Finite Math Examples

$3 x - 5 y + 6 z = 51$ , $5 x + 4 y - z = - 7$ , $8 x + 7 y + 2 z = 5$

Step 1

Solve for $x$ in $3 x - 5 y + 6 z = 51$ .

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Step 1.1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1.1

Add $5 y$ to both sides of the equation.

$3 x + 6 z = 51 + 5 y$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.1.2

Subtract $6 z$ from both sides of the equation.

$3 x = 51 + 5 y - 6 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$3 x = 51 + 5 y - 6 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2

Divide each term in $3 x = 51 + 5 y - 6 z$ by $3$ and simplify.

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Step 1.2.1

Divide each term in $3 x = 51 + 5 y - 6 z$ by $3$ .

$\frac{3 x}{3} = \frac{51}{3} + \frac{5 y}{3} + \frac{- 6 z}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.2

Simplify the left side.

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Step 1.2.2.1

Cancel the common factor of $3$ .

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Step 1.2.2.1.1

Cancel the common factor.

$\frac{3 x}{3} = \frac{51}{3} + \frac{5 y}{3} + \frac{- 6 z}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.2.1.2

Divide $x$ by $1$ .

$x = \frac{51}{3} + \frac{5 y}{3} + \frac{- 6 z}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = \frac{51}{3} + \frac{5 y}{3} + \frac{- 6 z}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = \frac{51}{3} + \frac{5 y}{3} + \frac{- 6 z}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.3

Simplify the right side.

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Step 1.2.3.1

Simplify each term.

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Step 1.2.3.1.1

Divide $51$ by $3$ .

$x = 17 + \frac{5 y}{3} + \frac{- 6 z}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.3.1.2

Cancel the common factor of $- 6$ and $3$ .

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Step 1.2.3.1.2.1

Factor $3$ out of $- 6 z$ .

$x = 17 + \frac{5 y}{3} + \frac{3 (- 2 z)}{3}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.3.1.2.2

Cancel the common factors.

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Step 1.2.3.1.2.2.1

Factor $3$ out of $3$ .

$x = 17 + \frac{5 y}{3} + \frac{3 (- 2 z)}{3 (1)}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.3.1.2.2.2

Cancel the common factor.

$x = 17 + \frac{5 y}{3} + \frac{3 (- 2 z)}{3 \cdot 1}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.3.1.2.2.3

Rewrite the expression.

$x = 17 + \frac{5 y}{3} + \frac{- 2 z}{1}$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 1.2.3.1.2.2.4

Divide $- 2 z$ by $1$ .

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

$x = 17 + \frac{5 y}{3} - 2 z$

$5 x + 4 y - z = - 7$

$8 x + 7 y + 2 z = 5$

Step 2

Replace all occurrences of $x$ with $17 + \frac{5 y}{3} - 2 z$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $5 x + 4 y - z = - 7$ with $17 + \frac{5 y}{3} - 2 z$ .

$5 (17 + \frac{5 y}{3} - 2 z) + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $5 (17 + \frac{5 y}{3} - 2 z) + 4 y - z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$5 \cdot 17 + 5 (\frac{5 y}{3}) + 5 (- 2 z) + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $5$ by $17$ .

$85 + 5 (\frac{5 y}{3}) + 5 (- 2 z) + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.1.2.2

Multiply $5 \frac{5 y}{3}$ .

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Step 2.2.1.1.2.2.1

Combine $5$ and $\frac{5 y}{3}$ .

$85 + \frac{5 (5 y)}{3} + 5 (- 2 z) + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.1.2.2.2

Multiply $5$ by $5$ .

$85 + \frac{25 y}{3} + 5 (- 2 z) + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 + \frac{25 y}{3} + 5 (- 2 z) + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.1.2.3

Multiply $- 2$ by $5$ .

$85 + \frac{25 y}{3} - 10 z + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 + \frac{25 y}{3} - 10 z + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 + \frac{25 y}{3} - 10 z + 4 y - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.2

To write $4 y$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$85 - 10 z + \frac{25 y}{3} + 4 y \cdot \frac{3}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.3

Simplify terms.

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Step 2.2.1.3.1

Combine $4 y$ and $\frac{3}{3}$ .

$85 - 10 z + \frac{25 y}{3} + \frac{4 y \cdot 3}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.3.2

Combine the numerators over the common denominator.

$85 - 10 z + \frac{25 y + 4 y \cdot 3}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 - 10 z + \frac{25 y + 4 y \cdot 3}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.4

Simplify each term.

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Step 2.2.1.4.1

Simplify the numerator.

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Step 2.2.1.4.1.1

Factor $y$ out of $25 y + 4 y \cdot 3$ .

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Step 2.2.1.4.1.1.1

Factor $y$ out of $25 y$ .

$85 - 10 z + \frac{y \cdot 25 + 4 y \cdot 3}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.4.1.1.2

Factor $y$ out of $4 y \cdot 3$ .

$85 - 10 z + \frac{y \cdot 25 + y (4 \cdot 3)}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.4.1.1.3

Factor $y$ out of $y \cdot 25 + y (4 \cdot 3)$ .

$85 - 10 z + \frac{y (25 + 4 \cdot 3)}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 - 10 z + \frac{y (25 + 4 \cdot 3)}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.4.1.2

Multiply $4$ by $3$ .

$85 - 10 z + \frac{y (25 + 12)}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.4.1.3

Add $25$ and $12$ .

$85 - 10 z + \frac{y \cdot 37}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 - 10 z + \frac{y \cdot 37}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.4.2

Move $37$ to the left of $y$ .

$85 - 10 z + \frac{37 y}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 - 10 z + \frac{37 y}{3} - z = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.2.1.5

Subtract $z$ from $- 10 z$ .

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$8 x + 7 y + 2 z = 5$

Step 2.3

Replace all occurrences of $x$ in $8 x + 7 y + 2 z = 5$ with $17 + \frac{5 y}{3} - 2 z$ .

$8 (17 + \frac{5 y}{3} - 2 z) + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $8 (17 + \frac{5 y}{3} - 2 z) + 7 y + 2 z$ .

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Step 2.4.1.1

Simplify each term.

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Step 2.4.1.1.1

Apply the distributive property.

$8 \cdot 17 + 8 (\frac{5 y}{3}) + 8 (- 2 z) + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.1.2

Simplify.

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Step 2.4.1.1.2.1

Multiply $8$ by $17$ .

$136 + 8 (\frac{5 y}{3}) + 8 (- 2 z) + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.1.2.2

Multiply $8 \frac{5 y}{3}$ .

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Step 2.4.1.1.2.2.1

Combine $8$ and $\frac{5 y}{3}$ .

$136 + \frac{8 (5 y)}{3} + 8 (- 2 z) + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.1.2.2.2

Multiply $5$ by $8$ .

$136 + \frac{40 y}{3} + 8 (- 2 z) + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 + \frac{40 y}{3} + 8 (- 2 z) + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.1.2.3

Multiply $- 2$ by $8$ .

$136 + \frac{40 y}{3} - 16 z + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 + \frac{40 y}{3} - 16 z + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 + \frac{40 y}{3} - 16 z + 7 y + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.2

To write $7 y$ as a fraction with a common denominator, multiply by $\frac{3}{3}$ .

$136 - 16 z + \frac{40 y}{3} + 7 y \cdot \frac{3}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.3

Simplify terms.

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Step 2.4.1.3.1

Combine $7 y$ and $\frac{3}{3}$ .

$136 - 16 z + \frac{40 y}{3} + \frac{7 y \cdot 3}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.3.2

Combine the numerators over the common denominator.

$136 - 16 z + \frac{40 y + 7 y \cdot 3}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 16 z + \frac{40 y + 7 y \cdot 3}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.4

Simplify each term.

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Step 2.4.1.4.1

Simplify the numerator.

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Step 2.4.1.4.1.1

Factor $y$ out of $40 y + 7 y \cdot 3$ .

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Step 2.4.1.4.1.1.1

Factor $y$ out of $40 y$ .

$136 - 16 z + \frac{y \cdot 40 + 7 y \cdot 3}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.4.1.1.2

Factor $y$ out of $7 y \cdot 3$ .

$136 - 16 z + \frac{y \cdot 40 + y (7 \cdot 3)}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.4.1.1.3

Factor $y$ out of $y \cdot 40 + y (7 \cdot 3)$ .

$136 - 16 z + \frac{y (40 + 7 \cdot 3)}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 16 z + \frac{y (40 + 7 \cdot 3)}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.4.1.2

Multiply $7$ by $3$ .

$136 - 16 z + \frac{y (40 + 21)}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.4.1.3

Add $40$ and $21$ .

$136 - 16 z + \frac{y \cdot 61}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 16 z + \frac{y \cdot 61}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.4.2

Move $61$ to the left of $y$ .

$136 - 16 z + \frac{61 y}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 16 z + \frac{61 y}{3} + 2 z = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 2.4.1.5

Add $- 16 z$ and $2 z$ .

$136 - 14 z + \frac{61 y}{3} = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 14 z + \frac{61 y}{3} = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 14 z + \frac{61 y}{3} = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$136 - 14 z + \frac{61 y}{3} = 5$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3

Solve for $z$ in $136 - 14 z + \frac{61 y}{3} = 5$ .

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Step 3.1

Move all terms not containing $z$ to the right side of the equation.

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Step 3.1.1

Subtract $136$ from both sides of the equation.

$- 14 z + \frac{61 y}{3} = 5 - 136$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.1.2

Subtract $\frac{61 y}{3}$ from both sides of the equation.

$- 14 z = 5 - 136 - \frac{61 y}{3}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.1.3

Subtract $136$ from $5$ .

$- 14 z = - 131 - \frac{61 y}{3}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$- 14 z = - 131 - \frac{61 y}{3}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2

Divide each term in $- 14 z = - 131 - \frac{61 y}{3}$ by $- 14$ and simplify.

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Step 3.2.1

Divide each term in $- 14 z = - 131 - \frac{61 y}{3}$ by $- 14$ .

$\frac{- 14 z}{- 14} = \frac{- 131}{- 14} + \frac{- \frac{61 y}{3}}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $- 14$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{- 14 z}{- 14} = \frac{- 131}{- 14} + \frac{- \frac{61 y}{3}}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.2.1.2

Divide $z$ by $1$ .

$z = \frac{- 131}{- 14} + \frac{- \frac{61 y}{3}}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{- 131}{- 14} + \frac{- \frac{61 y}{3}}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{- 131}{- 14} + \frac{- \frac{61 y}{3}}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Dividing two negative values results in a positive value.

$z = \frac{131}{14} + \frac{- \frac{61 y}{3}}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3.1.2

Multiply the numerator by the reciprocal of the denominator.

$z = \frac{131}{14} - \frac{61 y}{3} \cdot \frac{1}{- 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3.1.3

Move the negative in front of the fraction.

$z = \frac{131}{14} - \frac{61 y}{3} \cdot (- \frac{1}{14})$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3.1.4

Multiply $- \frac{61 y}{3} (- \frac{1}{14})$ .

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Step 3.2.3.1.4.1

Multiply $- 1$ by $- 1$ .

$z = \frac{131}{14} + 1 (\frac{61 y}{3}) \cdot \frac{1}{14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3.1.4.2

Multiply $\frac{61 y}{3}$ by $1$ .

$z = \frac{131}{14} + \frac{61 y}{3} \cdot \frac{1}{14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3.1.4.3

Multiply $\frac{61 y}{3}$ by $\frac{1}{14}$ .

$z = \frac{131}{14} + \frac{61 y}{3 \cdot 14}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 3.2.3.1.4.4

Multiply $3$ by $14$ .

$z = \frac{131}{14} + \frac{61 y}{42}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{131}{14} + \frac{61 y}{42}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{131}{14} + \frac{61 y}{42}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{131}{14} + \frac{61 y}{42}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{131}{14} + \frac{61 y}{42}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

$z = \frac{131}{14} + \frac{61 y}{42}$

$85 - 11 z + \frac{37 y}{3} = - 7$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4

Replace all occurrences of $z$ with $\frac{131}{14} + \frac{61 y}{42}$ in each equation.

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Step 4.1

Replace all occurrences of $z$ in $85 - 11 z + \frac{37 y}{3} = - 7$ with $\frac{131}{14} + \frac{61 y}{42}$ .

$85 - 11 (\frac{131}{14} + \frac{61 y}{42}) + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $85 - 11 (\frac{131}{14} + \frac{61 y}{42}) + \frac{37 y}{3}$ .

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Step 4.2.1.1

Find the common denominator.

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Step 4.2.1.1.1

Write $85$ as a fraction with denominator $1$ .

$\frac{85}{1} - 11 (\frac{131}{14} + \frac{61 y}{42}) + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.1.2

Multiply $\frac{85}{1}$ by $\frac{3}{3}$ .

$\frac{85}{1} \cdot \frac{3}{3} - 11 (\frac{131}{14} + \frac{61 y}{42}) + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.1.3

Multiply $\frac{85}{1}$ by $\frac{3}{3}$ .

$\frac{85 \cdot 3}{3} - 11 (\frac{131}{14} + \frac{61 y}{42}) + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.1.4

Write $- 11 (\frac{131}{14} + \frac{61 y}{42})$ as a fraction with denominator $1$ .

$\frac{85 \cdot 3}{3} + \frac{- 11 (\frac{131}{14} + \frac{61 y}{42})}{1} + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.1.5

Multiply $\frac{- 11 (\frac{131}{14} + \frac{61 y}{42})}{1}$ by $\frac{3}{3}$ .

$\frac{85 \cdot 3}{3} + \frac{- 11 (\frac{131}{14} + \frac{61 y}{42})}{1} \cdot \frac{3}{3} + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.1.6

Multiply $\frac{- 11 (\frac{131}{14} + \frac{61 y}{42})}{1}$ by $\frac{3}{3}$ .

$\frac{85 \cdot 3}{3} + \frac{- 11 (\frac{131}{14} + \frac{61 y}{42}) \cdot 3}{3} + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{85 \cdot 3}{3} + \frac{- 11 (\frac{131}{14} + \frac{61 y}{42}) \cdot 3}{3} + \frac{37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.2

Combine the numerators over the common denominator.

$\frac{85 \cdot 3 - 11 (\frac{131}{14} + \frac{61 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3

Simplify each term.

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Step 4.2.1.3.1

Multiply $85$ by $3$ .

$\frac{255 - 11 (\frac{131}{14} + \frac{61 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.2

Apply the distributive property.

$\frac{255 + (- 11 (\frac{131}{14}) - 11 \frac{61 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.3

Multiply $- 11 (\frac{131}{14})$ .

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Step 4.2.1.3.3.1

Combine $- 11$ and $\frac{131}{14}$ .

$\frac{255 + (\frac{- 11 \cdot 131}{14} - 11 \frac{61 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.3.2

Multiply $- 11$ by $131$ .

$\frac{255 + (\frac{- 1441}{14} - 11 \frac{61 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 + (\frac{- 1441}{14} - 11 \frac{61 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.4

Multiply $- 11 \frac{61 y}{42}$ .

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Step 4.2.1.3.4.1

Combine $- 11$ and $\frac{61 y}{42}$ .

$\frac{255 + (\frac{- 1441}{14} + \frac{- 11 (61 y)}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.4.2

Multiply $61$ by $- 11$ .

$\frac{255 + (\frac{- 1441}{14} + \frac{- 671 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 + (\frac{- 1441}{14} + \frac{- 671 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.5

Simplify each term.

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Step 4.2.1.3.5.1

Move the negative in front of the fraction.

$\frac{255 + (- \frac{1441}{14} + \frac{- 671 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.5.2

Move the negative in front of the fraction.

$\frac{255 + (- \frac{1441}{14} - \frac{671 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 + (- \frac{1441}{14} - \frac{671 y}{42}) \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.6

Apply the distributive property.

$\frac{255 - \frac{1441}{14} \cdot 3 - \frac{671 y}{42} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.7

Multiply $- \frac{1441}{14} \cdot 3$ .

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Step 4.2.1.3.7.1

Multiply $3$ by $- 1$ .

$\frac{255 - 3 (\frac{1441}{14}) - \frac{671 y}{42} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.7.2

Combine $- 3$ and $\frac{1441}{14}$ .

$\frac{255 + \frac{- 3 \cdot 1441}{14} - \frac{671 y}{42} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.7.3

Multiply $- 3$ by $1441$ .

$\frac{255 + \frac{- 4323}{14} - \frac{671 y}{42} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 + \frac{- 4323}{14} - \frac{671 y}{42} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.8

Cancel the common factor of $3$ .

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Step 4.2.1.3.8.1

Move the leading negative in $- \frac{671 y}{42}$ into the numerator.

$\frac{255 + \frac{- 4323}{14} + \frac{- 671 y}{42} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.8.2

Factor $3$ out of $42$ .

$\frac{255 + \frac{- 4323}{14} + \frac{- 671 y}{3 (14)} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.8.3

Cancel the common factor.

$\frac{255 + \frac{- 4323}{14} + \frac{- 671 y}{3 \cdot 14} \cdot 3 + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.8.4

Rewrite the expression.

$\frac{255 + \frac{- 4323}{14} + \frac{- 671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 + \frac{- 4323}{14} + \frac{- 671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.9

Simplify each term.

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Step 4.2.1.3.9.1

Move the negative in front of the fraction.

$\frac{255 - \frac{4323}{14} + \frac{- 671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.3.9.2

Move the negative in front of the fraction.

$\frac{255 - \frac{4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 - \frac{4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{255 - \frac{4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.4

To write $255$ as a fraction with a common denominator, multiply by $\frac{14}{14}$ .

$\frac{255 \cdot \frac{14}{14} - \frac{4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.5

Combine $255$ and $\frac{14}{14}$ .

$\frac{\frac{255 \cdot 14}{14} - \frac{4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.6

Combine the numerators over the common denominator.

$\frac{\frac{255 \cdot 14 - 4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.7

Simplify the numerator.

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Step 4.2.1.7.1

Multiply $255$ by $14$ .

$\frac{\frac{3570 - 4323}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.7.2

Subtract $4323$ from $3570$ .

$\frac{\frac{- 753}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{\frac{- 753}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.8

Move the negative in front of the fraction.

$\frac{- \frac{753}{14} - \frac{671 y}{14} + 37 y}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.9

To write $37 y$ as a fraction with a common denominator, multiply by $\frac{14}{14}$ .

$\frac{- \frac{753}{14} - \frac{671 y}{14} + 37 y \cdot \frac{14}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.10

Combine $37 y$ and $\frac{14}{14}$ .

$\frac{- \frac{753}{14} - \frac{671 y}{14} + \frac{37 y \cdot 14}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.11

Combine the numerators over the common denominator.

$\frac{- \frac{753}{14} + \frac{- 671 y + 37 y \cdot 14}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.12

Combine the numerators over the common denominator.

$\frac{\frac{- 753 - 671 y + 37 y \cdot 14}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.13

Multiply $14$ by $37$ .

$\frac{\frac{- 753 - 671 y + 518 y}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.14

Add $- 671 y$ and $518 y$ .

$\frac{\frac{- 753 - 153 y}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.15

Factor $3$ out of $- 753 - 153 y$ .

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Step 4.2.1.15.1

Factor $3$ out of $- 753$ .

$\frac{\frac{3 (- 251) - 153 y}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.15.2

Factor $3$ out of $- 153 y$ .

$\frac{\frac{3 (- 251) + 3 (- 51 y)}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.15.3

Factor $3$ out of $3 (- 251) + 3 (- 51 y)$ .

$\frac{\frac{3 (- 251 - 51 y)}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{\frac{3 (- 251 - 51 y)}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.16

Rewrite $- 251$ as $- 1 (251)$ .

$\frac{\frac{3 (- 1 \cdot 251 - 51 y)}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.17

Factor $- 1$ out of $- 51 y$ .

$\frac{\frac{3 (- 1 \cdot 251 - (51 y))}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.18

Factor $- 1$ out of $- 1 (251) - (51 y)$ .

$\frac{\frac{3 (- 1 (251 + 51 y))}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.19

Move the negative in front of the fraction.

$\frac{- \frac{3 (251 + 51 y)}{14}}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.20

Multiply the numerator by the reciprocal of the denominator.

$- \frac{3 (251 + 51 y)}{14} \cdot \frac{1}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.21

Cancel the common factor of $3$ .

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Step 4.2.1.21.1

Move the leading negative in $- \frac{3 (251 + 51 y)}{14}$ into the numerator.

$\frac{- 3 (251 + 51 y)}{14} \cdot \frac{1}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.21.2

Factor $3$ out of $- 3 (251 + 51 y)$ .

$\frac{3 (- (251 + 51 y))}{14} \cdot \frac{1}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.21.3

Cancel the common factor.

$\frac{3 (- (251 + 51 y))}{14} \cdot \frac{1}{3} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.21.4

Rewrite the expression.

$\frac{- (251 + 51 y)}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$\frac{- (251 + 51 y)}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.2.1.22

Move the negative in front of the fraction.

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 2 z$

Step 4.3

Replace all occurrences of $z$ in $x = 17 + \frac{5 y}{3} - 2 z$ with $\frac{131}{14} + \frac{61 y}{42}$ .

$x = 17 + \frac{5 y}{3} - 2 (\frac{131}{14} + \frac{61 y}{42})$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $17 + \frac{5 y}{3} - 2 (\frac{131}{14} + \frac{61 y}{42})$ .

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Step 4.4.1.1

Simplify each term.

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Step 4.4.1.1.1

Apply the distributive property.

$x = 17 + \frac{5 y}{3} - 2 (\frac{131}{14}) - 2 \frac{61 y}{42}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.2

Cancel the common factor of $2$ .

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Step 4.4.1.1.2.1

Factor $2$ out of $- 2$ .

$x = 17 + \frac{5 y}{3} + 2 (- 1) (\frac{131}{14}) - 2 \frac{61 y}{42}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.2.2

Factor $2$ out of $14$ .

$x = 17 + \frac{5 y}{3} + 2 \cdot (- 1 \frac{131}{2 \cdot 7}) - 2 \frac{61 y}{42}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.2.3

Cancel the common factor.

$x = 17 + \frac{5 y}{3} + 2 \cdot (- 1 \frac{131}{2 \cdot 7}) - 2 \frac{61 y}{42}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.2.4

Rewrite the expression.

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) - 2 \frac{61 y}{42}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) - 2 \frac{61 y}{42}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.3

Cancel the common factor of $2$ .

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Step 4.4.1.1.3.1

Factor $2$ out of $- 2$ .

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) + 2 (- 1) (\frac{61 y}{42})$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.3.2

Factor $2$ out of $42$ .

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) + 2 \cdot (- 1 \frac{61 y}{2 \cdot 21})$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.3.3

Cancel the common factor.

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) + 2 \cdot (- 1 \frac{61 y}{2 \cdot 21})$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.3.4

Rewrite the expression.

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) - 1 \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - 1 (\frac{131}{7}) - 1 \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.4

Simplify each term.

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Step 4.4.1.1.4.1

Rewrite $- 1 (\frac{131}{7})$ as $- (\frac{131}{7})$ .

$x = 17 + \frac{5 y}{3} - (\frac{131}{7}) - 1 \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.1.4.2

Rewrite $- 1 \frac{61 y}{21}$ as $- \frac{61 y}{21}$ .

$x = 17 + \frac{5 y}{3} - \frac{131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - \frac{131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 17 + \frac{5 y}{3} - \frac{131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.2

To write $17$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$x = \frac{5 y}{3} + 17 \cdot \frac{7}{7} - \frac{131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.3

Combine $17$ and $\frac{7}{7}$ .

$x = \frac{5 y}{3} + \frac{17 \cdot 7}{7} - \frac{131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.4

Combine the numerators over the common denominator.

$x = \frac{5 y}{3} + \frac{17 \cdot 7 - 131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.5

Simplify the numerator.

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Step 4.4.1.5.1

Multiply $17$ by $7$ .

$x = \frac{5 y}{3} + \frac{119 - 131}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.5.2

Subtract $131$ from $119$ .

$x = \frac{5 y}{3} + \frac{- 12}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = \frac{5 y}{3} + \frac{- 12}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.6

Move the negative in front of the fraction.

$x = \frac{5 y}{3} - \frac{12}{7} - \frac{61 y}{21}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.7

To write $\frac{5 y}{3}$ as a fraction with a common denominator, multiply by $\frac{7}{7}$ .

$x = \frac{5 y}{3} \cdot \frac{7}{7} - \frac{61 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.8

Write each expression with a common denominator of $21$ , by multiplying each by an appropriate factor of $1$ .

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Step 4.4.1.8.1

Multiply $\frac{5 y}{3}$ by $\frac{7}{7}$ .

$x = \frac{5 y \cdot 7}{3 \cdot 7} - \frac{61 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.8.2

Multiply $3$ by $7$ .

$x = \frac{5 y \cdot 7}{21} - \frac{61 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = \frac{5 y \cdot 7}{21} - \frac{61 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.9

Combine the numerators over the common denominator.

$x = \frac{5 y \cdot 7 - 61 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10

Simplify each term.

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Step 4.4.1.10.1

Simplify the numerator.

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Step 4.4.1.10.1.1

Factor $y$ out of $5 y \cdot 7 - 61 y$ .

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Step 4.4.1.10.1.1.1

Factor $y$ out of $5 y \cdot 7$ .

$x = \frac{y (5 \cdot 7) - 61 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10.1.1.2

Factor $y$ out of $- 61 y$ .

$x = \frac{y (5 \cdot 7) + y \cdot - 61}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10.1.1.3

Factor $y$ out of $y (5 \cdot 7) + y \cdot - 61$ .

$x = \frac{y (5 \cdot 7 - 61)}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = \frac{y (5 \cdot 7 - 61)}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10.1.2

Multiply $5$ by $7$ .

$x = \frac{y (35 - 61)}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10.1.3

Subtract $61$ from $35$ .

$x = \frac{y \cdot - 26}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = \frac{y \cdot - 26}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10.2

Move $- 26$ to the left of $y$ .

$x = \frac{- 26 \cdot y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 4.4.1.10.3

Move the negative in front of the fraction.

$x = - \frac{26 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$- \frac{251 + 51 y}{14} = - 7$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5

Solve for $y$ in $- \frac{251 + 51 y}{14} = - 7$ .

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Step 5.1

Multiply both sides of the equation by $- 14$ .

$- 14 (- \frac{251 + 51 y}{14}) = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2

Simplify both sides of the equation.

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Step 5.2.1

Simplify the left side.

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Step 5.2.1.1

Simplify $- 14 (- \frac{251 + 51 y}{14})$ .

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Step 5.2.1.1.1

Cancel the common factor of $14$ .

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Step 5.2.1.1.1.1

Move the leading negative in $- \frac{251 + 51 y}{14}$ into the numerator.

$- 14 \frac{- (251 + 51 y)}{14} = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2.1.1.1.2

Factor $14$ out of $- 14$ .

$14 (- 1) (\frac{- (251 + 51 y)}{14}) = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2.1.1.1.3

Cancel the common factor.

$14 \cdot (- 1 \frac{- (251 + 51 y)}{14}) = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2.1.1.1.4

Rewrite the expression.

$251 + 51 y = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$251 + 51 y = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2.1.1.2

Multiply.

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Step 5.2.1.1.2.1

Multiply $- 1$ by $- 1$ .

$1 (251 + 51 y) = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2.1.1.2.2

Multiply $251 + 51 y$ by $1$ .

$251 + 51 y = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$251 + 51 y = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$251 + 51 y = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$251 + 51 y = - 14 \cdot - 7$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.2.2

Simplify the right side.

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Step 5.2.2.1

Multiply $- 14$ by $- 7$ .

$251 + 51 y = 98$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$251 + 51 y = 98$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$251 + 51 y = 98$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.3

Move all terms not containing $y$ to the right side of the equation.

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Step 5.3.1

Subtract $251$ from both sides of the equation.

$51 y = 98 - 251$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.3.2

Subtract $251$ from $98$ .

$51 y = - 153$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$51 y = - 153$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.4

Divide each term in $51 y = - 153$ by $51$ and simplify.

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Step 5.4.1

Divide each term in $51 y = - 153$ by $51$ .

$\frac{51 y}{51} = \frac{- 153}{51}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.4.2

Simplify the left side.

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Step 5.4.2.1

Cancel the common factor of $51$ .

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Step 5.4.2.1.1

Cancel the common factor.

$\frac{51 y}{51} = \frac{- 153}{51}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.4.2.1.2

Divide $y$ by $1$ .

$y = \frac{- 153}{51}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$y = \frac{- 153}{51}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$y = \frac{- 153}{51}$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 5.4.3

Simplify the right side.

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Step 5.4.3.1

Divide $- 153$ by $51$ .

$y = - 3$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$y = - 3$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$y = - 3$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

$y = - 3$

$x = - \frac{26 y}{21} - \frac{12}{7}$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6

Replace all occurrences of $y$ with $- 3$ in each equation.

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Step 6.1

Replace all occurrences of $y$ in $x = - \frac{26 y}{21} - \frac{12}{7}$ with $- 3$ .

$x = - \frac{26 (- 3)}{21} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $- \frac{26 (- 3)}{21} - \frac{12}{7}$ .

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Step 6.2.1.1

Simplify each term.

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Step 6.2.1.1.1

Cancel the common factor of $- 3$ and $21$ .

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Step 6.2.1.1.1.1

Factor $3$ out of $26 (- 3)$ .

$x = - \frac{3 (26 \cdot (- 1))}{21} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.1.2

Cancel the common factors.

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Step 6.2.1.1.1.2.1

Factor $3$ out of $21$ .

$x = - \frac{3 (26 \cdot (- 1))}{3 (7)} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.1.2.2

Cancel the common factor.

$x = - \frac{3 (26 \cdot (- 1))}{3 \cdot 7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.1.2.3

Rewrite the expression.

$x = - \frac{26 \cdot (- 1)}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = - \frac{26 \cdot (- 1)}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = - \frac{26 \cdot (- 1)}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.2

Multiply $26$ by $- 1$ .

$x = - \frac{- 26}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.3

Move the negative in front of the fraction.

$x = \frac{26}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.4

Multiply $- - \frac{26}{7}$ .

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Step 6.2.1.1.4.1

Multiply $- 1$ by $- 1$ .

$x = 1 (\frac{26}{7}) - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.1.4.2

Multiply $\frac{26}{7}$ by $1$ .

$x = \frac{26}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = \frac{26}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = \frac{26}{7} - \frac{12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.2

Combine fractions.

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Step 6.2.1.2.1

Combine the numerators over the common denominator.

$x = \frac{26 - 12}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.2.2

Simplify the expression.

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Step 6.2.1.2.2.1

Subtract $12$ from $26$ .

$x = \frac{14}{7}$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.2.1.2.2.2

Divide $14$ by $7$ .

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{61 y}{42}$

Step 6.3

Replace all occurrences of $y$ in $z = \frac{131}{14} + \frac{61 y}{42}$ with $- 3$ .

$z = \frac{131}{14} + \frac{61 (- 3)}{42}$

$x = 2$

$y = - 3$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $\frac{131}{14} + \frac{61 (- 3)}{42}$ .

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Step 6.4.1.1

Multiply $61$ by $- 3$ .

$z = \frac{131}{14} + \frac{- 183}{42}$

$x = 2$

$y = - 3$

Step 6.4.1.2

Simplify each term.

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Step 6.4.1.2.1

Cancel the common factor of $- 183$ and $42$ .

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Step 6.4.1.2.1.1

Factor $3$ out of $- 183$ .

$z = \frac{131}{14} + \frac{3 (- 61)}{42}$

$x = 2$

$y = - 3$

Step 6.4.1.2.1.2

Cancel the common factors.

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Step 6.4.1.2.1.2.1

Factor $3$ out of $42$ .

$z = \frac{131}{14} + \frac{3 \cdot - 61}{3 \cdot 14}$

$x = 2$

$y = - 3$

Step 6.4.1.2.1.2.2

Cancel the common factor.

$z = \frac{131}{14} + \frac{3 \cdot - 61}{3 \cdot 14}$

$x = 2$

$y = - 3$

Step 6.4.1.2.1.2.3

Rewrite the expression.

$z = \frac{131}{14} + \frac{- 61}{14}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{- 61}{14}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} + \frac{- 61}{14}$

$x = 2$

$y = - 3$

Step 6.4.1.2.2

Move the negative in front of the fraction.

$z = \frac{131}{14} - \frac{61}{14}$

$x = 2$

$y = - 3$

$z = \frac{131}{14} - \frac{61}{14}$

$x = 2$

$y = - 3$

Step 6.4.1.3

Combine fractions.

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Step 6.4.1.3.1

Combine the numerators over the common denominator.

$z = \frac{131 - 61}{14}$

$x = 2$

$y = - 3$

Step 6.4.1.3.2

Simplify the expression.

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Step 6.4.1.3.2.1

Subtract $61$ from $131$ .

$z = \frac{70}{14}$

$x = 2$

$y = - 3$

Step 6.4.1.3.2.2

Divide $70$ by $14$ .

$z = 5$

$x = 2$

$y = - 3$

$z = 5$

$x = 2$

$y = - 3$

$z = 5$

$x = 2$

$y = - 3$

$z = 5$

$x = 2$

$y = - 3$

$z = 5$

$x = 2$

$y = - 3$

$z = 5$

$x = 2$

$y = - 3$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(2, - 3, 5)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(2, - 3, 5)$

Equation Form:

$x = 2, y = - 3, z = 5$