Finite Math Examples

$4 x + 4 y - 4 z = 24$ , $2 x - y + 2 = - 9$ , $x - 2 y + 3 z = 1$

Step 1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1

Add $2 y$ to both sides of the equation.

$x + 3 z = 1 + 2 y$

$4 x + 4 y - 4 z = 24$

$2 x - y + 2 = - 9$

Step 1.2

Subtract $3 z$ from both sides of the equation.

$x = 1 + 2 y - 3 z$

$4 x + 4 y - 4 z = 24$

$2 x - y + 2 = - 9$

$x = 1 + 2 y - 3 z$

$4 x + 4 y - 4 z = 24$

$2 x - y + 2 = - 9$

Step 2

Replace all occurrences of $x$ with $1 + 2 y - 3 z$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $4 x + 4 y - 4 z = 24$ with $1 + 2 y - 3 z$ .

$4 (1 + 2 y - 3 z) + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $4 (1 + 2 y - 3 z) + 4 y - 4 z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$4 \cdot 1 + 4 (2 y) + 4 (- 3 z) + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $4$ by $1$ .

$4 + 4 (2 y) + 4 (- 3 z) + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.2.1.1.2.2

Multiply $2$ by $4$ .

$4 + 8 y + 4 (- 3 z) + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.2.1.1.2.3

Multiply $- 3$ by $4$ .

$4 + 8 y - 12 z + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

$4 + 8 y - 12 z + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

$4 + 8 y - 12 z + 4 y - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Add $8 y$ and $4 y$ .

$4 + 12 y - 12 z - 4 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.2.1.2.2

Subtract $4 z$ from $- 12 z$ .

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$2 x - y + 2 = - 9$

Step 2.3

Replace all occurrences of $x$ in $2 x - y + 2 = - 9$ with $1 + 2 y - 3 z$ .

$2 (1 + 2 y - 3 z) - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $2 (1 + 2 y - 3 z) - y + 2$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$2 \cdot 1 + 2 (2 y) + 2 (- 3 z) - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 2.4.1.1.2

Simplify.

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Step 2.4.1.1.2.1

Multiply $2$ by $1$ .

$2 + 2 (2 y) + 2 (- 3 z) - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 2.4.1.1.2.2

Multiply $2$ by $2$ .

$2 + 4 y + 2 (- 3 z) - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 2.4.1.1.2.3

Multiply $- 3$ by $2$ .

$2 + 4 y - 6 z - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$2 + 4 y - 6 z - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$2 + 4 y - 6 z - y + 2 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 2.4.1.2

Simplify by adding terms.

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Step 2.4.1.2.1

Add $2$ and $2$ .

$4 y - 6 z - y + 4 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 2.4.1.2.2

Subtract $y$ from $4 y$ .

$3 y - 6 z + 4 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$3 y - 6 z + 4 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$3 y - 6 z + 4 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$3 y - 6 z + 4 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$3 y - 6 z + 4 = - 9$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3

Solve for $y$ in $3 y - 6 z + 4 = - 9$ .

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Step 3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 3.1.1

Add $6 z$ to both sides of the equation.

$3 y + 4 = - 9 + 6 z$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.1.2

Subtract $4$ from both sides of the equation.

$3 y = - 9 + 6 z - 4$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.1.3

Subtract $4$ from $- 9$ .

$3 y = 6 z - 13$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$3 y = 6 z - 13$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2

Divide each term in $3 y = 6 z - 13$ by $3$ and simplify.

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Step 3.2.1

Divide each term in $3 y = 6 z - 13$ by $3$ .

$\frac{3 y}{3} = \frac{6 z}{3} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $3$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{3 y}{3} = \frac{6 z}{3} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{6 z}{3} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = \frac{6 z}{3} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = \frac{6 z}{3} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Cancel the common factor of $6$ and $3$ .

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Step 3.2.3.1.1.1

Factor $3$ out of $6 z$ .

$y = \frac{3 (2 z)}{3} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.3.1.1.2

Cancel the common factors.

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Step 3.2.3.1.1.2.1

Factor $3$ out of $3$ .

$y = \frac{3 (2 z)}{3 (1)} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.3.1.1.2.2

Cancel the common factor.

$y = \frac{3 (2 z)}{3 \cdot 1} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.3.1.1.2.3

Rewrite the expression.

$y = \frac{2 z}{1} + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.3.1.1.2.4

Divide $2 z$ by $1$ .

$y = 2 z + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = 2 z + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = 2 z + \frac{- 13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 3.2.3.1.2

Move the negative in front of the fraction.

$y = 2 z - \frac{13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = 2 z - \frac{13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = 2 z - \frac{13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = 2 z - \frac{13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

$y = 2 z - \frac{13}{3}$

$4 + 12 y - 16 z = 24$

$x = 1 + 2 y - 3 z$

Step 4

Replace all occurrences of $y$ with $2 z - \frac{13}{3}$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $4 + 12 y - 16 z = 24$ with $2 z - \frac{13}{3}$ .

$4 + 12 (2 z - \frac{13}{3}) - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $4 + 12 (2 z - \frac{13}{3}) - 16 z$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$4 + 12 (2 z) + 12 (- \frac{13}{3}) - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.1.2

Multiply $2$ by $12$ .

$4 + 24 z + 12 (- \frac{13}{3}) - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.1.3

Cancel the common factor of $3$ .

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Step 4.2.1.1.3.1

Move the leading negative in $- \frac{13}{3}$ into the numerator.

$4 + 24 z + 12 (\frac{- 13}{3}) - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.1.3.2

Factor $3$ out of $12$ .

$4 + 24 z + 3 (4) (\frac{- 13}{3}) - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.1.3.3

Cancel the common factor.

$4 + 24 z + 3 \cdot (4 (\frac{- 13}{3})) - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.1.3.4

Rewrite the expression.

$4 + 24 z + 4 \cdot - 13 - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

$4 + 24 z + 4 \cdot - 13 - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.1.4

Multiply $4$ by $- 13$ .

$4 + 24 z - 52 - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

$4 + 24 z - 52 - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.2

Simplify by adding terms.

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Step 4.2.1.2.1

Subtract $52$ from $4$ .

$24 z - 48 - 16 z = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.2.1.2.2

Subtract $16 z$ from $24 z$ .

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 2 y - 3 z$

Step 4.3

Replace all occurrences of $y$ in $x = 1 + 2 y - 3 z$ with $2 z - \frac{13}{3}$ .

$x = 1 + 2 (2 z - \frac{13}{3}) - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $1 + 2 (2 z - \frac{13}{3}) - 3 z$ .

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Step 4.4.1.1

Simplify each term.

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Step 4.4.1.1.1

Apply the distributive property.

$x = 1 + 2 (2 z) + 2 (- \frac{13}{3}) - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.1.2

Multiply $2$ by $2$ .

$x = 1 + 4 z + 2 (- \frac{13}{3}) - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.1.3

Multiply $2 (- \frac{13}{3})$ .

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Step 4.4.1.1.3.1

Multiply $- 1$ by $2$ .

$x = 1 + 4 z - 2 (\frac{13}{3}) - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.1.3.2

Combine $- 2$ and $\frac{13}{3}$ .

$x = 1 + 4 z + \frac{- 2 \cdot 13}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.1.3.3

Multiply $- 2$ by $13$ .

$x = 1 + 4 z + \frac{- 26}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 4 z + \frac{- 26}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.1.4

Move the negative in front of the fraction.

$x = 1 + 4 z - \frac{26}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 1 + 4 z - \frac{26}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.2

Simplify by adding terms.

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Step 4.4.1.2.1

Write $1$ as a fraction with a common denominator.

$x = 4 z + \frac{3}{3} - \frac{26}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.2.2

Simplify the expression.

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Step 4.4.1.2.2.1

Combine the numerators over the common denominator.

$x = 4 z + \frac{3 - 26}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.2.2.2

Subtract $26$ from $3$ .

$x = 4 z + \frac{- 23}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.2.2.3

Move the negative in front of the fraction.

$x = 4 z - \frac{23}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = 4 z - \frac{23}{3} - 3 z$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 4.4.1.2.3

Subtract $3 z$ from $4 z$ .

$x = z - \frac{23}{3}$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = z - \frac{23}{3}$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = z - \frac{23}{3}$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = z - \frac{23}{3}$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

$x = z - \frac{23}{3}$

$8 z - 48 = 24$

$y = 2 z - \frac{13}{3}$

Step 5

Solve for $z$ in $8 z - 48 = 24$ .

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Step 5.1

Move all terms not containing $z$ to the right side of the equation.

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Step 5.1.1

Add $48$ to both sides of the equation.

$8 z = 24 + 48$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

Step 5.1.2

Add $24$ and $48$ .

$8 z = 72$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

$8 z = 72$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

Step 5.2

Divide each term in $8 z = 72$ by $8$ and simplify.

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Step 5.2.1

Divide each term in $8 z = 72$ by $8$ .

$\frac{8 z}{8} = \frac{72}{8}$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

Step 5.2.2

Simplify the left side.

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Step 5.2.2.1

Cancel the common factor of $8$ .

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Step 5.2.2.1.1

Cancel the common factor.

$\frac{8 z}{8} = \frac{72}{8}$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

Step 5.2.2.1.2

Divide $z$ by $1$ .

$z = \frac{72}{8}$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

$z = \frac{72}{8}$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

$z = \frac{72}{8}$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

Step 5.2.3

Simplify the right side.

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Step 5.2.3.1

Divide $72$ by $8$ .

$z = 9$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

$z = 9$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

$z = 9$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

$z = 9$

$x = z - \frac{23}{3}$

$y = 2 z - \frac{13}{3}$

Step 6

Replace all occurrences of $z$ with $9$ in each equation.

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Step 6.1

Replace all occurrences of $z$ in $x = z - \frac{23}{3}$ with $9$ .

$x = (9) - \frac{23}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $(9) - \frac{23}{3}$ .

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Step 6.2.1.1

To write $9$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$x = 9 \cdot \frac{3}{3} - \frac{23}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

Step 6.2.1.2

Combine $9$ and $\frac{3}{3}$ .

$x = \frac{9 \cdot 3}{3} - \frac{23}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

Step 6.2.1.3

Combine the numerators over the common denominator.

$x = \frac{9 \cdot 3 - 23}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

Step 6.2.1.4

Simplify the numerator.

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Step 6.2.1.4.1

Multiply $9$ by $3$ .

$x = \frac{27 - 23}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

Step 6.2.1.4.2

Subtract $23$ from $27$ .

$x = \frac{4}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = 2 z - \frac{13}{3}$

Step 6.3

Replace all occurrences of $z$ in $y = 2 z - \frac{13}{3}$ with $9$ .

$y = 2 (9) - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $2 (9) - \frac{13}{3}$ .

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Step 6.4.1.1

Multiply $2$ by $9$ .

$y = 18 - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 6.4.1.2

To write $18$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$y = 18 \cdot \frac{3}{3} - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 6.4.1.3

Combine $18$ and $\frac{3}{3}$ .

$y = \frac{18 \cdot 3}{3} - \frac{13}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 6.4.1.4

Combine the numerators over the common denominator.

$y = \frac{18 \cdot 3 - 13}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 6.4.1.5

Simplify the numerator.

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Step 6.4.1.5.1

Multiply $18$ by $3$ .

$y = \frac{54 - 13}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 6.4.1.5.2

Subtract $13$ from $54$ .

$y = \frac{41}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = \frac{41}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = \frac{41}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = \frac{41}{3}$

$x = \frac{4}{3}$

$z = 9$

$y = \frac{41}{3}$

$x = \frac{4}{3}$

$z = 9$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(\frac{4}{3}, \frac{41}{3}, 9)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(\frac{4}{3}, \frac{41}{3}, 9)$

Equation Form:

$x = \frac{4}{3}, y = \frac{41}{3}, z = 9$