Finite Math Examples

$x + y - z = 2$ , $2 x - y + z = - 5$ , $x - 4 y + 3 z = - 25$

Step 1

Move all terms not containing $x$ to the right side of the equation.

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Step 1.1

Subtract $y$ from both sides of the equation.

$x - z = 2 - y$

$2 x - y + z = - 5$

$x - 4 y + 3 z = - 25$

Step 1.2

Add $z$ to both sides of the equation.

$x = 2 - y + z$

$2 x - y + z = - 5$

$x - 4 y + 3 z = - 25$

$x = 2 - y + z$

$2 x - y + z = - 5$

$x - 4 y + 3 z = - 25$

Step 2

Replace all occurrences of $x$ with $2 - y + z$ in each equation.

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Step 2.1

Replace all occurrences of $x$ in $2 x - y + z = - 5$ with $2 - y + z$ .

$2 (2 - y + z) - y + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

Step 2.2

Simplify the left side.

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Step 2.2.1

Simplify $2 (2 - y + z) - y + z$ .

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Step 2.2.1.1

Simplify each term.

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Step 2.2.1.1.1

Apply the distributive property.

$2 \cdot 2 + 2 (- y) + 2 z - y + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

Step 2.2.1.1.2

Simplify.

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Step 2.2.1.1.2.1

Multiply $2$ by $2$ .

$4 + 2 (- y) + 2 z - y + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

Step 2.2.1.1.2.2

Multiply $- 1$ by $2$ .

$4 - 2 y + 2 z - y + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

$4 - 2 y + 2 z - y + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

$4 - 2 y + 2 z - y + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

Step 2.2.1.2

Simplify by adding terms.

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Step 2.2.1.2.1

Subtract $y$ from $- 2 y$ .

$4 - 3 y + 2 z + z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

Step 2.2.1.2.2

Add $2 z$ and $z$ .

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$x - 4 y + 3 z = - 25$

Step 2.3

Replace all occurrences of $x$ in $x - 4 y + 3 z = - 25$ with $2 - y + z$ .

$(2 - y + z) - 4 y + 3 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 2.4

Simplify the left side.

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Step 2.4.1

Simplify $(2 - y + z) - 4 y + 3 z$ .

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Step 2.4.1.1

Subtract $4 y$ from $- y$ .

$2 - 5 y + z + 3 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 2.4.1.2

Add $z$ and $3 z$ .

$2 - 5 y + 4 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$2 - 5 y + 4 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$2 - 5 y + 4 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$2 - 5 y + 4 z = - 25$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3

Solve for $y$ in $2 - 5 y + 4 z = - 25$ .

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Step 3.1

Move all terms not containing $y$ to the right side of the equation.

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Step 3.1.1

Subtract $2$ from both sides of the equation.

$- 5 y + 4 z = - 25 - 2$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.1.2

Subtract $4 z$ from both sides of the equation.

$- 5 y = - 25 - 2 - 4 z$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.1.3

Subtract $2$ from $- 25$ .

$- 5 y = - 27 - 4 z$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$- 5 y = - 27 - 4 z$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.2

Divide each term in $- 5 y = - 27 - 4 z$ by $- 5$ and simplify.

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Step 3.2.1

Divide each term in $- 5 y = - 27 - 4 z$ by $- 5$ .

$\frac{- 5 y}{- 5} = \frac{- 27}{- 5} + \frac{- 4 z}{- 5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.2.2

Simplify the left side.

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Step 3.2.2.1

Cancel the common factor of $- 5$ .

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Step 3.2.2.1.1

Cancel the common factor.

$\frac{- 5 y}{- 5} = \frac{- 27}{- 5} + \frac{- 4 z}{- 5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.2.2.1.2

Divide $y$ by $1$ .

$y = \frac{- 27}{- 5} + \frac{- 4 z}{- 5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$y = \frac{- 27}{- 5} + \frac{- 4 z}{- 5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$y = \frac{- 27}{- 5} + \frac{- 4 z}{- 5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.2.3

Simplify the right side.

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Step 3.2.3.1

Simplify each term.

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Step 3.2.3.1.1

Dividing two negative values results in a positive value.

$y = \frac{27}{5} + \frac{- 4 z}{- 5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 3.2.3.1.2

Dividing two negative values results in a positive value.

$y = \frac{27}{5} + \frac{4 z}{5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$y = \frac{27}{5} + \frac{4 z}{5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$y = \frac{27}{5} + \frac{4 z}{5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$y = \frac{27}{5} + \frac{4 z}{5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

$y = \frac{27}{5} + \frac{4 z}{5}$

$4 - 3 y + 3 z = - 5$

$x = 2 - y + z$

Step 4

Replace all occurrences of $y$ with $\frac{27}{5} + \frac{4 z}{5}$ in each equation.

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Step 4.1

Replace all occurrences of $y$ in $4 - 3 y + 3 z = - 5$ with $\frac{27}{5} + \frac{4 z}{5}$ .

$4 - 3 (\frac{27}{5} + \frac{4 z}{5}) + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2

Simplify the left side.

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Step 4.2.1

Simplify $4 - 3 (\frac{27}{5} + \frac{4 z}{5}) + 3 z$ .

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Step 4.2.1.1

Simplify each term.

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Step 4.2.1.1.1

Apply the distributive property.

$4 - 3 (\frac{27}{5}) - 3 \frac{4 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.1.2

Multiply $- 3 (\frac{27}{5})$ .

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Step 4.2.1.1.2.1

Combine $- 3$ and $\frac{27}{5}$ .

$4 + \frac{- 3 \cdot 27}{5} - 3 \frac{4 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.1.2.2

Multiply $- 3$ by $27$ .

$4 + \frac{- 81}{5} - 3 \frac{4 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$4 + \frac{- 81}{5} - 3 \frac{4 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.1.3

Multiply $- 3 \frac{4 z}{5}$ .

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Step 4.2.1.1.3.1

Combine $- 3$ and $\frac{4 z}{5}$ .

$4 + \frac{- 81}{5} + \frac{- 3 (4 z)}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.1.3.2

Multiply $4$ by $- 3$ .

$4 + \frac{- 81}{5} + \frac{- 12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$4 + \frac{- 81}{5} + \frac{- 12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.1.4

Simplify each term.

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Step 4.2.1.1.4.1

Move the negative in front of the fraction.

$4 - \frac{81}{5} + \frac{- 12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.1.4.2

Move the negative in front of the fraction.

$4 - \frac{81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$4 - \frac{81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$4 - \frac{81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.2

To write $4$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$4 \cdot \frac{5}{5} - \frac{81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.3

Combine $4$ and $\frac{5}{5}$ .

$\frac{4 \cdot 5}{5} - \frac{81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.4

Combine the numerators over the common denominator.

$\frac{4 \cdot 5 - 81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.5

Simplify the numerator.

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Step 4.2.1.5.1

Multiply $4$ by $5$ .

$\frac{20 - 81}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.5.2

Subtract $81$ from $20$ .

$\frac{- 61}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$\frac{- 61}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.6

Move the negative in front of the fraction.

$- \frac{61}{5} - \frac{12 z}{5} + 3 z = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.7

To write $3 z$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$- \frac{61}{5} - \frac{12 z}{5} + 3 z \cdot \frac{5}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.8

Combine $3 z$ and $\frac{5}{5}$ .

$- \frac{61}{5} - \frac{12 z}{5} + \frac{3 z \cdot 5}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.9

Combine the numerators over the common denominator.

$- \frac{61}{5} + \frac{- 12 z + 3 z \cdot 5}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.10

Combine the numerators over the common denominator.

$\frac{- 61 - 12 z + 3 z \cdot 5}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.11

Multiply $5$ by $3$ .

$\frac{- 61 - 12 z + 15 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.12

Add $- 12 z$ and $15 z$ .

$\frac{- 61 + 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.13

Rewrite $- 61$ as $- 1 (61)$ .

$\frac{- 1 \cdot 61 + 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.14

Factor $- 1$ out of $3 z$ .

$\frac{- 1 \cdot 61 - (- 3 z)}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.15

Factor $- 1$ out of $- 1 (61) - (- 3 z)$ .

$\frac{- 1 (61 - 3 z)}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.2.1.16

Move the negative in front of the fraction.

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = 2 - y + z$

Step 4.3

Replace all occurrences of $y$ in $x = 2 - y + z$ with $\frac{27}{5} + \frac{4 z}{5}$ .

$x = 2 - (\frac{27}{5} + \frac{4 z}{5}) + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4

Simplify the right side.

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Step 4.4.1

Simplify $2 - (\frac{27}{5} + \frac{4 z}{5}) + z$ .

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Step 4.4.1.1

Apply the distributive property.

$x = 2 - \frac{27}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.2

To write $2$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$x = 2 \cdot \frac{5}{5} - \frac{27}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.3

Combine $2$ and $\frac{5}{5}$ .

$x = \frac{2 \cdot 5}{5} - \frac{27}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.4

Combine the numerators over the common denominator.

$x = \frac{2 \cdot 5 - 27}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.5

Simplify the numerator.

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Step 4.4.1.5.1

Multiply $2$ by $5$ .

$x = \frac{10 - 27}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.5.2

Subtract $27$ from $10$ .

$x = \frac{- 17}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = \frac{- 17}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.6

Move the negative in front of the fraction.

$x = - \frac{17}{5} - \frac{4 z}{5} + z$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.7

To write $z$ as a fraction with a common denominator, multiply by $\frac{5}{5}$ .

$x = - \frac{17}{5} - \frac{4 z}{5} + z \cdot \frac{5}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.8

Simplify terms.

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Step 4.4.1.8.1

Combine $z$ and $\frac{5}{5}$ .

$x = - \frac{17}{5} - \frac{4 z}{5} + \frac{z \cdot 5}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.8.2

Combine the numerators over the common denominator.

$x = - \frac{17}{5} + \frac{- 4 z + z \cdot 5}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.8.3

Combine the numerators over the common denominator.

$x = \frac{- 17 - 4 z + z \cdot 5}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = \frac{- 17 - 4 z + z \cdot 5}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.9

Move $5$ to the left of $z$ .

$x = \frac{- 17 - 4 z + 5 z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.10

Simplify terms.

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Step 4.4.1.10.1

Add $- 4 z$ and $5 z$ .

$x = \frac{- 17 + z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.10.2

Rewrite $- 17$ as $- 1 (17)$ .

$x = \frac{- 1 \cdot 17 + z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.10.3

Factor $- 1$ out of $z$ .

$x = \frac{- 1 \cdot 17 - 1 (- z)}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.10.4

Factor $- 1$ out of $- 1 (17) - 1 (- z)$ .

$x = \frac{- 1 (17 - z)}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 4.4.1.10.5

Move the negative in front of the fraction.

$x = - \frac{17 - z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - \frac{17 - z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - \frac{17 - z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - \frac{17 - z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - \frac{17 - z}{5}$

$- \frac{61 - 3 z}{5} = - 5$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5

Solve for $z$ in $- \frac{61 - 3 z}{5} = - 5$ .

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Step 5.1

Multiply both sides of the equation by $- 5$ .

$- 5 (- \frac{61 - 3 z}{5}) = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2

Simplify both sides of the equation.

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Step 5.2.1

Simplify the left side.

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Step 5.2.1.1

Simplify $- 5 (- \frac{61 - 3 z}{5})$ .

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Step 5.2.1.1.1

Cancel the common factor of $5$ .

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Step 5.2.1.1.1.1

Move the leading negative in $- \frac{61 - 3 z}{5}$ into the numerator.

$- 5 \frac{- (61 - 3 z)}{5} = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2.1.1.1.2

Factor $5$ out of $- 5$ .

$5 (- 1) (\frac{- (61 - 3 z)}{5}) = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2.1.1.1.3

Cancel the common factor.

$5 \cdot (- 1 \frac{- (61 - 3 z)}{5}) = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2.1.1.1.4

Rewrite the expression.

$61 - 3 z = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$61 - 3 z = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2.1.1.2

Multiply.

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Step 5.2.1.1.2.1

Multiply $- 1$ by $- 1$ .

$1 (61 - 3 z) = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2.1.1.2.2

Multiply $61 - 3 z$ by $1$ .

$61 - 3 z = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$61 - 3 z = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$61 - 3 z = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$61 - 3 z = - 5 \cdot - 5$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.2.2

Simplify the right side.

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Step 5.2.2.1

Multiply $- 5$ by $- 5$ .

$61 - 3 z = 25$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$61 - 3 z = 25$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$61 - 3 z = 25$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.3

Move all terms not containing $z$ to the right side of the equation.

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Step 5.3.1

Subtract $61$ from both sides of the equation.

$- 3 z = 25 - 61$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.3.2

Subtract $61$ from $25$ .

$- 3 z = - 36$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$- 3 z = - 36$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.4

Divide each term in $- 3 z = - 36$ by $- 3$ and simplify.

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Step 5.4.1

Divide each term in $- 3 z = - 36$ by $- 3$ .

$\frac{- 3 z}{- 3} = \frac{- 36}{- 3}$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.4.2

Simplify the left side.

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Step 5.4.2.1

Cancel the common factor of $- 3$ .

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Step 5.4.2.1.1

Cancel the common factor.

$\frac{- 3 z}{- 3} = \frac{- 36}{- 3}$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.4.2.1.2

Divide $z$ by $1$ .

$z = \frac{- 36}{- 3}$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$z = \frac{- 36}{- 3}$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$z = \frac{- 36}{- 3}$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 5.4.3

Simplify the right side.

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Step 5.4.3.1

Divide $- 36$ by $- 3$ .

$z = 12$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$z = 12$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$z = 12$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

$z = 12$

$x = - \frac{17 - z}{5}$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6

Replace all occurrences of $z$ with $12$ in each equation.

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Step 6.1

Replace all occurrences of $z$ in $x = - \frac{17 - z}{5}$ with $12$ .

$x = - \frac{17 - (12)}{5}$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6.2

Simplify the right side.

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Step 6.2.1

Simplify $- \frac{17 - (12)}{5}$ .

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Step 6.2.1.1

Simplify the numerator.

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Step 6.2.1.1.1

Multiply $- 1$ by $12$ .

$x = - \frac{17 - 12}{5}$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6.2.1.1.2

Subtract $12$ from $17$ .

$x = - \frac{5}{5}$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - \frac{5}{5}$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6.2.1.2

Reduce the expression by cancelling the common factors.

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Step 6.2.1.2.1

Cancel the common factor of $5$ .

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Step 6.2.1.2.1.1

Cancel the common factor.

$x = - \frac{5}{5}$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6.2.1.2.1.2

Rewrite the expression.

$x = - 1 \cdot 1$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - 1 \cdot 1$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6.2.1.2.2

Multiply $- 1$ by $1$ .

$x = - 1$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - 1$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - 1$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

$x = - 1$

$z = 12$

$y = \frac{27}{5} + \frac{4 z}{5}$

Step 6.3

Replace all occurrences of $z$ in $y = \frac{27}{5} + \frac{4 z}{5}$ with $12$ .

$y = \frac{27}{5} + \frac{4 (12)}{5}$

$x = - 1$

$z = 12$

Step 6.4

Simplify the right side.

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Step 6.4.1

Simplify $\frac{27}{5} + \frac{4 (12)}{5}$ .

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Step 6.4.1.1

Combine the numerators over the common denominator.

$y = \frac{27 + 4 (12)}{5}$

$x = - 1$

$z = 12$

Step 6.4.1.2

Simplify the expression.

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Step 6.4.1.2.1

Multiply $4$ by $12$ .

$y = \frac{27 + 48}{5}$

$x = - 1$

$z = 12$

Step 6.4.1.2.2

Add $27$ and $48$ .

$y = \frac{75}{5}$

$x = - 1$

$z = 12$

Step 6.4.1.2.3

Divide $75$ by $5$ .

$y = 15$

$x = - 1$

$z = 12$

$y = 15$

$x = - 1$

$z = 12$

$y = 15$

$x = - 1$

$z = 12$

$y = 15$

$x = - 1$

$z = 12$

$y = 15$

$x = - 1$

$z = 12$

Step 7

The solution to the system is the complete set of ordered pairs that are valid solutions.

$(- 1, 15, 12)$

Step 8

The result can be shown in multiple forms.

Point Form:

$(- 1, 15, 12)$

Equation Form:

$x = - 1, y = 15, z = 12$