out of $25$ .

$5 \cdot (- 12 \frac{3}{5 \cdot 5}) - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.1.3

Cancel the common factor.

$5 \cdot (- 12 \frac{3}{5 \cdot 5}) - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.1.4

Rewrite the expression.

$- 12 (\frac{3}{5}) - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$- 12 (\frac{3}{5}) - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.2

Combine $- 12$ and $\frac{3}{5}$ .

$\frac{- 12 \cdot 3}{5} - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.3

Multiply $- 12$ by $3$ .

$\frac{- 36}{5} - 60 \frac{3 b}{5} - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.4

Cancel the common factor of $5$ .

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Step 2.2.1.1.2.4.1

Factor $5$ out of $- 60$ .

$\frac{- 36}{5} + 5 (- 12) (\frac{3 b}{5}) - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.4.2

Cancel the common factor.

$\frac{- 36}{5} + 5 \cdot (- 12 \frac{3 b}{5}) - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.4.3

Rewrite the expression.

$\frac{- 36}{5} - 12 (3 b) - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$\frac{- 36}{5} - 12 (3 b) - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.5

Multiply $3$ by $- 12$ .

$\frac{- 36}{5} - 36 b - 60 \frac{2 c}{5} + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.6

Cancel the common factor of $5$ .

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Step 2.2.1.1.2.6.1

Factor $5$ out of $- 60$ .

$\frac{- 36}{5} - 36 b + 5 (- 12) (\frac{2 c}{5}) + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.6.2

Cancel the common factor.

$\frac{- 36}{5} - 36 b + 5 \cdot (- 12 \frac{2 c}{5}) + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.6.3

Rewrite the expression.

$\frac{- 36}{5} - 36 b - 12 (2 c) + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$\frac{- 36}{5} - 36 b - 12 (2 c) + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.2.7

Multiply $2$ by $- 12$ .

$\frac{- 36}{5} - 36 b - 24 c + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$\frac{- 36}{5} - 36 b - 24 c + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.1.3

Move the negative in front of the fraction.

$- \frac{36}{5} - 36 b - 24 c + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$- \frac{36}{5} - 36 b - 24 c + 104 b - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Add $- 36 b$ and $104 b$ .

$- \frac{36}{5} + 68 b - 24 c - 4 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.2.1.2.2

Subtract $4 c$ from $- 24 c$ .

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 40 a - 4 b + 104 c = 0$

Step 2.3

Replace all occurrences of $a$ in $- 40 a - 4 b + 104 c = 0$ with $\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$ .

$- 40 (\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}) - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $- 40 (\frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}) - 4 b + 104 c$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$- 40 (\frac{3}{25}) - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2

Simplify.

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Step 2.4.1.1.2.1

Cancel the common factor of $5$ .

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Step 2.4.1.1.2.1.1

Factor $5$ out of $- 40$ .

$5 (- 8) (\frac{3}{25}) - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.1.2

Factor $5$ out of $25$ .

$5 \cdot (- 8 \frac{3}{5 \cdot 5}) - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.1.3

Cancel the common factor.

$5 \cdot (- 8 \frac{3}{5 \cdot 5}) - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.1.4

Rewrite the expression.

$- 8 (\frac{3}{5}) - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 8 (\frac{3}{5}) - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.2

Combine $- 8$ and $\frac{3}{5}$ .

$\frac{- 8 \cdot 3}{5} - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.3

Multiply $- 8$ by $3$ .

$\frac{- 24}{5} - 40 \frac{3 b}{5} - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.4

Cancel the common factor of $5$ .

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Step 2.4.1.1.2.4.1

Factor $5$ out of $- 40$ .

$\frac{- 24}{5} + 5 (- 8) (\frac{3 b}{5}) - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.4.2

Cancel the common factor.

$\frac{- 24}{5} + 5 \cdot (- 8 \frac{3 b}{5}) - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.4.3

Rewrite the expression.

$\frac{- 24}{5} - 8 (3 b) - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{- 24}{5} - 8 (3 b) - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.5

Multiply $3$ by $- 8$ .

$\frac{- 24}{5} - 24 b - 40 \frac{2 c}{5} - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.6

Cancel the common factor of $5$ .

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Step 2.4.1.1.2.6.1

Factor $5$ out of $- 40$ .

$\frac{- 24}{5} - 24 b + 5 (- 8) (\frac{2 c}{5}) - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.6.2

Cancel the common factor.

$\frac{- 24}{5} - 24 b + 5 \cdot (- 8 \frac{2 c}{5}) - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.6.3

Rewrite the expression.

$\frac{- 24}{5} - 24 b - 8 (2 c) - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{- 24}{5} - 24 b - 8 (2 c) - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.2.7

Multiply $2$ by $- 8$ .

$\frac{- 24}{5} - 24 b - 16 c - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{- 24}{5} - 24 b - 16 c - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.1.3

Move the negative in front of the fraction.

$- \frac{24}{5} - 24 b - 16 c - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{24}{5} - 24 b - 16 c - 4 b + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.2

Simplify by adding terms.

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Step 2.4.1.2.1

Subtract $4 b$ from $- 24 b$ .

$- \frac{24}{5} - 28 b - 16 c + 104 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 2.4.1.2.2

Add $- 16 c$ and $104 c$ .

$- \frac{24}{5} - 28 b + 88 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{24}{5} - 28 b + 88 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{24}{5} - 28 b + 88 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{24}{5} - 28 b + 88 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{24}{5} - 28 b + 88 c = 0$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3

Solve for $b$ in $- \frac{24}{5} - 28 b + 88 c = 0$ .

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Step 3.1

Move all terms not containing $b$ to the right side of the equation.

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Step 3.1.1

Add $\frac{24}{5}$ to both sides of the equation.

$- 28 b + 88 c = \frac{24}{5}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.1.2

Subtract $88 c$ from both sides of the equation.

$- 28 b = \frac{24}{5} - 88 c$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- 28 b = \frac{24}{5} - 88 c$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2

Divide each term in $- 28 b = \frac{24}{5} - 88 c$ by $- 28$ and simplify.

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Step 3.2.1

Divide each term in $- 28 b = \frac{24}{5} - 88 c$ by $- 28$ .

$\frac{- 28 b}{- 28} = \frac{\frac{24}{5}}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $- 28$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{- 28 b}{- 28} = \frac{\frac{24}{5}}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.2.1.2

Divide $b$ by $1$ .

$b = \frac{\frac{24}{5}}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = \frac{\frac{24}{5}}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = \frac{\frac{24}{5}}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Multiply the numerator by the reciprocal of the denominator.

$b = \frac{24}{5} \cdot \frac{1}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.2

Cancel the common factor of $4$ .

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Step 3.2.3.1.2.1

Factor $4$ out of $24$ .

$b = \frac{4 (6)}{5} \cdot \frac{1}{- 28} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.2.2

Factor $4$ out of $- 28$ .

$b = \frac{4 \cdot 6}{5} \cdot \frac{1}{4 \cdot - 7} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.2.3

Cancel the common factor.

$b = \frac{4 \cdot 6}{5} \cdot \frac{1}{4 \cdot - 7} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.2.4

Rewrite the expression.

$b = \frac{6}{5} \cdot \frac{1}{- 7} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = \frac{6}{5} \cdot \frac{1}{- 7} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.3

Multiply $\frac{6}{5}$ by $\frac{1}{- 7}$ .

$b = \frac{6}{5 \cdot - 7} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.4

Multiply $5$ by $- 7$ .

$b = \frac{6}{- 35} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.5

Move the negative in front of the fraction.

$b = - \frac{6}{35} + \frac{- 88 c}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.6

Cancel the common factor of $- 88$ and $- 28$ .

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Step 3.2.3.1.6.1

Factor $- 4$ out of $- 88 c$ .

$b = - \frac{6}{35} + \frac{- 4 (22 c)}{- 28}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.6.2

Cancel the common factors.

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Step 3.2.3.1.6.2.1

Factor $- 4$ out of $- 28$ .

$b = - \frac{6}{35} + \frac{- 4 (22 c)}{- 4 \cdot 7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.6.2.2

Cancel the common factor.

$b = - \frac{6}{35} + \frac{- 4 (22 c)}{- 4 \cdot 7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 3.2.3.1.6.2.3

Rewrite the expression.

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$- \frac{36}{5} + 68 b - 28 c = 0$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4

Replace all occurrences of $b$ with $- \frac{6}{35} + \frac{22 c}{7}$ in each equation.

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Step 4.1

Replace all occurrences of $b$ in $- \frac{36}{5} + 68 b - 28 c = 0$ with $- \frac{6}{35} + \frac{22 c}{7}$ .

$- \frac{36}{5} + 68 (- \frac{6}{35} + \frac{22 c}{7}) - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $- \frac{36}{5} + 68 (- \frac{6}{35} + \frac{22 c}{7}) - 28 c$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$- \frac{36}{5} + 68 (- \frac{6}{35}) + 68 (\frac{22 c}{7}) - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.1.2

Multiply $68 (- \frac{6}{35})$ .

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Step 4.2.1.1.2.1

Multiply $- 1$ by $68$ .

$- \frac{36}{5} - 68 (\frac{6}{35}) + 68 (\frac{22 c}{7}) - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.1.2.2

Combine $- 68$ and $\frac{6}{35}$ .

$- \frac{36}{5} + \frac{- 68 \cdot 6}{35} + 68 (\frac{22 c}{7}) - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.1.2.3

Multiply $- 68$ by $6$ .

$- \frac{36}{5} + \frac{- 408}{35} + 68 (\frac{22 c}{7}) - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{36}{5} + \frac{- 408}{35} + 68 (\frac{22 c}{7}) - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.1.3

Multiply $68 \frac{22 c}{7}$ .

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Step 4.2.1.1.3.1

Combine $68$ and $\frac{22 c}{7}$ .

$- \frac{36}{5} + \frac{- 408}{35} + \frac{68 (22 c)}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.1.3.2

Multiply $22$ by $68$ .

$- \frac{36}{5} + \frac{- 408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{36}{5} + \frac{- 408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.1.4

Move the negative in front of the fraction.

$- \frac{36}{5} - \frac{408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{36}{5} - \frac{408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.2

To write $- \frac{36}{5}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$- \frac{36}{5} \cdot \frac{7}{7} - \frac{408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.3

Write each expression with a common denominator of $35$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.2.1.3.1

Multiply $\frac{36}{5}$ by $\frac{7}{7}$ .

$- \frac{36 \cdot 7}{5 \cdot 7} - \frac{408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.3.2

Multiply $5$ by $7$ .

$- \frac{36 \cdot 7}{35} - \frac{408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{36 \cdot 7}{35} - \frac{408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.4

Combine the numerators over the common denominator.

$\frac{- 36 \cdot 7 - 408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.5

Simplify the numerator.

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Step 4.2.1.5.1

Multiply $- 36$ by $7$ .

$\frac{- 252 - 408}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.5.2

Subtract $408$ from $- 252$ .

$\frac{- 660}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{- 660}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.6

Simplify each term.

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Step 4.2.1.6.1

Cancel the common factor of $- 660$ and $35$ .

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Step 4.2.1.6.1.1

Factor $5$ out of $- 660$ .

$\frac{5 (- 132)}{35} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.6.1.2

Cancel the common factors.

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Step 4.2.1.6.1.2.1

Factor $5$ out of $35$ .

$\frac{5 \cdot - 132}{5 \cdot 7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.6.1.2.2

Cancel the common factor.

$\frac{5 \cdot - 132}{5 \cdot 7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.6.1.2.3

Rewrite the expression.

$\frac{- 132}{7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{- 132}{7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{- 132}{7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.6.2

Move the negative in front of the fraction.

$- \frac{132}{7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{132}{7} + \frac{1496 c}{7} - 28 c = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.7

To write $- 28 c$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$- \frac{132}{7} + \frac{1496 c}{7} - 28 c \cdot \frac{7}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.8

Combine $- 28 c$ and $\frac{7}{7}$ .

$- \frac{132}{7} + \frac{1496 c}{7} + \frac{- 28 c \cdot 7}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.9

Combine the numerators over the common denominator.

$- \frac{132}{7} + \frac{1496 c - 28 c \cdot 7}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.10

Combine the numerators over the common denominator.

$\frac{- 132 + 1496 c - 28 c \cdot 7}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.11

Multiply $7$ by $- 28$ .

$\frac{- 132 + 1496 c - 196 c}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.12

Subtract $196 c$ from $1496 c$ .

$\frac{- 132 + 1300 c}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.13

Factor $4$ out of $- 132 + 1300 c$ .

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Step 4.2.1.13.1

Factor $4$ out of $- 132$ .

$\frac{4 (- 33) + 1300 c}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.13.2

Factor $4$ out of $1300 c$ .

$\frac{4 (- 33) + 4 (325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.13.3

Factor $4$ out of $4 (- 33) + 4 (325 c)$ .

$\frac{4 (- 33 + 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$\frac{4 (- 33 + 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.14

Rewrite $- 33$ as $- 1 (33)$ .

$\frac{4 (- 1 \cdot 33 + 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.15

Factor $- 1$ out of $325 c$ .

$\frac{4 (- 1 \cdot 33 - (- 325 c))}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.16

Factor $- 1$ out of $- 1 (33) - (- 325 c)$ .

$\frac{4 (- 1 (33 - 325 c))}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.2.1.17

Move the negative in front of the fraction.

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$

Step 4.3

Replace all occurrences of $b$ in $a = \frac{3}{25} + \frac{3 b}{5} + \frac{2 c}{5}$ with $- \frac{6}{35} + \frac{22 c}{7}$ .

$a = \frac{3}{25} + \frac{3 (- \frac{6}{35} + \frac{22 c}{7})}{5} + \frac{2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $\frac{3}{25} + \frac{3 (- \frac{6}{35} + \frac{22 c}{7})}{5} + \frac{2 c}{5}$ .

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Step 4.4.1.1

Combine the numerators over the common denominator.

$a = \frac{3}{25} + \frac{3 (- \frac{6}{35} + \frac{22 c}{7}) + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2

Simplify each term.

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Step 4.4.1.2.1

Apply the distributive property.

$a = \frac{3}{25} + \frac{3 (- \frac{6}{35}) + 3 (\frac{22 c}{7}) + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2.2

Multiply $3 (- \frac{6}{35})$ .

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Step 4.4.1.2.2.1

Multiply $- 1$ by $3$ .

$a = \frac{3}{25} + \frac{- 3 (\frac{6}{35}) + 3 (\frac{22 c}{7}) + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2.2.2

Combine $- 3$ and $\frac{6}{35}$ .

$a = \frac{3}{25} + \frac{\frac{- 3 \cdot 6}{35} + 3 (\frac{22 c}{7}) + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2.2.3

Multiply $- 3$ by $6$ .

$a = \frac{3}{25} + \frac{\frac{- 18}{35} + 3 (\frac{22 c}{7}) + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{\frac{- 18}{35} + 3 (\frac{22 c}{7}) + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2.3

Multiply $3 \frac{22 c}{7}$ .

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Step 4.4.1.2.3.1

Combine $3$ and $\frac{22 c}{7}$ .

$a = \frac{3}{25} + \frac{\frac{- 18}{35} + \frac{3 (22 c)}{7} + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2.3.2

Multiply $22$ by $3$ .

$a = \frac{3}{25} + \frac{\frac{- 18}{35} + \frac{66 c}{7} + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{\frac{- 18}{35} + \frac{66 c}{7} + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.2.4

Move the negative in front of the fraction.

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{66 c}{7} + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{66 c}{7} + 2 c}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.3

To write $2 c$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{66 c}{7} + 2 c \cdot \frac{7}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.4

Simplify terms.

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Step 4.4.1.4.1

Combine $2 c$ and $\frac{7}{7}$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{66 c}{7} + \frac{2 c \cdot 7}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.4.2

Combine the numerators over the common denominator.

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{66 c + 2 c \cdot 7}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{66 c + 2 c \cdot 7}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.5

Simplify the numerator.

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Step 4.4.1.5.1

Factor $2 c$ out of $66 c + 2 c \cdot 7$ .

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Step 4.4.1.5.1.1

Factor $2 c$ out of $66 c$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{2 c (33) + 2 c \cdot 7}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.5.1.2

Factor $2 c$ out of $2 c \cdot 7$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{2 c (33) + 2 c (7)}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.5.1.3

Factor $2 c$ out of $2 c (33) + 2 c (7)$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{2 c (33 + 7)}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{2 c (33 + 7)}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.5.2

Add $33$ and $7$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{2 c \cdot 40}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.5.3

Multiply $40$ by $2$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{80 c}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{80 c}{7}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6

Simplify each term.

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Step 4.4.1.6.1

Simplify the numerator.

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Step 4.4.1.6.1.1

To write $\frac{80 c}{7}$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{80 c}{7} \cdot \frac{5}{5}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.2

Write each expression with a common denominator of $35$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.4.1.6.1.2.1

Multiply $\frac{80 c}{7}$ by $\frac{5}{5}$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{80 c \cdot 5}{7 \cdot 5}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.2.2

Multiply $7$ by $5$ .

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{80 c \cdot 5}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{- \frac{18}{35} + \frac{80 c \cdot 5}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.3

Combine the numerators over the common denominator.

$a = \frac{3}{25} + \frac{\frac{- 18 + 80 c \cdot 5}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.4

Simplify the numerator.

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Step 4.4.1.6.1.4.1

Factor $2$ out of $- 18 + 80 c \cdot 5$ .

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Step 4.4.1.6.1.4.1.1

Factor $2$ out of $- 18$ .

$a = \frac{3}{25} + \frac{\frac{2 (- 9) + 80 c \cdot 5}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.4.1.2

Factor $2$ out of $80 c \cdot 5$ .

$a = \frac{3}{25} + \frac{\frac{2 (- 9) + 2 (40 c \cdot 5)}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.4.1.3

Factor $2$ out of $2 (- 9) + 2 (40 c \cdot 5)$ .

$a = \frac{3}{25} + \frac{\frac{2 (- 9 + 40 c \cdot 5)}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{\frac{2 (- 9 + 40 c \cdot 5)}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.1.4.2

Multiply $5$ by $40$ .

$a = \frac{3}{25} + \frac{\frac{2 (- 9 + 200 c)}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{\frac{2 (- 9 + 200 c)}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{\frac{2 (- 9 + 200 c)}{35}}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.2

Multiply the numerator by the reciprocal of the denominator.

$a = \frac{3}{25} + \frac{2 (- 9 + 200 c)}{35} \cdot \frac{1}{5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.3

Multiply $\frac{2 (- 9 + 200 c)}{35} \cdot \frac{1}{5}$ .

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Step 4.4.1.6.3.1

Multiply $\frac{2 (- 9 + 200 c)}{35}$ by $\frac{1}{5}$ .

$a = \frac{3}{25} + \frac{2 (- 9 + 200 c)}{35 \cdot 5}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.6.3.2

Multiply $35$ by $5$ .

$a = \frac{3}{25} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3}{25} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.7

To write $\frac{3}{25}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$a = \frac{3}{25} \cdot \frac{7}{7} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.8

Write each expression with a common denominator of $175$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.4.1.8.1

Multiply $\frac{3}{25}$ by $\frac{7}{7}$ .

$a = \frac{3 \cdot 7}{25 \cdot 7} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.8.2

Multiply $25$ by $7$ .

$a = \frac{3 \cdot 7}{175} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3 \cdot 7}{175} + \frac{2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.9

Combine the numerators over the common denominator.

$a = \frac{3 \cdot 7 + 2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.10

Simplify the numerator.

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Step 4.4.1.10.1

Multiply $3$ by $7$ .

$a = \frac{21 + 2 (- 9 + 200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.10.2

Apply the distributive property.

$a = \frac{21 + 2 \cdot - 9 + 2 (200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.10.3

Multiply $2$ by $- 9$ .

$a = \frac{21 - 18 + 2 (200 c)}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.10.4

Multiply $200$ by $2$ .

$a = \frac{21 - 18 + 400 c}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 4.4.1.10.5

Subtract $18$ from $21$ .

$a = \frac{3 + 400 c}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3 + 400 c}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3 + 400 c}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3 + 400 c}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3 + 400 c}{175}$

$- \frac{4 (33 - 325 c)}{7} = 0$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5

Solve for $c$ in $- \frac{4 (33 - 325 c)}{7} = 0$ .

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Step 5.1

Set the numerator equal to zero.

$4 (33 - 325 c) = 0$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2

Solve the equation for $c$ .

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Step 5.2.1

Divide each term in $4 (33 - 325 c) = 0$ by $4$ and simplify.

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Step 5.2.1.1

Divide each term in $4 (33 - 325 c) = 0$ by $4$ .

$\frac{4 (33 - 325 c)}{4} = \frac{0}{4}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.1.2

Simplify the left side.

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Step 5.2.1.2.1

Cancel the common factor of $4$ .

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Step 5.2.1.2.1.1

Cancel the common factor.

$\frac{4 (33 - 325 c)}{4} = \frac{0}{4}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.1.2.1.2

Divide $33 - 325 c$ by $1$ .

$33 - 325 c = \frac{0}{4}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$33 - 325 c = \frac{0}{4}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$33 - 325 c = \frac{0}{4}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.1.3

Simplify the right side.

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Step 5.2.1.3.1

Divide $0$ by $4$ .

$33 - 325 c = 0$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$33 - 325 c = 0$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$33 - 325 c = 0$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.2

Subtract $33$ from both sides of the equation.

$- 325 c = - 33$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.3

Divide each term in $- 325 c = - 33$ by $- 325$ and simplify.

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Step 5.2.3.1

Divide each term in $- 325 c = - 33$ by $- 325$ .

$\frac{- 325 c}{- 325} = \frac{- 33}{- 325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.3.2

Simplify the left side.

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Step 5.2.3.2.1

Cancel the common factor of $- 325$ .

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Step 5.2.3.2.1.1

Cancel the common factor.

$\frac{- 325 c}{- 325} = \frac{- 33}{- 325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.3.2.1.2

Divide $c$ by $1$ .

$c = \frac{- 33}{- 325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$c = \frac{- 33}{- 325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$c = \frac{- 33}{- 325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 5.2.3.3

Simplify the right side.

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Step 5.2.3.3.1

Dividing two negative values results in a positive value.

$c = \frac{33}{325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$c = \frac{33}{325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$c = \frac{33}{325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$c = \frac{33}{325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$c = \frac{33}{325}$

$a = \frac{3 + 400 c}{175}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6

Replace all occurrences of $c$ with $\frac{33}{325}$ in each equation.

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Step 6.1

Replace all occurrences of $c$ in $a = \frac{3 + 400 c}{175}$ with $\frac{33}{325}$ .

$a = \frac{3 + 400 (\frac{33}{325})}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $\frac{3 + 400 (\frac{33}{325})}{175}$ .

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Step 6.2.1.1

Simplify the numerator.

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Step 6.2.1.1.1

Cancel the common factor of $25$ .

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Step 6.2.1.1.1.1

Factor $25$ out of $400$ .

$a = \frac{3 + 25 (16) (\frac{33}{325})}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.1.2

Factor $25$ out of $325$ .

$a = \frac{3 + 25 \cdot (16 (\frac{33}{25 \cdot 13}))}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.1.3

Cancel the common factor.

$a = \frac{3 + 25 \cdot (16 (\frac{33}{25 \cdot 13}))}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.1.4

Rewrite the expression.

$a = \frac{3 + 16 (\frac{33}{13})}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{3 + 16 (\frac{33}{13})}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.2

Combine $16$ and $\frac{33}{13}$ .

$a = \frac{3 + \frac{16 \cdot 33}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.3

Multiply $16$ by $33$ .

$a = \frac{3 + \frac{528}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.4

To write $3$ as a fraction with a common denominator, multiply by $\frac{13}{13}$ .

$a = \frac{3 \cdot \frac{13}{13} + \frac{528}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.5

Combine $3$ and $\frac{13}{13}$ .

$a = \frac{\frac{3 \cdot 13}{13} + \frac{528}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.6

Combine the numerators over the common denominator.

$a = \frac{\frac{3 \cdot 13 + 528}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.7

Simplify the numerator.

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Step 6.2.1.1.7.1

Multiply $3$ by $13$ .

$a = \frac{\frac{39 + 528}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.1.7.2

Add $39$ and $528$ .

$a = \frac{\frac{567}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{\frac{567}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{\frac{567}{13}}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.2

Multiply the numerator by the reciprocal of the denominator.

$a = \frac{567}{13} \cdot \frac{1}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.3

Cancel the common factor of $7$ .

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Step 6.2.1.3.1

Factor $7$ out of $567$ .

$a = \frac{7 (81)}{13} \cdot \frac{1}{175}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.3.2

Factor $7$ out of $175$ .

$a = \frac{7 \cdot 81}{13} \cdot \frac{1}{7 \cdot 25}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.3.3

Cancel the common factor.

$a = \frac{7 \cdot 81}{13} \cdot \frac{1}{7 \cdot 25}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.3.4

Rewrite the expression.

$a = \frac{81}{13} \cdot \frac{1}{25}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{81}{13} \cdot \frac{1}{25}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.4

Multiply $\frac{81}{13}$ by $\frac{1}{25}$ .

$a = \frac{81}{13 \cdot 25}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.2.1.5

Multiply $13$ by $25$ .

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{22 c}{7}$

Step 6.3

Replace all occurrences of $c$ in $b = - \frac{6}{35} + \frac{22 c}{7}$ with $\frac{33}{325}$ .

$b = - \frac{6}{35} + \frac{22 (\frac{33}{325})}{7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $- \frac{6}{35} + \frac{22 (\frac{33}{325})}{7}$ .

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Step 6.4.1.1

Simplify each term.

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Step 6.4.1.1.1

Combine $22$ and $\frac{33}{325}$ .

$b = - \frac{6}{35} + \frac{\frac{22 \cdot 33}{325}}{7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.1.2

Multiply $22$ by $33$ .

$b = - \frac{6}{35} + \frac{\frac{726}{325}}{7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.1.3

Multiply the numerator by the reciprocal of the denominator.

$b = - \frac{6}{35} + \frac{726}{325} \cdot \frac{1}{7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.1.4

Multiply $\frac{726}{325} \cdot \frac{1}{7}$ .

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Step 6.4.1.1.4.1

Multiply $\frac{726}{325}$ by $\frac{1}{7}$ .

$b = - \frac{6}{35} + \frac{726}{325 \cdot 7}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.1.4.2

Multiply $325$ by $7$ .

$b = - \frac{6}{35} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = - \frac{6}{35} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.2

To write $- \frac{6}{35}$ as a fraction with a common denominator, multiply by $\frac{65}{65}$ .

$b = - \frac{6}{35} \cdot \frac{65}{65} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.3

Write each expression with a common denominator of $2275$ , by multiplying each by an appropriate factor of $1$ .

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Step 6.4.1.3.1

Multiply $\frac{6}{35}$ by $\frac{65}{65}$ .

$b = - \frac{6 \cdot 65}{35 \cdot 65} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.3.2

Multiply $35$ by $65$ .

$b = - \frac{6 \cdot 65}{2275} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = - \frac{6 \cdot 65}{2275} + \frac{726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.4

Combine the numerators over the common denominator.

$b = \frac{- 6 \cdot 65 + 726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.5

Simplify the numerator.

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Step 6.4.1.5.1

Multiply $- 6$ by $65$ .

$b = \frac{- 390 + 726}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.5.2

Add $- 390$ and $726$ .

$b = \frac{336}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = \frac{336}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.6

Cancel the common factor of $336$ and $2275$ .

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Step 6.4.1.6.1

Factor $7$ out of $336$ .

$b = \frac{7 (48)}{2275}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.6.2

Cancel the common factors.

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Step 6.4.1.6.2.1

Factor $7$ out of $2275$ .

$b = \frac{7 \cdot 48}{7 \cdot 325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.6.2.2

Cancel the common factor.

$b = \frac{7 \cdot 48}{7 \cdot 325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 6.4.1.6.2.3

Rewrite the expression.

$b = \frac{48}{325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = \frac{48}{325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = \frac{48}{325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = \frac{48}{325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = \frac{48}{325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

$b = \frac{48}{325}$

$a = \frac{81}{325}$

$c = \frac{33}{325}$

Step 7

List all of the solutions.

$b = \frac{48}{325}, a = \frac{81}{325}, c = \frac{33}{325}$